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Last updated on November 27, 2025

Mean of Grouped Data

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The mean is the average of arithmetical data. The mean of grouped data is the mean data of grouped sets, categories, objects, etc. The mean of a set of values is found by adding all the values together and dividing by the total number of values.

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What is the Mean of Grouped Data?

The mean of grouped data is the average value of the data organized into classes or groups. Such data, arranged in groups or categories, is called grouped data, in which each class interval shows a range of values, and the frequency indicates how many observations fall within that range. The mean, also known as the central value, helps us understand the overall trend of the data. For grouped data, we use the midpoint of each class to calculate the mean

 

In statistics, the mean is the sum of all observations divided by the total number of observations. The mean is denoted as \(\bar x\) (x bar). That is:
 

\( x = x_1 + x_2 + x_3 + …. + x_n.\)

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Mean of Grouped Data Formula

The mean of grouped data is calculated using the midpoint (class mark) of each class interval along with its frequency. The central value of its interval is known as the midpoint. By multiplying these midpoints by their respective frequencies and dividing the total by the overall frequency. The formula for the mean of grouped data is: 
 

\({\bar x} = {{∑{f_i} {x_i} \over N }}\)
 

Where,

 
\(\bar x\) is the mean value of the set of given data


\(f_i\) is the frequency of the individual data


\(x_i\) is the midpoint of each class interval 


N is the sum of the frequencies
 

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How to Find the Mean of Grouped Data?

The mean of grouped data is a measure of central tendency that represents the average value of a dataset organized into classes. The different methods to calculate the mean of grouped data are: 
 

  • Direct Method
     
  • Assumed Mean Method
     
  • Step Deviation Method

     

Direct Method


The direct method is the simplest method used to calculate the mean of grouped data. If the values of the observations are \(x_1, x_2,..., x_n\), with their corresponding frequencies being \(f_1, f_2,..., f_n\). Then the mean of the data is given by,
 

 \(x = \frac{x_1f_1 + x_2f_2 + \cdots + x_n f_n}{f_1 + f_2 + \cdots + f_n} \)

 

    \(x = \frac{\Sigma (f \times x)}{\Sigma f} \), where i = 1, 2, 3, 4,...n

 

To find the mean of grouped data, follow these steps: 
 

  • Create a table and organize the data into class intervals with their frequencies. Each class interval represents the range of a group, and the midpoints xi represent the central value of the interval: 

    \(x_i = \frac{\text{lower limit} + \text{upper limit}}{2} \)
     
  • Multiply each point xi by its frequency \(f_i\).
     
  • Then substitute the values in the formula:  \({\bar x} = {{\frac{\sum x_i f_i}{\sum f_i} }}\)

 

For example, a class of students scored the following marks in a test. Find the mean marks. 

 

Mark Number of Students 
0-10 2
10-20 3
20-30 5
30-40 4
40-50 6

 

To find the midpoints (xi) of each class using the formula: \(x_i = \frac{\text{lower limit} + \text{upper limit}}{2} \)


 

Mark Number of Students  Midpoint (\(x_i\) \({{f_i} {x_i}}\)
0-10 2 \({{0 + 10}\over 2 } = 5\) \(2 \times 5 = 10 \)
10-20 3 \({{10 + 20}\over 2 } = 15\) \(3 \times 15 = 45\)
20-30 5 \({{20 + 30}\over 2 } = 25\) \(5 \times 25 = 125 \)
30-40 4 \({{30 + 40}\over 2 } = 140\) \(4 \times 35 = 140\)
40-50 6 \({{40 + 50}\over 2 } = 270\) \( 6 \times 45 = 270\)

 

Sum the frequencies and sum the products: 
 

\(Σf_i = 2 + 3 + 5 + 4 + 6 = 20\)

 

\(Σf_ix_i = 10 + 45 + 125 + 140 + 270 = 590\)

 

Finding the mean of grouped data using the formula: \(\bar{x} = \frac{\sum f_i x_i}{N} \)


\({\bar x} ={{590 \over 20 }} \)


= 29.5

 

Assumed Mean Method

The assumed mean method is used to estimate the mean of a large dataset. In this method, a value from the dataset is chosen as an assumed mean (a), and the deviations of all midpoints from this assumed mean are calculated. 

Let the deviation of each midpoint from the assumed mean be: \(d_i = x_i - a\)

Then the mean is calculated as: 



  \(\bar{x} = \frac{\sum (a + d_i) f_i}{\sum f_i} \)

 

\(\bar{x} = a + \frac{\sum ( f_i d_i)}{\sum f_i}\)


Find the mean of the following grouped data using the assumed mean method. 

