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1422 LearnersLast updated on November 25, 2025

The modal class is the class interval with the highest frequency in a grouped distribution. It represents the range where most data is concentrated. Unlike a single mode in ungrouped data, the modal class gives a broader perspective on data distribution. Let us now see more about modal classes and how to calculate them.
The modal class is the class interval in a grouped frequency distribution that has the highest frequency, indicating the range in which the majority of data points are concentrated. Unlike the mode in ungrouped data, which identifies a single most frequent value, the modal class highlights the interval where values occur most often.
For example, find the modal class of marks for a class of 30 students, if the number of students scoring in different ranges is:
| Marks | Students |
| 0-10 | 2 |
| 10-20 | 5 |
| 20-30 | 15 |
| 30-40 | 8 |
| 40-50 | 3 |
The class interval with the highest frequency is 20-30. So, the modal class is 20-30.
Modal class formula is used to estimate the mode from grouped data when exact values are not known. The modal class formula is:
\(\text{Mode} = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h \)
Where,
L is the lower boundary of the modal class
f1 is the frequency of the modal class
f0 is the frequency of the class before the modal class
f2 is the frequency of the class after the modal class
h is the class width
The modal class is the group or range in a dataset that has the most values. To find a modal class, follow the following steps:
Step 1: If your data is not organized, divide it into intervals or classes.
Step 2: Identify the class interval with the highest frequency; this is the modal class.
Step 3: Apply the formula:
\(\text{Mode} = L + \left( \frac{(f_{1} - f_{0})}{(2f_{1} - f_{0} - f_{2})} \right) \times h\)
Where,
L is the lower limit of the modal class
f0 is the frequency of the modal class
f1 is the frequency of the class preceding the modal class
f2 is the frequency of the class succeeding the modal class
h is the class width.
Step 4: Substitute the values and compute to get the modal class where the data is most concentrated.
For example, find the modal class of marks for a class of 30 students, if the numbers of students scoring in different range is:
| Marks | Students |
| 0-10 | 5 |
| 10-20 | 8 |
| 20-30 | 12 |
| 30-40 | 20 |
| 40-50 | 10 |
| 50-60 | 5 |
Here, the highest frequency is 20
So, the modal class is 30-40
Identifying the values for the formula:
\(L = 30 \\ \ \\ f-0 = 20 \\ \ \\ f_1 = 12 \\ \ \\ f_2 = 10 \\ \ \\ h = 10 \)
Applying the formula: \(\text{Mode} = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h \)
\(\text{Mode} = 30 + \frac{20 - 12}{2 \cdot 20 - 12 - 10} \times 10 \)
\(= 30 + {8 \over {40 - 22}} × 10\)
\(= {30} + {8 \over 18} \times 10\)
\(= 30 + 4.44\)
= 34.44
Therefore, the modal value of the marks is approximately 34.44.


To find the modal class from a chart or graph, follow the steps mentioned below:
Step 1: Identify the highest bar or peak:
In a histogram, look for the tallest bar (highest frequency). In a frequency polygon, find the highest peak on the graph. For the bar chart, locate the category with the highest bar.
Step 2: Read the class interval:
The modal class is the interval corresponding to the tallest bar or peak. If two bars have the same highest frequency, then the given dataset is bimodal or multimodal.
Step 3: Estimate the mode using the formula:
If needed, apply the mode formula for grouped data:
\(\text{Mode} = L + \left( \frac{(f_{1} - f_{0})}{(2f_{1} - f_{0} - f_{2})} \right) \times h\)
Where,
L is the lower limit of the modal class
fm is the frequency of the modal class
f1 is the frequency of the class preceding the modal class
f2 is the frequency of the class succeeding the modal class
h is the class width.
For example, find the modal class from the graph.
| Marks | Number of Students |
| 0-10 | 5 |
| 10-20 | 8 |
| 20-30 | 12 |
| 30-40 | 20 |
| 40-50 | 10 |
| 50-60 | 5 |
Here, the tallest bar corresponds to 30-40, so this is the modal class.
