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112 LearnersLast updated on August 11, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 16 and 28.
The greatest common factor of 16 and 28 is 4. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 16 and 28, a few methods are described below - Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 16 and 28 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 16 = 1, 2, 4, 8, 16.
Factors of 28 = 1, 2, 4, 7, 14, 28.
Step 2: Now, identify the common factors of them Common factors of 16 and 28: 1, 2, 4.
Step 3: Choose the largest factor The largest factor that both numbers have is 4. The GCF of 16 and 28 is 4.
To find the GCF of 16 and 28 using Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 16: 16 = 2 × 2 × 2 × 2 = 24
Prime Factors of 28: 28 = 2 × 2 × 7 = 22 × 7
Step 2: Now, identify the common prime factors The common prime factors are: 2 × 2 = 22
Step 3: Multiply the common prime factors 22 = 4.
The Greatest Common Factor of 16 and 28 is 4.
Find the GCF of 16 and 28 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 28 by 16 28 ÷ 16 = 1 (quotient), The remainder is calculated as 28 − (16×1) = 12 The remainder is 12, not zero, so continue the process
Step 2: Now divide the previous divisor (16) by the previous remainder (12) Divide 16 by 12 16 ÷ 12 = 1 (quotient), remainder = 16 − (12×1) = 4
The remainder is 4, not zero, so continue the process
Step 3: Now divide the previous divisor (12) by the previous remainder (4) Divide 12 by 4 12 ÷ 4 = 3 (quotient), remainder = 12 − (4×3) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 16 and 28 is 4.
Finding GCF of 16 and 28 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 16 red roses and 28 white roses. She wants to arrange them into equal bunches with the largest number of flowers in each bunch. How many flowers will be in each bunch?
We should find the GCF of 16 and 28 GCF of 16 and 28 2 × 2 = 4. There are 4 equal bunches 16 ÷ 4 = 4 28 ÷ 4 = 7 There will be 4 bunches, and each bunch gets 4 red roses and 7 white roses.
As the GCF of 16 and 28 is 4, the gardener can make 4 bunches. Now divide 16 and 28 by 4. Each bunch gets 4 red roses and 7 white roses.
A construction company has 16 large bricks and 28 small bricks. They want to stack them in rows with the same number of bricks in each row, using the largest possible number of bricks per row. How many bricks will be in each row?
GCF of 16 and 28 2 × 2 = 4. So each row will have 4 bricks.
There are 16 large and 28 small bricks. To find the total number of bricks in each row, we should find the GCF of 16 and 28. There will be 4 bricks in each row.
A chef has 16 tablespoons of sugar and 28 tablespoons of flour. She wants to divide both into portions of equal size, using the longest possible length. What should be the size of each portion?
For calculating the longest equal size, we have to calculate the GCF of 16 and 28 The GCF of 16 and 28 2 × 2 = 4. The portion size is 4 tablespoons.
For calculating the longest size of the portions first, we need to calculate the GCF of 16 and 28 which is 4. The size of each portion will be 4 tablespoons.
A designer has two pieces of fabric, one 16 meters long and the other 28 meters long. He wants to cut them into the longest possible equal pieces, without any fabric left over. What should be the length of each piece?
The designer needs the longest piece of fabric GCF of 16 and 28 2 × 2 = 4. The longest length of each piece is 4 meters.
To find the longest length of each piece of the two pieces of fabric, 16 meters and 28 meters, respectively. We have to find the GCF of 16 and 28, which is 4 meters. The longest length of each piece is 4 meters.
If the GCF of 16 and ‘b’ is 4, and the LCM is 112. Find ‘b’.
The value of ‘b’ is 28.
GCF × LCM = product of the numbers 4 × 112 = 16 × b 448 = 16b b = 448 ÷ 16 = 28
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