 

Class Interval Frequency (f)
10-20 5
20-30 8
30-40 12
40-50 7
50-60 3

 

To find the midpoint, xi, we use the formula: 

\(x_i = \frac{\text{lower limit} + \text{upper limit}}{2} \)

 

Here, the midpoints are 15, 25, 35, 45, and 55

Let a = 35

Then deviations, di is calculated using the formula \(d_i = x_i - a\)

Class Interval Frequency (f) \(x_i\) \({d_i} = {x_i} - a\) \({f_i} \cdot {d_i}\)
10-20 5 15 -20 -100
20-30 8 25 -10 -80
30-40 12 35 0 0
40-50 7 45 10 70
50-60 3 55 20 60

 

Applying the assumed mean formula: \(\bar{x} = a + \frac{\sum f_i d_i}{\sum f_i} \)
 

\({d_if_i} = (-100) + (-80) + 0 + 70 + 60 = -50\)
 

\(Σf_i = 5 + 8 + 12 + 7 + 3 = 35 \)

 

\( = {{35 + -50} \over { 35 }}\)

 

\(= 35 - 1.43\)

 

= 33.57

 

Step Deviation Method     

The step deviation method is used when the values in a data set are large and far from the assumed mean. Here, deviations are divided by the class size h to simplify calculations:     

\(\bar{x} = a + h \cdot \frac{\sum f_i u_i}{\sum f_i} \)
 

Where, 
 

a is the assumed mean
 

h is the class size
 

ui = \(\frac{d_i}{h} \)

 

For example, find the mean of the following data using the step deviation method. 

 

Class Interval Frequency
100-110 5
110-120 8
120-130 12
130-140 7
140-150 3

 

Finding the midpoints xi using:

\(x_i = \frac{\text{lower limit} + \text{upper limit}}{2} \)

 

Here, the midpoints are 105, 115, 125, 135, 145


Let the assumed mean: a = 125


Calculating deviation and step deviation:

 

\(d_i = x_i - a \)
 

\(u_i = \frac{d_i}{h} \), where h = 10
 

Class Interval Frequency \(x_i\) \(d_i = x_i - a\) \(u_i = {d_i \over h}\) \({f_i u_i}\)
100-110 5 105 -20 -2 -10
110-120 8 115 -10 -1 -8
120-130 12 125 0 0 0
130-140 7 135 10 1 7
140-150 3 145 20 2 6

 

\(f_iu_i = -10 + -8 + 0 + 7 + 6 = -5 \)
 

\(f_i = 5 + 8 + 12 + 7 + 3 \)


Substituting the values in the equation: \(\bar{x} = a + h \cdot \frac{\sum f_i u_i}{\sum f_i} \)
 

\(\bar{x} = 125 + 10 \left( -\frac{5}{35} \right) \)

 

\(= {125 - 1.43}\)

 

\(\bar {x} = 123.57\)

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Tips and Tricks to Master Mean of Grouped Data

Mean of Grouped data is a complex mathematical topic and therefore some tips and tricks can be helpful. In this section we discuss such tips and tricks.

 

  • Check for equal class intervals: Make sure all class intervals are equal before applying short-cut or step-deviation methods. If not, use the direct method.
     
  • Cross-verify the mean: After calculating, quickly check your results using both the direct and short-cut methods for accuracy.
     
  • Practice with real data: Use practical examples (like marks, income, or temperature data) to strengthen your conceptual understanding.
     
  • Use a calculator or spreadsheet for speed: When dealing with large grouped data, use tools like Excel or a calculator to speed up computation while focusing on the logic behind the steps.
     
  • Choose an appropriate assumed mean (a): Select a class mark from the middle of the data as the assumed mean — it keeps deviations small and calculations easier.
     
  • Encourage understanding: Parents can help students understand the formula and its logic rather than memorize it. 
     
  • Provide step-by-step practice: Teachers can use structured tables for midpoints, frequencies, and deviations to help students visualize and organize calculations.
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Common Mistakes of Mean of Grouped Data and How to Avoid Them

The possibility of kids making mistakes while doing mean grouped data is high. This is not similar to finding the ordinary mean value. Here are some of the few common mistakes that kids might make and how to avoid them.
 

Mistake 1

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Incorrect using or summing frequency values.

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Carefully review the given frequency distribution and verify the total frequency before performing division to prevent calculation errors.

Mistake 2

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Rounding off too early in intermediate steps.
 

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Keep all calculations in full precision until the final answer, then round off to the required decimal places. 
 