Using the Mode formula: \(\text{Mode} = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h \)
Where,
\(L = 30 \\ \ \\ f_1 = 20 \\ \ \\ f_0 = 12 \\ \ \\ f_2 = 10 \\ \ \\ h = 10 \)
\(\text{Mode} = L + \frac{f_1 - f_0}{2f_1 - f_0 - f_2} \times h \)
\(= 30 + \frac{20 - 10}{2 \times 20 -12- 12} \times 10 \)
\(= 30 + {8 \over 18} \times 10\)
\(= 34.44\)
So, modal class is 30-40 and mode is 34.44 marks.
To master the model class, focus on identifying the class interval with the highest frequency and on applying the mode formula to real-life datasets.
When understanding the concept of modal class, students tend to make mistakes. Here, are some common mistakes and solutions:
There are many uses of the modal class. Let us now see the uses and applications of modal classes in different fields:
The modal class is used in sports to identify the most common performance range among athletes, such as the most frequent running times or game scores, and to plan training programs accordingly.
In weather and climate studies, modal classes are used to identify the most common temperature ranges in a city, determine typical rainfall levels in a region, and predict agricultural and disaster-management patterns.
Given the frequency distribution below, identify the modal class
The modal class here is 30 – 40.
Look at the frequency column.
Identify the highest frequency
Frequencies: 5, 12, 20, 15
The highest frequency is 20
Class interval with frequency 20 is 30 – 40.
Consider the following frequency table. Identify the modal class or classes
The modal classes are 20 – 30 and 30 – 40.
The given frequencies: 3, 7, 10, 10, 8
The highest frequency is 10, and it appears in 20 – 30 and 30 – 40.
Since the two classes share the highest frequency, the distribution is bimodal.
Given the grouped data below, find the mode of the data:
The estimated mode is 36.15.
Identify the modal class:
The highest frequency is 20, which appears in the intervals 20–30 and 30–40.
Assign the values:
L = 30
f1 = 20
fm = 12
f2 = 15
h = 10
Apply the formula
\(\text{Mode} = L + \left( \frac{(f_{1} - f_{0})}{(2f_{1} - f_{0} - f_{2})} \right) \times h\)
Mode \(= 30 + \left( \frac{20 - 12}{2(20) - 12 - 15} \right) \times 10\)
\(= 30 + \left( \frac{8}{40 - 12 - 15} \right) \times 10\)
\(= 30 + \left( \frac{8}{13} \right) \times 10\)
\(= 30 + 6.15\)
= 36.15
Using the mode formula, calculate the mode for the following data:
The estimated mode is approximately 66.67.
Identify the modal class:
The highest frequency is 25 in 60 – 70.
Assign the values:
L = 60
f1 = 25
fm = 15
f2 = 20
h = 10
Apply the formula:
\(\text{Mode} = L + \left( \frac{(f_{1} - f_{0})}{(2f_{1} - f_{0} - f_{2})} \right) \times h\)
\(= 60 + \left( \frac{25 - 15}{2(25) - 15 - 20} \right) \times 10\)
\(= 60 + \left( \frac{10}{50 - 15 - 20} \right) \times 10\)
\(= 60 + \left( \frac{10}{15} \right) \times 10\)
= 60 + 6.67
= 66.67.
Given the grouped data below, identify the modal class(s) and estimate the mode. Choose one modal class for the calculation.
The distribution is bimodal with modal classes 35 – 45 and 45 – 55; using the first modal class, the estimated mode is 45.
Identify the modal classes:
The highest frequency is 12, which occurs in both 35 – 45 and 45 – 55.
Choose one for calculation:
35 – 45.
Assign the values:
L = 35
f1 = 12
fm = 9
f2 = 12
h = 10
Apply the formula:
\(\text{Mode} = L + \left( \frac{(f_{1} - f_{0})}{(2f_{1} - f_{0} - f_{2})} \right) \times h\)
\(\text{Mode} = 35 + \left( \frac{12 - 9}{2(12) - 9 - 12} \right) \times 10\)
\(= 35 + \left( \frac{3}{3} \right) \times 10\)
= 35 + 10 = 45.
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






