Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 20 and 32.
The greatest common factor of 20 and 32 is 4. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 20 and 32, a few methods are described below
Steps to find the GCF of 20 and 32 using the listing of factors:
Step 1: Firstly, list the factors of each number:
Factors of 20 = 1, 2, 4, 5, 10, 20.
Factors of 32 = 1, 2, 4, 8, 16, 32.
Step 2: Now, identify the common factors of them Common factors of 20 and 32: 1, 2, 4.
Step 3: Choose the largest factor:
The largest factor that both numbers have is 4.
The GCF of 20 and 32 is 4.
To find the GCF of 20 and 32 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime factors of 20: 20 = 2 x 2 x 5 = 22 x 5
Prime factors of 32: 32 = 2 x 2 x 2 x 2 x 2 = 25
Step 2: Now, identify the common prime factors.
The common prime factor is: 2 x 2 = 22
Step 3: Multiply the common prime factors 22 = 4.
The Greatest Common Factor of 20 and 32 is 4.
Find the GCF of 20 and 32 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 32 by 20 32 ÷ 20 = 1 (quotient), The remainder is calculated as 32 − (20×1) = 12
The remainder is 12, not zero, so continue the process
Step 2: Now divide the previous divisor (20) by the previous remainder (12)
Divide 20 by 12 20 ÷ 12 = 1 (quotient), remainder = 20 − (12×1) = 8 Now, divide 12 by 8 12 ÷ 8 = 1 (quotient), remainder = 12 − (8×1) = 4
Now, divide 8 by 4 8 ÷ 4 = 2 (quotient), remainder = 8 − (4×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 20 and 32 is 4.
Finding GCF of 20 and 32 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 20 rose bushes and 32 tulip bulbs. She wants to plant them in equal rows with the largest number of plants in each row. How many plants will be in each row?
We should find the GCF of 20 and 32 The GCF of 20 and 32
22 = 4.
There are 4 equal rows
20 ÷ 4 = 5
32 ÷ 4 = 8
There will be 4 rows, and each row has 5 rose bushes and 8 tulip bulbs.
As the GCF of 20 and 32 is 4, the gardener can make 4 rows.
Now divide 20 and 32 by 4.
Each row gets 5 rose bushes and 8 tulip bulbs.
A school has 20 red balls and 32 blue balls. They want to arrange them in groups with the same number of balls in each group, using the largest possible number of balls per group. How many balls will be in each group?
The GCF of 20 and 32
22 = 4.
So each group will have 4 balls.
There are 20 red and 32 blue balls. To find the total number of balls in each group, we should find the GCF of 20 and 32. There will be 4 balls in each group.
A chef has 20 kilograms of flour and 32 kilograms of sugar. He wants to divide both into equal portions of the longest possible length. What should be the weight of each portion?
For calculating the longest equal portion weight, we have to calculate the GCF of 20 and 32
The GCF of 20 and 32
22 = 4.
Each portion is 4 kilograms.
For calculating the longest portion weight, first, we need to calculate the GCF of 20 and 32, which is 4. The weight of each portion will be 4 kilograms.
A carpenter has two wooden planks, one 20 cm long and the other 32 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood
The GCF of 20 and 32
22 = 4.
The longest length of each piece is 4 cm.
To find the longest length of each piece of the two wooden planks, 20 cm and 32 cm, respectively, we have to find the GCF of 20 and 32, which is 4 cm.
The longest length of each piece is 4 cm.
If the GCF of 20 and ‘a’ is 4, and the LCM is 160, find ‘a’.
The value of ‘a’ is 32.
GCF x LCM = product of the numbers
4 × 160 = 20 × a
640 = 20a
a = 640 ÷ 20 = 32
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.