Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 25 and 55.
The greatest common factor of 25 and 55 is 5. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 25 and 55, a few methods are described below:
Steps to find the GCF of 25 and 55 using the listing of factors:
Step 1: Firstly, list the factors of each number:
Factors of 25 = 1, 5, 25.
Factors of 55 = 1, 5, 11, 55.
Step 2: Now, identify the common factors of them:
Common factors of 25 and 55: 1, 5.
Step 3: Choose the largest factor:
The largest factor that both numbers have is 5.
The GCF of 25 and 55 is 5.
To find the GCF of 25 and 55 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number:
Prime Factors of 25: 25 = 5 x 5 = 5²
Prime Factors of 55: 55 = 5 x 11
Step 2: Now, identify the common prime factors.
The common prime factor is: 5
Step 3: Multiply the common prime factors.
The GCF of 25 and 55 is 5.
Find the GCF of 25 and 55 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 55 by 25 55 ÷ 25 = 2 (quotient), The remainder is calculated as 55 − (25×2) = 5
The remainder is 5, not zero, so continue the process
Step 2: Now divide the previous divisor (25) by the previous remainder (5)
Divide 25 by 5
25 ÷ 5 = 5 (quotient), remainder = 25 − (5×5) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 25 and 55 is 5.
Finding GCF of 25 and 55 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 25 notebooks and 55 pens. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 25 and 55.
GCF of 25 and 55 is 5.
There are 5 equal groups
25 ÷ 5 = 5
55 ÷ 5 = 11
There will be 5 groups, and each group gets 5 notebooks and 11 pens.
As the GCF of 25 and 55 is 5, the teacher can make 5 groups.
Now divide 25 and 55 by 5.
Each group gets 5 notebooks and 11 pens.
A school has 25 red chairs and 55 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 25 and 55 is 5. So each row will have 5 chairs.
There are 25 red and 55 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 25 and 55.
There will be 5 chairs in each row.
A tailor has 25 meters of red ribbon and 55 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 25 and 55.
The GCF of 25 and 55 is 5.
The ribbon is 5 meters long.
For calculating the longest length of the ribbon first, we need to calculate the GCF of 25 and 55, which is 5. The length of each piece of the ribbon will be 5 meters.
A carpenter has two wooden planks, one 25 cm long and the other 55 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood.
GCF of 25 and 55 is 5.
The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 25 cm and 55 cm, respectively, we have to find the GCF of 25 and 55, which is 5 cm.
The longest length of each piece is 5 cm.
If the GCF of 25 and ‘a’ is 5, and the LCM is 275. Find ‘a’.
The value of ‘a’ is 55.
GCF x LCM = product of the numbers
5 × 275 = 25 × a
1375 = 25a
a = 1375 ÷ 25 = 55
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.