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1273 LearnersLast updated on November 26, 2025

Frequency polygons are the graphical visualizations used to understand data distribution in a dataset. They represent values in a distribution through a specific shape. This graphical representation is commonly used in statistics which helps to compare multiple datasets and identify trends and patterns of data. In this topic, we will explore the frequency polygons.
Frequency polygons are a fundamental graphical tool in statistics. They represent the frequency distribution of continuous data. In the late 19th century, the frequency polygon was first introduced by the English statistician Karl Pearson.
A frequency polygon shows the distribution of a dataset across different class intervals. It helps to simplify and organize large datasets for easier understanding. It represents data using a line graph that connects the midpoints of the other intervals.
For example,
If a teacher records the marks of students and groups them into class intervals:
| Marks (Class interval) | Frequency |
| 0-10 | 3 |
| 10-20 | 7 |
| 20-30 | 12 |
| 30-40 | 9 |
| 40-50 | 4 |
Here,
First, find the midpoints of each interval
Now, plot each midpoint against its frequency
\((5, 3), (15, 7), (25, 12), (35,9), (45, 4)\)
Connect the points with straight lines. The resulting line graph is the frequency polygon, showing how students marks are distributed across the intervals.
Now, let us learn how to draw a frequency polygon. Like a regular graph, a frequency polygon has two axes, one is the x-axis, and the next is the y-axis. On both the x-axis and y-axis, the frequency polygon’s curve is depicted. In the x-axis, the various values in a dataset are represented, while the number of occurrences in each category is represented by the y-axis.
While drawing a frequency polygon, the most important aspect to consider is the class intervals. We can depict a frequency polygon with or without a histogram. Histograms are rectangular bars that represent the information or values in a dataset. So, if we draw a frequency polygon with a histogram, we first draw the rectangular bars for each class interval.
Later, connect the bar’s midpoints to form a frequency polygon. Below are some steps, that we should follow while drawing a frequency polygon without a histogram:
Step 1: Mark the class intervals on the x-axis and plot the frequencies on the y-axis.
Step 2: Calculate the midpoints of each class interval, or the class marks.
Step 3: Plot the class marks on the x-axis.
Step 4: Plot the frequency based on each class mark on the height. Be sure to mark it on the same class mark, not at the higher or lower limit of the interval.
Step 5: After marking the points, connect them with line segments. These are similar to a line graph.
Step 6: After this, we get a curve known as the frequency polygon.
When drawing a frequency polygon, we need a critical value for each class interval, the midpoint, also called the class mark. This midpoint tells us the middle value of a class interval and helps us place each point correctly on the graph.
Formula for midpoint
\(\text{Midpoint (Class mark)} = \frac{\text{Upper limit} + \text{Lower limit}}{2} \)
For example,
If we have a class interval, 20-30
Lower limit = 20
Upper limit = 30
By using the formula,
\(\text{Midpoint} = \frac{20 + 30}{2} = \frac{50}{2} = 25 \)
So, 25 is the midpoint of the interval 20 - 30.
This midpoint represents the entire class interval on the frequency polygon.
Data presented in the form of class intervals and frequencies is graphically represented by a frequency polygon graph. It allows us to analyze and compare large datasets while identifying patterns and trends in data distribution. For a better understanding, we can consider an example. Here is a frequency table that shows the goals scored by students in a match:
| Goals scored | Frequency |
| 0 | 3 |
| 1 | 6 |
| 2 | 5 |
| 3 | 7 |
| 4 | 4 |
| 5 | 5 |
For the above frequency table, we can plot the frequency polygon by marking the frequency on the x-axis and the goals scored on the y-axis.
The cumulative frequency polygon depicts the cumulative frequencies of a given dataset. In this graph, the dots are plotted at the upper-class borders against the corresponding cumulative frequencies. After that, the dots are connected by a line and result in a cumulative frequency polygon. The accumulation of data over time or intervals is illustrated by these graphs. Now, let us consider an example. Here is a frequency table showing the marks scored by students for the English exam:
| Marks scored | Frequency | Cumulative frequency |
| 0 - 10 | 3 | 3 |
| 11 - 20 | 5 | 8 |
| 21 - 30 | 11 | 19 |
| 31 - 40 | 6 | 25 |
| 41 - 50 | 3 | 28 |
For the above frequency table, we can plot the cumulative frequency polygon by marking the frequency on the y-axis and the marks scored on the x-axis. When we calculate the cumulative frequency, we add up the
frequencies \( ( 3 + 5 = 8)\).
A frequency polygon is a graphical representation of data that is represented in the form of class intervals and frequencies. It is similar to histograms, but a frequency polygon uses line segments to join the midpoints of each class interval. The main differences between these two graphs are listed below:
A frequency polygon is drawn using the x-axis and y-axis, just like a regular graph.
The most important part of creating a frequency polygon is finding the midpoints of each class interval. A frequency polygon can be drawn with or without a histogram. When drawn with a histogram, you simply connect the midpoints at the top of each bar.
Here, we focus on drawing a frequency polygon without a histogram.
