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Last updated on September 22, 2025

Derivative of Cube Root

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We use the derivative of the cube root function, which is 1/(3∛(x²)), as a measuring tool for how the cube root function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of the cube root function in detail.

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What is the Derivative of Cube Root?

We now understand the derivative of the cube root function. It is commonly represented as d/dx (∛x) or (∛x)', and its value is 1/(3∛(x²)). The function ∛x has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below:

 

Cube Root Function: The cube root of x is represented as ∛x.

 

Power Rule: Rule for differentiating functions of the form xⁿ.

 

Chain Rule: Used when differentiating functions that are composite.

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Derivative of Cube Root Formula

The derivative of ∛x can be denoted as d/dx (∛x) or (∛x)'. The formula we use to differentiate ∛x is: d/dx (∛x) = 1/(3∛(x²)) The formula applies to all x except where x=0.

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Proofs of the Derivative of Cube Root

We can derive the derivative of ∛x using proofs. To show this, we will use the power rule along with the rules of differentiation. There are several methods we use to prove this, such as:

 

  1. By First Principle
  2. Using Chain Rule
  3. Using Power Rule

 

We will now demonstrate that the differentiation of ∛x results in 1/(3∛(x²)) using the above-mentioned methods:

 

By First Principle

 

The derivative of ∛x can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.

 

To find the derivative of ∛x using the first principle, we will consider f(x) = ∛x. Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1)

 

Given that f(x) = ∛x, we write f(x + h) = ∛(x + h). Substituting these into equation (1), f'(x) = limₕ→₀ [∛(x + h) - ∛x] / h

 

We simplify using the binomial expansion for roots: = limₕ→₀ [ (x + h)^(1/3) - x^(1/3) ] / h

 

Using the limit definition, we find: f'(x) = 1/(3x^(2/3))

 

Hence, proved.

 

Using Chain Rule

 

To prove the differentiation of ∛x using the chain rule, We express the cube root as a power: ∛x = x^(1/3). Using the chain rule, the derivative of x^(1/3) is: d/dx (x^(1/3)) = (1/3)x^(-2/3) Which is equivalent to: 1/(3∛(x²))

 

Using Power Rule

 

The power rule states if y = x^n, then dy/dx = nx^(n-1). For ∛x, rewrite it as x^(1/3).

 

Applying the power rule, d/dx (x^(1/3)) = (1/3)x^(-2/3) This simplifies to: 1/(3∛(x²))

 

Thus, it is proved.

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Higher-Order Derivatives of Cube Root

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.

 

To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like ∛x.

 

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′ (x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.

 

For the nth Derivative of ∛x, we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change, continuing for higher-order derivatives.

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Special Cases:

When x is 0, the derivative is undefined because ∛x is not differentiable at x=0. When x is 1, the derivative of ∛x = 1/(3∛(1²)), which is 1/3.

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Common Mistakes and How to Avoid Them in Derivatives of Cube Root

Students frequently make mistakes when differentiating ∛x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

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Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using the chain rule. Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Misunderstanding the Domain of Cube Root

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They might not remember that ∛x is undefined at x=0. Keep in mind that you should consider the domain of the function that you differentiate. It will help you understand that the function is not continuous at such certain points.

Mistake 3

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Incorrect use of Chain Rule

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While differentiating functions such as (∛x), students misapply the chain rule. For example: Incorrect differentiation: d/dx (∛x) = 1/(3x²). Applying the chain rule, d/dx (x^(1/3)) = (1/3)x^(-2/3) To avoid this mistake, write the chain rule without errors. Always check for errors in the calculation and ensure it is properly simplified.

Mistake 4

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Not writing Constants and Coefficients

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There is a common mistake that students at times forget to multiply the constants placed before ∛x. For example, they incorrectly write d/dx (5∛x) = 1/(3∛(x²)). Students should check the constants in the terms and ensure they are multiplied properly. For example, the correct equation is d/dx (5∛x) = 5/(3∛(x²)).

Mistake 5

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Forgetting the Power Conversion

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Students often forget to convert the cube root into a power form before differentiating. This happens when they do not consider the power rule. For example: Incorrect: d/dx (∛x) = 1/3. To fix this error, students should rewrite the cube root as x^(1/3) and then apply the power rule.

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Examples Using the Derivative of Cube Root

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Problem 1

Calculate the derivative of (∛x·x²)

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Here, we have f(x) = ∛x·x².

