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1570 LearnersLast updated on November 25, 2025

Some events are called dependent events because they are influenced by the results of events that had occurred previously. If the outcome of the event A is changed, then the outcome of the event B, occurring after the first event, is likely to be changed. Here, A and B are dependent events. In this topic, we are going to learn about dependent events and why it’s important.
Dependent events are events in probability where the outcome of one event affects or changes the probability of another event. In other words, once one event occurs, it affects the likelihood of another event happening afterward.
For example, if you have a jar containing five red marbles and five blue marbles. You pick one marble and do not put it back. Then you pick another marble.
If the first marble is red, there are now fewer red marbles left in the jar.
Because the first pick affects the second pick, these are dependent events.
In probability, an event is any possible outcome or a group of outcomes from a random experiment. It represents what we observe or measure during the experiment. Events are classified by how their outcomes relate to each other. The main types of events are:
Independent and dependent events differ in whether the outcome of one event influences the probability of the other—the difference between independent and dependent events.
| Dependent Event |
Independent Event |
| In a dependent event, the outcome of one event changes or influences the probability of the next event. | In an independent event, the outcome of one event does not affect the probability of another. |
| Dependent events occur mainly in situations where sampling is done without replacement. | In an independent event, the sampling is done with replacement. |
| The occurrence of the first event directly affects the likelihood of the second. | The occurrence of one event does not impact the outcome of the other. |
| \(P(A \text{ and } B) = P(A) \times P(B \mid A) \) | \(P(A \text{ and } B) = P(A) \times P(B) \) |
| For example, drawing cards from a deck without replacement | For example, flipping a coin and rolling a die |
Dependent events are events in which the outcome of one event influences or changes the result of another. These events play an important role in probability, decision-making, and real-world predictions. Below are the key properties of dependent events:
When one event occurs, it can alter the number of remaining possible outcomes. For example, drawing a card from a deck without replacing it reduces the total number of cards for the next draw.
Dependent events do not always have a direct or obvious connection. For example, bad weather might increase the number of car accidents. Weather and accidents are different, but they affect each other.
The sequence in which events happen can affect the probabilities of dependent events. For example, drawing cards one after another without replacement is different from drawing with replacement.
The probability of dependent events is based on conditional probability, which tells us how likely one event is to occur given that another has already happened. In dependent events, the outcome of the first event changes the probability of the second event.
For example, a box has three red balls and two blue balls. You pick one ball and do not put it back. Then you pick a second ball. Since the first ball is not replaced, the number of balls changes. This means the probability of the second pick depends on what was picked first, so the events are dependent.
The probability of dependent events is the chance that one event occurs after another. The formula for finding the probability of dependent events uses conditional probability. It is written as:
\(P(B | A) = {{P (A ∩ B) \over P (A)}}\)
Where P(A ∩B) is the probability that both events A and B occur
P(A) is the probability that event A happens.
To find the probability of a dependent event, we use the concept of conditional probability. This helps us determine how likely an event is to occur after another event has already occurred.
If event A happens first and event B occurs next, the probability of event B after A is written as P(B | A). The formula is:
\(P(B | A) = {P (A ∩ B) \over P (A)}\)
For example, a jar contains three red candies and two blue candies. You pick one candy and do not put it back. Then you pick another candy. If you like a red candy first, what is the probability that you will enjoy a blue candy second?
To find the probability of picking blue candy, we use the formula:
\(P(B | A) = {P (A ∩ B) \over P (A)}\)
Let, the probability of picking a red candy be event A and the probability of picking a blue candy be B.
Finding P(A):
There are 3 red and 2 blue candies, so the total is 5
P(A) = \(3\over 5\)
After picking a red, the total candies left = 4
So, the remaining blue candies = 2
So, \(P(B|A) = {{2\over 4}} = {{1\over 2}}\)
So, the probability of picking a blue candy second after picking a red candy first is \(1 \over 2\).
Helping children understand dependent events becomes much easier when learning is grounded in simple examples and hands-on activities. Here are a few tips and tricks to master dependent events.
When dealing with dependent events, students can make mistakes. Learning about the following common mistakes can help us avoid them:
We use the concept of dependent events on a daily basis. It is widely used in environmental sciences and various other fields.
A bottle contains 5 red balls and 3 blue balls. Two balls are drawn without replacement. What is the probability that both balls are red?
The probability that both balls are red is \(5\over14\).
We use the formula, \(P{{(A {\text { and }} B)}} = {{P(A) × P(B | A)}}\).
P(Red1 and Red2) \(= {{5\over8} × {4\over 7}} = {20\over 56} = {5\over 14}\)
Step 1: Probability of first red \(= {{5\over 8}}\)
Since a ball is taken and not replaced, there will be 4 red balls and a total of 7 balls remaining.
Step 2: Probability of second red (without replacement) \(= {{4\over 7}} \)
Now we multiply the probabilities to get the final answer. So, \({5\over 8} × {4\over 7} = {20\over 56} = {{5\over 14}}\)
In a deck, there are 52 cards. What is the probability of drawing a King followed by a Queen without replacement?
\(4\over 663\).
We use the formula, \(P(A {\text {and }}B) = P(A) × P(B | A)\).
If a class has 12 boys and 8 girls. Two students are chosen randomly, what is the probability that both students chosen are girls?
\(14\over 95\)
We use the formula, \(P(A {\text { and }}B) = P(A) × P(B | A)\).
P(Girl1 and Girl2) = \({8\over20} × {7\over19} = {56\over380} = {14\over95}\)
A box contains 3 dark chocolates and 5 milk chocolates. What is the probability of picking a dark chocolate first and then a milk chocolate, if the chocolates aren’t replaced?
\(15\over 56\).
We use the formula, \(P( A {\text { and }}B) = P(A) × P(B | A)\).
P(Dark and Milk) \(= 38 × 57 = 1556\)
In a lottery with 10 tickets, 3 are winners. If 2 tickets are purchased without replacement, what is the probability that both are winners?
\(1\over15\).
\(P( A {\text { and }}B) = P(A) × P(B | A)\)
P(T1 and T2) = \({3\over10} × {2\over9} = {6\over90} = {1\over15}
\)
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!






