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Last updated on September 8, 2025
The perimeter of a shape is the total length of its boundary. The perimeter for curved shapes involves calculating the boundary that is not straight. Perimeter is also used for fencing a property, sewing, and more. In this topic, we will learn about the perimeter of curved shapes.
The perimeter of curved shapes is the total length around the shape. Unlike polygons, where the perimeter is the sum of straight sides, curved shapes involve arcs or curves.
For instance, the perimeter of a circle is called the circumference, calculated using the formula C=2πr, where r is the radius of the circle.
If a shape is a semicircle with a radius of 5, its perimeter is the sum of the straight line (the diameter) and the curved part (half the circumference), calculated as P = πr + 2r = π(5) + 10.
Let’s consider an example of a semicircle with a radius, r = 7.
The perimeter of the semicircle will be: P = πr + 2r = π(7) + 14 = 7π + 14.
To find the perimeter of curved shapes, apply the relevant formulas for each specific shape. For example, for a circle, use C=2πr.
For a given semicircle with a radius of 6, the perimeter is calculated as P = πr + 2r = π(6) + 12 = 6π + 12 cm. Example Problem on Perimeter of Curved Shapes -
For finding the perimeter of an ellipse, use the approximation formula P ≈ π(3(a + b) - √((3a + b)(a + 3b))).
For instance, if a=5 cm and b=3 cm, then: P ≈ π(3(5 + 3) - √((3*5 + 3)(5 + 3*3))) P ≈ π(24 - √(18*14))
Therefore, following the calculation, you will get the approximate perimeter.
Learning some tips and tricks makes it easier to calculate the perimeter of curved shapes. Here are some tips and tricks given below:
Always remember to use the correct formula for the specific shape you are dealing with, such as C=2πr for circles.
For shapes combining straight and curved edges, sum the lengths of all boundary parts. For example, the perimeter of a semicircle includes both the curved part and the diameter. When using approximations, especially for ellipses, be aware that they provide an estimate rather than an exact measure.
Ensure that measurements for radii and diameters are as precise as possible for accurate perimeter calculations.
In real-world applications, like designing tracks or garden paths, accounting for both the curved and straight portions of the boundary is crucial.
Did you know that while working with the perimeter of curved shapes, people might encounter some errors or difficulties? We have many solutions to resolve these problems. Here are some given below:
A circular garden has a circumference of 44 meters. If a portion of the garden is fenced along a semicircular path, what length of fencing is needed?
Length of fencing needed = 22 + 14 ≈ 36 meters.
The circumference of the circle is 44 meters, which gives us a diameter of 44/π.
For a semicircle, the perimeter includes half the circumference and the diameter: P = 22 + (44/2) = 22 + 22 = 44 meters.
Thus, the length of fencing needed is approximately 36 meters.
A racetrack is shaped like an ellipse with semi-major axis a = 150 meters and semi-minor axis b = 100 meters. Estimate the perimeter of the track using the approximation formula.
Approximately 785 meters.
Using the approximation for an ellipse:
P ≈ π(3(a + b) - √((3a + b)(a + 3b))) P ≈ π(3(150 + 100) - √((3*150 + 100)(150 + 3*100))) P ≈ π(750 - √(550*450))
Calculate the above to get an estimated perimeter of approximately 785 meters.
Find the circumference of a circle with a radius of 10 cm.
62.8 cm
Circumference of a circle = 2πr C = 2 * π * 10 ≈ 62.8 cm
Therefore, the circumference of the circle is approximately 62.8 cm.
A bridge arch is semicircular with a radius of 8 meters. Calculate the total length of the arch, including the base.
Annie will need 40.28 meters to go around the arch.
The perimeter of the semicircle includes the arc and the diameter. Using the formula: P = πr + 2r P = π(8) + 16 ≈ 40.28 meters.
Calculate the perimeter of a sector with a radius of 6 cm and a central angle of 90 degrees.
Approximately 18.85 cm.
The perimeter of a sector includes the arc length and the two radii.
Arc length = (θ/360) * 2πr P = (90/360) * 2π(6) + 2(6) ≈ 9.42 + 12 ≈ 18.85 cm.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables