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Last updated on October 3, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 10 and 21.
The greatest common factor of 10 and 21 is 1.
The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 10 and 21, a few methods are described below -
Listing Factors Prime Factorization Long Division Method / Euclidean Algorithm
Steps to find the GCF of 10 and 21 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 10 = 1, 2, 5, 10. Factors of 21 = 1, 3, 7, 21.
Step 2: Now, identify the common factors of them Common factor of 10 and 21: 1.
Step 3: Choose the largest factor, The largest factor that both numbers have is 1.
The GCF of 10 and 21 is 1.
To find the GCF of 10 and 21 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 10: 10 = 2 x 5 Prime Factors of 21: 21 = 3 x 7
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Since there are no common prime factors, the GCF is 1.
The Greatest Common Factor of 10 and 21 is 1.
Find the GCF of 10 and 21 using the division method or Euclidean Algorithm.
Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 21 by 10 21 ÷ 10 = 2 (quotient), The remainder is calculated as 21 − (10×2) = 1 The remainder is 1, not zero, so continue the process.
Step 2: Now divide the previous divisor (10) by the previous remainder (1) Divide 10 by 1 10 ÷ 1 = 10 (quotient), remainder = 10 − (1×10) = 0, The remainder is zero, the divisor will become the GCF.
The GCF of 10 and 21 is 1.
Finding the GCF of 10 and 21 seems simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A teacher has 10 apples and 21 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 10 and 21. GCF of 10 and 21 is 1.
There are 1 equal groups. 10 ÷ 1 = 10 21 ÷ 1 = 21.
There will be 1 group, and each group gets 10 apples and 21 oranges.
As the GCF of 10 and 21 is 1, the teacher can make 1 group. Now divide 10 and 21 by 1.
Each group gets 10 apples and 21 oranges.
A school has 10 red chairs and 21 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 10 and 21 is 1.
So each row will have 1 chair.
There are 10 red and 21 blue chairs.
To find the total number of chairs in each row, we should find the GCF of 10 and 21.
There will be 1 chair in each row.
A tailor has 10 meters of red ribbon and 21 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 10 and 21.
The GCF of 10 and 21 is 1.
The ribbon is 1 meter long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 10 and 21, which is 1.
The length of each piece of the ribbon will be 1 meter.
A carpenter has two wooden planks, one 10 cm long and the other 21 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 10 and 21 is 1.
The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 10 cm and 21 cm, respectively, we have to find the GCF of 10 and 21, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 10 and ‘a’ is 1, and the LCM is 210. Find ‘a’.
The value of ‘a’ is 21.
GCF x LCM = product of the numbers 1 × 210 = 10 × a 210 = 10a a = 210 ÷ 10 = 21
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.