Summarize this article:
105 LearnersLast updated on September 24, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 162 and 192.
The greatest common factor of 162 and 192 is 6. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 162 and 192, a few methods are described below -
Steps to find the GCF of 162 and 192 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 162 = 1, 2, 3, 6, 9, 18, 27, 54, 81, 162.
Factors of 192 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 32, 48, 64, 96, 192.
Step 2: Now, identify the common factors of them Common factors of 162 and 192: 1, 2, 3, 6.
Step 3: Choose the largest factor The largest factor that both numbers have is 6.
The GCF of 162 and 192 is 6.
To find the GCF of 162 and 192 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime factors of 162: 162 = 2 x 3 x 3 x 3 x 3 = 2 x 34
Prime factors of 192: 192 = 2 x 2 x 2 x 2 x 2 x 3 = 26 x 3
Step 2: Now, identify the common prime factors The common prime factors are: 2 x 3
Step 3: Multiply the common prime factors 2 x 3 = 6.
The Greatest Common Factor of 162 and 192 is 6.
Find the GCF of 162 and 192 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 192 by 162 192 ÷ 162 = 1 (quotient), The remainder is calculated as 192 − (162×1) = 30
The remainder is 30, not zero, so continue the process
Step 2: Now divide the previous divisor (162) by the previous remainder (30) Divide 162 by 30 162 ÷ 30 = 5 (quotient), remainder = 162 − (30×5) = 12
Step 3: Now divide the previous divisor (30) by the previous remainder (12) 30 ÷ 12 = 2 (quotient), remainder = 30 − (12×2) = 6
Step 4: Now divide the previous divisor (12) by the previous remainder (6) 12 ÷ 6 = 2 (quotient), remainder = 12 − (6×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 162 and 192 is 6.
Finding the GCF of 162 and 192 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A baker has 162 chocolate chips and 192 sprinkles. She wants to make as many identical cookies as possible, using the largest possible number of chips and sprinkles in each cookie. How many chips and sprinkles will be in each cookie?
We should find the GCF of 162 and 192. GCF of 162 and 192 2 x 3 = 6.
There are 6 identical cookies. 162 ÷ 6 = 27 192 ÷ 6 = 32
Each cookie will have 27 chocolate chips and 32 sprinkles.
As the GCF of 162 and 192 is 6, the baker can make 6 cookies.
Now divide 162 and 192 by 6. Each cookie gets 27 chocolate chips and 32 sprinkles.
A music teacher has 162 drums and 192 tambourines. They want to arrange them in rows with the same number of instruments in each row, using the largest possible number of instruments per row. How many instruments will be in each row?
GCF of 162 and 192 2 x 3 = 6.
So each row will have 6 instruments.
There are 162 drums and 192 tambourines. To find the total number of instruments in each row, we should find the GCF of 162 and 192. There will be 6 instruments in each row.
A seamstress has 162 meters of silk fabric and 192 meters of cotton fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 162 and 192. The GCF of 162 and 192 2 x 3 = 6. The fabric is 6 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 162 and 192, which is 6. The length of each piece of fabric will be 6 meters.
A carpenter has two wooden planks, one 162 cm long and the other 192 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 162 and 192 2 x 3 = 6.
The longest length of each piece is 6 cm.
To find the longest length of each piece of the two wooden planks, 162 cm and 192 cm, respectively, we have to find the GCF of 162 and 192, which is 6 cm. The longest length of each piece is 6 cm.
If the GCF of 162 and ‘b’ is 6, and the LCM is 5184, find ‘b’.
The value of ‘b’ is 192.
GCF x LCM = product of the numbers
6 x 5184 = 162 x b
31104 = 162b
b = 31104 ÷ 162 = 192
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






