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Last updated on September 12, 2025
The derivative of tan(x), which is sec²(x), helps us understand how the tangent function changes. But what about the derivative of this derivative? Exploring these higher-order derivatives gives us more insights into the nature of functions. We will delve into the derivative of the derivative of tan(x) in detail.
The first derivative of tan x is sec²x. Differentiating sec²x gives us the second derivative of tan x. This is represented as d²/dx²(tan x) or (tan x)''.
By differentiating sec²x, we find: -
First derivative: sec²x
Second derivative: 2 sec²xtan x
Key concepts:
Tangent Function: tan(x) = sin(x)/cos(x)
Secant Function: sec(x) = 1/cos(x)
Differentiation Rules: Product and Chain Rule
The first derivative of tan x is sec²x.
To find the derivative of sec²x, use: d²/dx²(tan x) = d/dx(sec²x) = 2 sec²x tan x.
This formula applies to all x where cos(x) ≠ 0.
To prove the second derivative of tan x, we differentiate sec²x. Methods include: Using Product Rule: -
First derivative: sec²x = sec x · sec x
Use product rule: d/dx(u·v) = u'v + uv'
Differentiate: d/dx(sec x) = sec x tan x - Proof: 2 sec²x tan x
Using Chain Rule:
Differentiate sec²x as (sec x)²
Use chain rule: dy/dx = 2 sec x · d/dx(sec x)
Result: 2 sec²x tan x
Higher-order derivatives extend beyond the first and second derivatives. Each subsequent derivative provides deeper insights, similar to analyzing a car's changing speed and acceleration.
For the nth derivative of tan x, we use fⁿ(x). The second derivative, f''(x), shows the rate of change of the rate of change.
- At x = π/2, derivatives are undefined due to vertical asymptotes. - At x = 0, the first derivative of tan x is sec²(0), which is 1.
Mistakes in finding higher-order derivatives often arise from misunderstandings. Here's how to avoid them:
Calculate the second derivative of (tan x·sec²x).
Given f(x) = tan x · sec²x, find the second derivative using the product rule:
First derivative: f'(x) = sec²x · sec²x + tan x · 2 sec²x tan x
Second derivative: Differentiate each term again
Result: f''(x) = 4 sec²x tan²x + 2 sec⁴x
The process involves finding the first derivative using the product rule, then differentiating again to find the second derivative.
A slope is modeled by y = tan(x). If x = π/4, find the second derivative of the slope function.
First derivative: dy/dx = sec²(x) Second derivative:
d²y/dx² = 2 sec²(x) tan(x) At x = π/4:
sec²(π/4) = 2 - tan(π/4) = 1
Result: 2 * 2 * 1 = 4
We calculate the second derivative by differentiating sec²x and substituting x = π/4 to find the specific value.
Derive the second derivative of y = tan(x) using the chain rule.
First derivative: dy/dx = sec²(x) Second derivative: d²y/dx² = d/dx(sec²(x))
Use chain rule: d²y/dx² = 2 sec(x) · sec(x) tan(x)
Result: 2 sec²(x) tan(x)
The chain rule is applied to differentiate sec²x, resulting in the second derivative 2 sec²(x) tan(x).
Prove: d²/dx²(tan²(x)) = 4 tan(x) sec²(x) + 2 sec⁴(x).
Start with y = tan²(x)
First derivative: dy/dx = 2 tan(x) sec²(x)
Second derivative: Apply product rule to dy/dx
Result: 4 tan(x) sec²(x) + 2 sec⁴(x)
Using product and chain rules, the proof involves differentiating tan²(x) twice, resulting in the second derivative.
Solve: d²/dx²(tan x/x).
First, find the first derivative using the quotient rule:
d/dx(tan x/x) = (x sec²x - tan x) / x² Differentiate again for the second derivative:
Apply quotient rule to the first derivative.
Result: Differentiating (x sec²x - tan x) / x² involves careful application of the quotient rule.
The solution requires applying the quotient rule twice, first for the first derivative, then for the second derivative.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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