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107 LearnersLast updated on August 5, 2025
Volume Of A Sphere Calculator
A calculator is a tool designed to perform both basic arithmetic operations and advanced calculations, such as those involving geometry. It is especially helpful for completing mathematical school projects or exploring complex mathematical concepts. In this topic, we will discuss the Volume Of A Sphere Calculator.
What is the Volume Of A Sphere Calculator
The Volume Of A Sphere Calculator is a tool designed for calculating the volume of a sphere.
A sphere is a perfectly symmetrical three-dimensional shape, where every point on its surface is equidistant from its center.
The diameter of the sphere is a straight line running through the center and joining opposite points of the sphere.
The word "sphere" comes from the Greek word "sphaira," meaning "globe."
How to Use the Volume Of A Sphere Calculator
For calculating the volume of a sphere using the calculator, follow the steps below:
Step 1: Input: Enter the radius
Step 2: Click: Calculate Volume.
By doing so, the radius you have given as input will be processed
Step 3: You will see the volume of the sphere in the output column
Tips and Tricks for Using the Volume Of A Sphere Calculator
Here are some tips to help you get the right answer using the Volume Of A Sphere Calculator.
Know the formula: The formula for the volume of a sphere is 4/3 π r3, where ‘r’ is the radius (the distance from the center to the edge of the sphere).
Use the Right Units: Make sure the radius is in the right units, like centimeters or meters.
The answer will be in cubic units (like cubic centimeters or cubic meters), so it’s important to match them.
Enter Correct Numbers: When entering the radius, make sure the numbers are accurate.
Small mistakes can lead to big differences, especially with larger numbers.
Common Mistakes and How to Avoid Them When Using the Volume Of A Sphere Calculator
Calculators mostly help us with quick solutions.
For calculating complex math questions, students must know the intricate features of a calculator.
Given below are some common mistakes and solutions to tackle these mistakes.
Mistake 1
Rounding off too soon
Rounding the decimal number too soon can lead to wrong results.
For example, if the volume is 523.60 cm³, don’t round it to 524 right away.
Finish the calculation first.
Mistake 2
Entering the wrong number as the radius
Make sure to double-check the number you are going to enter as the radius.
If you enter the radius as ‘6’ instead of ‘7’, the result will be incorrect.
Mistake 3
Mixing up 4/3 π r3 with 4 π r2
‘4 π r2’ defines the surface area, whereas ‘4/3 π r3’ defines the volume of a sphere.
Using the wrong formula will give the wrong result.
The volume of the sphere is 4/3 π r3 not 4 π r2.
Mistake 4
Relying too much on the calculator.
The calculator gives an estimate.
Real objects may not be perfect, so the answer might be slightly different.
Keep in mind that it's an approximation.
Mistake 5
Mixing up the positive and negative signs
Always check that you’ve entered the correct positive (+) or negative (–) signs.
A small mistake, like using the wrong sign for the radius, can completely change the result.
Make sure the signs are correct before finishing your calculation.
For example, if the radius is 29 cm, entering -29 cm instead of +29 cm could give you an incorrect volume.
Volume Of A Sphere Calculator Examples
Problem 1
Help Alice find the volume of a basketball if its radius is 12 cm.
We find the volume of the basketball to be approximately 7238.23 cm³.
Explanation
To find the volume, we use the formula: V = 4/3 π r3
Here, the value of ‘r’ is given as 12.
Now, we have to substitute the value of ‘r’ in the formula: V = 4/3 x 3.14 x (12)3 = 4/3 x 3.14 x 1728 = 7238.23 cm3.
Problem 2
The radius ‘r’ of a spherical balloon is 15 cm. What will be its volume?
The volume is approximately 14137.17 cm³.
Explanation
To find the volume, we use the formula:V = (4/3)πr³
Since the radius is given as 15, we can find the volume as
V = (4/3) × 3.14 × (15)³ = (4/3) × 3.14 × 3375 = 14137.17 cm³
Problem 3
Find the volume of a cube with side length ‘s’ as 4 cm and the volume of a sphere with radius 5 cm. After finding the volume of the cube and sphere, take their sum.
We will get the sum as approximately 645.33 cm³.
Explanation
For the volume of a cube, we use the formula ‘V = s³’, and for a sphere, we use ‘V = (4/3)πr³’.
Volume of cube = s³ = 4³ = 4 × 4 × 4 = 64 cm³
Volume of sphere = (4/3)πr³ = (4/3) × 3.14 × (5)³ = (4/3) × 3.14 × 125 = 523.33 cm³
The total volume = volume of cube + volume of sphere = 64 + 523.33 = 587.33 cm³.
Problem 4
The radius of a spherical metal ball is 10 cm. Find its volume.
We find the volume of the spherical metal ball to be approximately 4188.79 cm³.
Explanation
Volume = (4/3)πr³ = (4/3) × 3.14 × (10)³ = (4/3) × 3.14 × 1000 = 4188.79 cm³
Problem 5
Sarah wants to fill a spherical tank with water. If the radius of the tank is 20 cm, help Sarah find its volume.
The volume of the spherical tank is approximately 33510.32 cm³.
Explanation
Volume of spherical tank = (4/3)πr³ = (4/3) × 3.14 × (20)³ = (4/3) × 3.14 × 8000 = 33,510.32 cm³
FAQs on Using the Volume Of A Sphere Calculator
1.What is the volume of the sphere?
2.What is the value of ‘r’ that gets entered as ‘0’?
3.What will be the volume of the sphere if the radius is given as 7?
4.What units are used to represent the volume?
5.Can we use this calculator to find the volume of a hemisphere?
Important Glossary for the Volume Of Sphere Calculator
- Volume: It is the amount of space occupied by any object. It is measured either in cubic meters (m³) or cubic centimeters (cm³).
- Radius: Distance measured from the center of a sphere to its surface.For example, in V = 4/3 × 3.14 × 7³, ‘7’ is the radius.
- Pi (\(\pi\)): A mathematical constant that represents the ratio of a circle's circumference to its diameter.The value of pi is approximately equal to 3.14159.
- Cubic Units: Units used to measure volume.We use m³ and cm³ to represent the volume.
- Sphere: A three-dimensional shape that is perfectly symmetrical and round, with every point on its surface equidistant from its center.
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Seyed Ali Fathima S
About the Author
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
Fun Fact
: She has songs for each table which helps her to remember the tables
