Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 30 and 50.
The greatest common factor of 30 and 50 is 10. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 30 and 50, a few methods are described below:
Steps to find the GCF of 30 and 50 using the listing of factors:
Step 1: Firstly, list the factors of each number.
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Factors of 50 = 1, 2, 5, 10, 25, 50.
Step 2: Now, identify the common factors. Common factors of 30 and 50: 1, 2, 5, 10.
Step 3: Choose the largest factor.
The largest factor that both numbers have is 10.
The GCF of 30 and 50 is 10.
To find the GCF of 30 and 50 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number.
Prime factors of 30: 30 = 2 x 3 x 5
Prime factors of 50: 50 = 2 x 5 x 5
Step 2: Now, identify the common prime factors.
The common prime factors are: 2 x 5
Step 3: Multiply the common prime factors. 2 x 5 = 10.
The Greatest Common Factor of 30 and 50 is 10.
Find the GCF of 30 and 50 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 50 by 30. 50 ÷ 30 = 1 (quotient),
The remainder is calculated as 50 − (30×1) = 20.
The remainder is 20, not zero, so continue the process.
Step 2: Now divide the previous divisor (30) by the previous remainder (20).
Divide 30 by 20. 30 ÷ 20 = 1 (quotient), remainder = 30 − (20×1) = 10.
Step 3: Continue with the process. Now divide the previous divisor (20) by the previous remainder (10). 20 ÷ 10 = 2 (quotient), remainder = 20 − (10×2) = 0.
The remainder is zero, so the divisor becomes the GCF.
The GCF of 30 and 50 is 10.
Finding the GCF of 30 and 50 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A farmer has 30 apples and 50 oranges. He wants to pack them into boxes with the largest number of fruits in each box, without mixing apples and oranges. How many fruits will be in each box?
We should find the GCF of 30 and 50.
GCF of 30 and 50 = 10.
There are 10 fruits in each box.
30 ÷ 10 = 3
50 ÷ 10 = 5
There will be 10 boxes, with 3 apples and 5 oranges in each box.
As the GCF of 30 and 50 is 10, the farmer can pack 10 fruits in each box.
Now, divide 30 and 50 by 10.
Each box will have 3 apples and 5 oranges.
A concert hall has 30 speakers and 50 spotlights. They want to arrange them in rows with the same number of items in each row, using the maximum number of items per row. How many items will be in each row?
GCF of 30 and 50 = 10. So each row will have 10 items.
There are 30 speakers and 50 spotlights. To find the total number of items in each row, we should find the GCF of 30 and 50. There will be 10 items in each row.
A chef has 30 kg of flour and 50 kg of sugar. He wants to divide both into equal packages, using the largest possible weight. What should be the weight of each package?
For calculating the largest equal weight, we have to calculate the GCF of 30 and 50.
The GCF of 30 and 50 = 10.
Each package will weigh 10 kg.
For calculating the largest weight of the packages, first, we need to calculate the GCF of 30 and 50, which is 10. The weight of each package of flour or sugar will be 10 kg.
A carpenter has two wooden boards, one 30 cm wide and the other 50 cm wide. He wants to cut them into the widest possible equal strips, without any wood left over. What should be the width of each strip?
The carpenter needs the widest strip of wood.
GCF of 30 and 50 = 10.
The widest width of each strip is 10 cm.
To find the widest width of each strip of the two wooden boards, 30 cm and 50 cm, respectively, we have to find the GCF of 30 and 50, which is 10 cm. The widest width of each strip is 10 cm.
If the GCF of 30 and ‘b’ is 10, and the LCM is 150, find ‘b’.
The value of ‘b’ is 50.
GCF x LCM = product of the numbers
10 × 150 = 30 × b
1500 = 30b
b = 1500 ÷ 30 = 50
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.