Last updated on August 12th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 30 and 45.
The greatest common factor of 30 and 45 is 15. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 30 and 45, a few methods are described below - Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 30 and 45 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Factors of 45 = 1, 3, 5, 9, 15, 45.
Step 2: Now, identify the common factors of them Common factors of 30 and 45: 1, 3, 5, 15.
Step 3: Choose the largest factor The largest factor that both numbers have is 15. The GCF of 30 and 45 is 15.
To find the GCF of 30 and 45 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 30: 30 = 2 x 3 x 5
Prime Factors of 45: 45 = 3 x 3 x 5
Step 2: Now, identify the common prime factors The common prime factors are: 3 x 5
Step 3: Multiply the common prime factors 3 x 5 = 15.
The Greatest Common Factor of 30 and 45 is 15.
Find the GCF of 30 and 45 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 45 by 30 45 ÷ 30 = 1 (quotient), The remainder is calculated as 45 − (30×1) = 15 The remainder is 15, not zero, so continue the process
Step 2: Now divide the previous divisor (30) by the previous remainder (15) Divide 30 by 15 30 ÷ 15 = 2 (quotient), remainder = 30 − (15×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 30 and 45 is 15.
Finding GCF of 30 and 45 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 30 apples and 45 oranges. He wants to arrange them into equal sets, with the largest number of fruits in each set. How many fruits will be in each set?
We should find the GCF of 30 and 45 GCF of 30 and 45 3 x 5 = 15.
There are 15 equal groups 30 ÷ 15 = 2 45 ÷ 15 = 3
There will be 15 groups, and each group gets 2 apples and 3 oranges.
As the GCF of 30 and 45 is 15, the chef can make 15 groups. Now divide 30 and 45 by 15. Each group gets 2 apples and 3 oranges.
A school has 30 red chairs and 45 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 30 and 45 3 x 5 = 15. So each row will have 15 chairs.
There are 30 red and 45 blue chairs. To find the total number of chairs in each row, we should find the GCF of 30 and 45. There will be 15 chairs in each row.
A tailor has 30 meters of red fabric and 45 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 30 and 45 The GCF of 30 and 45 3 x 5 = 15. The fabric pieces are 15 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 30 and 45, which is 15. The length of each piece of fabric will be 15 meters.
A carpenter has two wooden planks, one 30 cm long and the other 45 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 30 and 45 3 x 5 = 15. The longest length of each piece is 15 cm.
To find the longest length of each piece of the two wooden planks, 30 cm and 45 cm, respectively. We have to find the GCF of 30 and 45, which is 15 cm. The longest length of each piece is 15 cm.
If the GCF of 30 and ‘b’ is 15, and the LCM is 90. Find ‘b’.
The value of ‘b’ is 45.
GCF x LCM = product of the numbers 15 x 90 = 30 x b 1350 = 30b b = 1350 ÷ 30 = 45
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.