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130 LearnersLast updated on December 11, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 25 and 30.
The greatest common factor of 25 and 30 is 5.
The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 25 and 30, a few methods are described below -
Steps to find the GCF of 25 and 30 using the listing of factors
Step 1: Firstly, list the factors of each number,
Factors of 25 = 1, 5, 25
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30
Step 2: Now, identify the common factors of them Common factors of 25 and 30: 1, 5
Step 3: Choose the largest factor The largest factor that both numbers have is 5.
The GCF of 25 and 30 is 5.


To find the GCF of 25 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 25: 25 = 5 x 5 = 5² Prime Factors of 30: 30 = 2 x 3 x 5
Step 2: Now, identify the common prime factors The common prime factor is: 5
Step 3: Multiply the common prime factors The greatest common factor of 25 and 30 is 5.
Find the GCF of 25 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 30 by 25 30 ÷ 25 = 1 (quotient), The remainder is calculated as 30 − (25×1) = 5. The remainder is 5, not zero, so continue the process
Step 2: Now divide the previous divisor (25) by the previous remainder (5) Divide 25 by 5 25 ÷ 5 = 5 (quotient), remainder = 25 − (5×5) = 0.The remainder is zero, the divisor will become the GCF.
The GCF of 25 and 30 is 5.
Finding the GCF of 25 and 30 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by students.
A teacher has 25 markers and 30 notebooks. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 25 and 30 GCF of 25 and 30 5
There are 5 equal groups 25 ÷ 5 = 5 30 ÷ 5 = 6
There will be 5 groups, and each group gets 5 markers and 6 notebooks.
As the GCF of 25 and 30 is 5, the teacher can make 5 groups.
Now divide 25 and 30 by 5.
Each group gets 5 markers and 6 notebooks.
A school has 25 students and 30 teachers. They want to arrange them in rows with the same number of people in each row, using the largest possible number of people per row. How many people will be in each row?
GCF of 25 and 30 5 So each row will have 5 people.
There are 25 students and 30 teachers.
To find the total number of people in each row, we should find the GCF of 25 and 30.
There will be 5 people in each row.
A tailor has 25 meters of fabric and 30 meters of thread. She wants to cut both into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 25 and 30.
The GCF of 25 and 30 is 5.
The pieces are 5 meters long.
For calculating the longest length of the fabric and thread, first, we need to calculate the GCF of 25 and 30, which is 5.
The length of each piece will be 5 meters.
A carpenter has two wooden planks, one 25 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 25 and 30 is 5.
The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 25 cm and 30 cm, respectively, we have to find the GCF of 25 and 30, which is 5 cm.
The longest length of each piece is 5 cm.
If the GCF of 25 and โaโ is 5, and the LCM is 150. Find โaโ.
The value of ‘a’ is 30.
GCF x LCM = product of the numbers
5 × 150 = 25 × a
750 = 25a
a = 750 ÷ 25 = 30

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






