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Last updated on September 24, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 32 and 60.
The greatest common factor of 32 and 60 is 4. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are coprime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 32 and 60, a few methods are described below
Steps to find the GCF of 32 and 60 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 32 = 1, 2, 4, 8, 16, 32.
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Step 2: Now, identify the common factors of them Common factors of 32 and 60: 1, 2, 4.
Step 3: Choose the largest factor The largest factor that both numbers have is 4.
The GCF of 32 and 60 is 4.
To find the GCF of 32 and 60 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 32: 32 = 2 × 2 × 2 × 2 × 2 = 25
Prime Factors of 60: 60 = 2 × 2 × 3 × 5 = 22 × 3 × 5
Step 2: Now, identify the common prime factors The common prime factors are: 2 × 2 = 22
Step 3: Multiply the common prime factors 22 = 4.
The Greatest Common Factor of 32 and 60 is 4.
Find the GCF of 32 and 60 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 60 by 32 60 ÷ 32 = 1 (quotient),
The remainder is calculated as 60 − (32×1) = 28
The remainder is 28, not zero, so continue the process
Step 2: Now divide the previous divisor (32) by the previous remainder (28)
Divide 32 by 28 32 ÷ 28 = 1 (quotient), remainder = 32 − (28×1) = 4
Step 3: Now divide the previous divisor (28) by the remainder (4) 28 ÷ 4 = 7 (quotient), remainder = 28 − (4×7) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 32 and 60 is 4.
Finding GCF of 32 and 60 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 32 rose bushes and 60 sunflower plants. She wants to arrange them in rows with the largest possible equal number of plants in each row. How many plants will be in each row?
We should find the GCF of 32 and 60 GCF of 32 and 60 22 = 4.
There are 4 equal groups 32 ÷ 4 = 8 60 ÷ 4 = 15
There will be 4 rows, and each row gets 8 rose bushes and 15 sunflower plants.
As the GCF of 32 and 60 is 4, the gardener can make 4 rows.
Now divide 32 and 60 by 4.
Each row gets 8 rose bushes and 15 sunflower plants.
A chef has 32 apples and 60 oranges. He wants to pack them into baskets with the same number of fruits in each basket, using the largest number of fruits per basket possible. How many fruits will be in each basket?
GCF of 32 and 60 22 = 4.
So each basket will have 4 fruits.
There are 32 apples and 60 oranges.
To find the total number of fruits in each basket, we should find the GCF of 32 and 60.
There will be 4 fruits in each basket.
A tailor has 32 meters of green fabric and 60 meters of yellow fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 32 and 60
The GCF of 32 and 60 22 = 4.
The fabric pieces are 4 meters long.
For calculating the longest length of the fabric pieces, first, we need to calculate the GCF of 32 and 60, which is 4.
The length of each piece of the fabric will be 4 meters.
A carpenter has two wooden planks, one 32 cm long and the other 60 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 32 and 60 22 = 4.
The longest length of each piece is 4 cm.
To find the longest length of each piece of the two wooden planks, 32 cm and 60 cm, respectively, we have to find the GCF of 32 and 60, which is 4 cm.
The longest length of each piece is 4 cm.
If the GCF of 32 and ‘a’ is 4, and the LCM is 480, find ‘a’.
The value of ‘a’ is 60.
GCF × LCM = product of the numbers
4 × 480 = 32 × a
1920 = 32a
a = 1920 ÷ 32 = 60
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.