Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 12 and 28.
The greatest common factor of 12 and 28 is 4. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 12 and 28, a few methods are described below -
Steps to find the GCF of 12 and 28 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 12 = 1, 2, 3, 4, 6, 12.
Factors of 28 = 1, 2, 4, 7, 14, 28.
Step 2: Now, identify the common factors of them Common factors of 12 and 28: 1, 2, 4.
Step 3: Choose the largest factor
The largest factor that both numbers have is 4.
The GCF of 12 and 28 is 4.
To find the GCF of 12 and 28 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 12: 12 = 2 x 2 x 3 = 2² x 3
Prime Factors of 28: 28 = 2 x 2 x 7 = 2² x 7
Step 2: Now, identify the common prime factors
The common prime factors are: 2 x 2 = 2²
Step 3: Multiply the common prime factors 2² = 4.
The Greatest Common Factor of 12 and 28 is 4.
Find the GCF of 12 and 28 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 28 by 12
28 ÷ 12 = 2 (quotient), remainder is calculated as 28 − (12×2) = 4
The remainder is 4, not zero, so continue the process
Step 2: Now divide the previous divisor (12) by the previous remainder (4)
Divide 12 by 4 12 ÷ 4 = 3 (quotient), remainder = 12 − (4×3) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 12 and 28 is 4.
Finding GCF of 12 and 28 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 12 rose plants and 28 tulip plants. She wants to arrange them in equal rows with the largest number of plants in each row. How many plants will be in each row?
We should find the GCF of 12 and 28 GCF of 12 and 28 2² = 4.
There are 4 equal groups 12 ÷ 4 = 3 28 ÷ 4 = 7
There will be 4 groups, and each group gets 3 rose plants and 7 tulip plants.
As the GCF of 12 and 28 is 4, the gardener can make 4 groups. Now divide 12 and 28 by 4. Each group gets 3 rose plants and 7 tulip plants.
A coach has 12 footballs and 28 basketballs. He wants to store them in bins with the same number of balls in each bin, using the largest possible number of balls per bin. How many balls will be in each bin?
GCF of 12 and 28 2² = 4. So each bin will have 4 balls.
There are 12 footballs and 28 basketballs. To find the total number of balls in each bin, we should find the GCF of 12 and 28. There will be 4 balls in each bin.
A chef has 12 kg of flour and 28 kg of sugar. She wants to pack them into bags of equal weight, using the largest possible weight for each bag. What should be the weight of each bag?
For calculating the largest equal weight, we have to calculate the GCF of 12 and 28
The GCF of 12 and 28 2² = 4.
Each bag will weigh 4 kg.
For calculating the largest weight of the bags first, we need to calculate the GCF of 12 and 28, which is 4. The weight of each bag will be 4 kg.
A builder has two beams, one 12 meters long and the other 28 meters long. He wants to cut them into the longest possible equal pieces without any wood left over. What should be the length of each piece?
The builder needs the longest piece of wood GCF of 12 and 28 2² = 4.
The longest length of each piece is 4 meters.
To find the longest length of each piece of the two beams, 12 meters and 28 meters, respectively, we have to find the GCF of 12 and 28, which is 4 meters. The longest length of each piece is 4 meters.
If the GCF of 12 and ‘b’ is 4, and the LCM is 84, find ‘b’.
The value of ‘b’ is 28.
GCF x LCM = product of the numbers 4 × 84 = 12 × b
336 = 12b
b = 336 ÷ 12 = 28
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.