Mistake 3

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Confusing grouped data mean with individual data mean formulas.
 

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Understand that for grouped data, you use midpoints and frequencies, whereas for individual data, you sum up the values and divide by the count. Always apply the correct formula based on the data type. 

Mistake 4

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Skipping frequencies while calculating the mean.

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Ensure all class intervals are included when summing f × x and f. Skipping a row or copying the wrong frequency can lead to incorrect results.

Mistake 5

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 Mistakenly using cumulative frequency instead of class frequency.

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Use the actual frequency (f) for each class when calculating f  x, not the cumulative frequency, which is used for other statistical measures like the median.

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Real-Life Applications of Mean of Grouped Data

The mean of grouped data is used in many real-life situations where data is collected in ranges. Here are some important applications: 

 

  • Education: Teachers use the mean of grouped data to evaluate students’ overall performance based on their scores in exams. 

 

  • Business and economics: Companies use grouped data to analyze the average salary of employees across different departments.
     
  • Healthcare: Hospitals analyze patient data, such as average blood pressure, weight, or cholesterol levels, using grouped data.
     
  • Agriculture: Farmers use the mean of grouped data to determine the average crop yield from different plots of land or over several seasons.
     
  • Weather analysis: Meteorologists calculate the mean temperature, rainfall, or humidity over grouped time intervals (like weeks or months) to study climate patterns.

 

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Solved Examples On Mean of Grouped Data

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Problem 1

A teacher records the test scores of students in a class as follows: Score Range 40 - 50, 50-60, 60-70, 70-80 Frequency 3, 5, 8, 4. Find the mean score.

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The mean score is 63.75.

Explanation

Find class midpoints

\(\begin{align*} \frac{40 + 50}{2} &= 45 \\ \ \\ \frac{50 + 60}{2} &= 55 \\ \ \\ \frac{60 + 70}{2} &= 65 \\ \ \\ \frac{70 + 80}{2} &= 75 \end{align*} \)

 

Multiply each midpoint by its frequency:
 

\((45 \times 3) + (55 \times  5) + (65 \times 8) + (75 \times  4)\)
 

\(= 135 + 275 + 520 + 300\)

 

= 1230

 

Sum of frequencies: \(3 + 5 + 8 + 4 = 20\)

 

Mean = \(\frac{1230}{20} = 61.5 \) 
 

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Problem 2

The following table shows the number of hours students spend studying in a week. Hours studied : 0-5 , 5-10 , 10-15, 15-20 , frequency : 6, 10, 8, 6. Find the mean number of hours studied.

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The mean study time is 9.58 hours.

Explanation

Find the class midpoints 


\(\begin{align*} \frac{0 + 5}{2} &= 2.5 \\ \ \\ \frac{5 + 10}{2} &= 7.5 \\ \ \\ \frac{10 + 15}{2} &= 12.5 \\ \ \\ \frac{15 + 20}{2} &= 17.5 \end{align*} \)

 

Multiplying each midpoint by its frequency 

 

\((2.5 ×  6) + (7.5 × 10) + (12.5 × 8) + (17.5 × 6)\)
 

\(= 15 + 75 + 100 + 105\)

 

\(= 295\)

 

 

Sum of frequencies: \(6 + 10 + 8 + 6 = 30\)

 

Mean = \(\frac{295}{30} = 9.83\overline{3} \)
 

= 9.58
 

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Problem 3

The speed (in km/h) of vehicles on a highway is recorded for 50 vehicles. Speed (km/h) : 40 - 50 , 50 - 60 , 60 - 70 , 70 - 80 , 80 - 90 Frequency (Vehicles) : 5. 10, 15, 12 , 8. Find the mean speed of vehicles.

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The mean speed is 66 km/h.

Explanation

Find class midpoints: 


\(\begin{align*} \frac{40 + 50}{2} &= 45 \\ \ \\ \frac{50 + 60}{2} &= 55 \\ \ \\ \frac{60 + 70}{2} &= 65 \\ \ \\ \frac{70 + 80}{2} &= 75 \\ \ \\ \frac{80 + 90}{2} &= 85 \end{align*} \)


Multiply each midpoint by its frequency 


\((45 × 5) + (55 × 10) + (65 × 15) + (75 × 12) + (85 × 8)\)

 

\(= 225 + 550 + 975 + 900 + 680 \)

 

\(= 3330\)

 

Sum of frequencies: 5 + 10 + 15 + 12 + 8 = 50

 

Mean = \(\frac{3330}{50} = 66.6 \) 

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Jaipreet Kour Wazir

About the Author

Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref

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Fun Fact

: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!

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