 

Using the product rule, f'(x) = u′v + uv′ In the given equation, u = ∛x and v = x².

 

Let’s differentiate each term, u′ = d/dx (∛x) = 1/(3∛(x²)) v′ = d/dx (x²) = 2x

 

Substituting into the given equation, f'(x) = (1/(3∛(x²))). (x²) + (∛x). (2x)

 

Let’s simplify terms to get the final answer, f'(x) = x²/(3∛(x²)) + 2x∛x

 

Thus, the derivative of the specified function is x²/(3∛(x²)) + 2x∛x.

Explanation

We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

The local bakery's dough rising is modeled by the function y = ∛x where y represents the volume of dough after x hours. If x = 8 hours, measure the rate at which the dough's volume is increasing.

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We have y = ∛x (rate of dough rising)...(1)

 

Now, we will differentiate the equation (1) Take the derivative ∛x: dy/dx = 1/(3∛(x²))

 

Given x = 8 (substitute this into the derivative) dy/dx = 1/(3∛(8²)) ∛(8²) = ∛64 = 4

 

Therefore, dy/dx = 1/(3*4) = 1/12

 

Hence, we get the rate of dough rising at x=8 as 1/12.

Explanation

We find the rate at which the dough's volume increases at x=8 as 1/12, which means that at this given point, the volume of the dough rises at a rate of 1/12 cubic units per hour.

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Problem 3

Derive the second derivative of the function y = ∛x.

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The first step is to find the first derivative, dy/dx = 1/(3∛(x²))...(1)

 

Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [1/(3∛(x²))]

 

Here we use the chain rule, d²y/dx² = -1/(9x∛(x⁴))

 

Therefore, the second derivative of the function y = ∛x is -1/(9x∛(x⁴)).

Explanation

We use the step-by-step process, where we start with the first derivative. Using the chain rule, we differentiate 1/(3∛(x²)). We then substitute the identity and simplify the terms to find the final answer.

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Problem 4

Prove: d/dx ((∛x)²) = 2∛x/(3∛(x²)).

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Let’s start using the chain rule: Consider y = (∛x)² = [x^(1/3)]² = x^(2/3)

 

To differentiate, we use the power rule: dy/dx = (2/3)x^(-1/3) Since ∛x = x^(1/3), dy/dx = 2∛x/(3∛(x²))

 

Hence proved.

Explanation

In this step-by-step process, we used the power rule to differentiate the equation. Then, we replace x with its power form. As a final step, we substitute ∛x = x^(1/3) to derive the equation.

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Problem 5

Solve: d/dx (∛x/x)

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To differentiate the function, we use the quotient rule: d/dx (∛x/x) = (d/dx (∛x). x - ∛x. d/dx(x))/x²

 

We will substitute d/dx (∛x) = 1/(3∛(x²)) and d/dx (x) = 1 (1/(3∛(x²)). x - ∛x. 1) / x² = (x/(3∛(x²)) - ∛x) / x² = (x - 3∛(x³))/ (3x²∛(x²))

 

Therefore, d/dx (∛x/x) = (x - 3∛(x³))/ (3x²∛(x²))

Explanation

In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of Cube Root

1.Find the derivative of ∛x.

Using the power rule, rewrite ∛x as x^(1/3), d/dx (∛x) = 1/(3∛(x²)) (simplified)

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2.Can we use the derivative of the cube root in real life?

Yes, we can use the derivative of the cube root in real life to calculate the rate of change of any volume growth, especially in fields such as chemistry, biology, and engineering.

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3.Is it possible to take the derivative of ∛x at the point where x=0?

No, x=0 is a point where ∛x is not differentiable, so it is impossible to take the derivative at these points (since the function is not defined there).

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4.What rule is used to differentiate ∛x/x?

We use the quotient rule to differentiate ∛x/x, d/dx (∛x/x) = (x/(3∛(x²)) - ∛x) / x².

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5.Are the derivatives of ∛x and x^(1/3) the same?

Yes, they are the same. The derivative of both ∛x and x^(1/3) is 1/(3∛(x²)).

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Important Glossaries for the Derivative of Cube Root

  • Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

 

  • Cube Root Function: The cube root function is represented as ∛x, indicating the value which gives x when cubed.

 

  • Power Rule: A rule used to differentiate functions of the form xⁿ.

 

  • Chain Rule: A method for differentiating composite functions.

 

  • Undefined Point: A point where the function is not differentiable or does not exist.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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