Step 1: Write the class intervals on the x-axis, and mark the corresponding frequencies on the y-axis.
Step 2: Calculate the midpoint for each interval using,
\(\text{Midpoint} = \frac{\text{Upper limit} + \text{Lower limit}}{2} \)
Step 3: Plot these midpoints along the x-axis.
Step 4: For each midpoint, plot its frequency directly above it on the y-axis.
Step 5: Connect all the plotted points using straight line segments, just like drawing a line graph.
Step 6: The connected line forms the frequency polygon, representing the frequency distribution clearly and neatly.
Frequency polygons are a complex mathematical concept. In this section, we will discuss some important tips and tricks to master frequency polygons.
Drawing a frequency polygon is simple, and the data comparison becomes easier with these types of graphs. However, some common mistakes can happen and will lead to inaccurate data comparison and interpretation. Here are some common errors and their helpful solutions for frequency polygons.
A frequency polygon is a graphical representation of data using line segments, which form a curve. In various fields, the frequency polygons are commonly used to interpret data and identify trends and patterns. Here are some of the real-world applications of frequency polygons:
If the pages range of pages students read in a week in a reading club is distributed by 0 - 50, 50 - 100, 100 - 150, 150 - 200, 200 - 250. What would be the class marks for each page range?
\(0 - 50 = 25ย \)
\(50 - 100 = 75\)
\(100 - 150 = 125\)
\(150 - 200 = 175\)
\(200 - 250 = 225\)
To calculate the classmark for a frequency polygon graph, we use the formula:
Class mark (Midpoint) = \( \frac{\text{Upper Limit} + \text{Lower Limit}}{2} \)
Hence, Class interval \(0 - 50\) = \( \frac{50 + 0}{2} = 25 \)
Class interval \(50 - 100\) = \( \frac{100 + 50}{2} = 75 \)
Class interval \(100 - 150\) = \( \frac{150 + 100}{2} = 125 \)
Class interval\(150 - 200\) = \( \frac{200 + 150}{2} = 175 \)
Class interval \(200 - 250 \) = \( \frac{250 + 200}{2} = 225 \)
If the weight range for a class of 50 students is distributed by 30 - 40, 40 - 50, 50 - 60, 60 - 70. What would be the class marks for each weight range?
\(30 - 40 โ 35\)
\(40 - 50 โ 45\)
\(50 - 60 โ 55\)
\(60 - 70 โ 65\)
To calculate the classmark for a frequency polygon graph, we use the formula,\( \text{Classmark} = \frac{\text{Upper Limit} + \text{Lower Limit}}{2} \)
Hence, the classmarks \(30 - 40\) =\( \frac{30 + 40}{2} = 35 \)
The classmarks \(40 - 50\) = \( \frac{40 + 50}{2} = 45 \)
The classmarks \(50 - 60\) = \( \frac{60 + 50}{2} = 55 \)
The classmarks \( 60 - 70\) = \( \frac{70 + 60}{2} = 65 \)
If the age group of employees in a company is distributed as 20โ30, 30โ40, 40โ50, 50โ60, and 60โ70, what would be the class marks for each group?
\(20โ30 โ 25\)
\(30โ40 โ 35\)
\(40โ50 โ 45\)
\(50โ60 โ 55\)
\(60โ70 โ 65\)
\( \text{Classmark} = \frac{\text{Upper Limit} + \text{Lower Limit}}{2} \)
So,
\(20โ30\) = \( \frac{20 + 30}{2} = 25 \)= 25
\(30โ40 \)= \( \frac{30 + 40}{2} = 35 \) = 35
\(40โ50\) = \( \frac{40 + 50}{2} = 45 \) = 45
\(50โ60\) =\( \frac{50 + 60}{2} = 55 \) = 55
\(60โ70\) = \( \frac{60 + 70}{2} = 65 \) = 65
The temperature (in ยฐC) recorded for a week is grouped as 10โ20, 20โ30, 30โ40, 40โ50. Find the class marks.
\(10โ20 โ 15\)
\(20โ30 โ 25\)
\(30โ40 โ 35\)
\(40โ50 โ 45\)
\( \frac{10 + 20}{2} \)= 15
\( \frac{20 + 30}{2} \) = 25
\( \frac{30 + 40}{2} \)= 35
\( \frac{40 + 50}{2} = 45 \)
The number of hours students study in a week is distributed as 5โ10, 10โ15, 15โ20, 20โ25, 25โ30. Find the class marks.
\(5โ10 โ 7.5\)
\(10โ15 โ 12.5\)
\(15โ20 โ 17.5\)
\(20โ25 โ 22.5\)
\(25โ30 โ 27.5\)
\( \frac{5 + 10}{2} \) = 7.5
\( \frac{10 + 15}{2} \) = 12.5
\( \frac{15 + 20}{2} \) = 17.5
\( \frac{20 + 25}{2} \) = 22.5
\( \frac{25 + 30}{2} \) = 27.5
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle gamesโthe more you play with them, the clearer the picture becomes!






