Last updated on June 25th, 2025
Calculators are reliable tools for solving simple mathematical problems and advanced calculations like trigonometry. Whether you're cooking, tracking BMI, or planning a construction project, calculators will make your life easy. In this topic, we are going to talk about substitution method calculators.
A substitution method calculator is a tool to solve systems of linear equations by substituting one equation into another. This calculator makes solving for variables much easier and faster, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the equations: Input the system of linear equations into the given field.
Step 2: Click on solve: Click on the solve button to apply the substitution method and get the result.
Step 3: View the result: The calculator will display the result instantly.
To apply the substitution method, follow these steps:
Solve one of the equations for one variable in terms of the other.
Substitute this expression into the other equation.
Solve the resulting equation for the variable.
Substitute back to find the other variable.
For example, for the system of equations:
x + y = 5
2x − y = 3
Solve the first equation for y:
y = 5 − x
Substitute y = 5 − x into the second equation:
2x − (5 − x) = 3
Solve for x:
2x − 5 + x = 3
3x = 8
x = 8⁄3
Substitute back to find y:
y = 5 − 8⁄3 = 7⁄3
When using a substitution method calculator, there are a few tips and tricks that we can use to make it easier and avoid mistakes:
Make sure to isolate one variable completely.
Double-check your algebraic manipulations.
Use fractions or decimals consistently.
We may think that when using a calculator, mistakes will not happen. However, it is possible to make mistakes when using a calculator.
Solve the system of equations: \( x + 2y = 10 \) and \( 3x - y = 5 \).
Step 1: Solve the first equation for x:
x = 10 − 2y
Step 2: Substitute x = 10 − 2y into the second equation:
3(10 − 2y) − y = 5
Step 3: Simplify and solve for y:
30 − 6y − y = 5
30 − 7y = 5
−7y = −25
y = 25⁄7
Step 4: Substitute back to find x:
x = 10 − 2(25⁄7) = 20⁄7
By substituting the expression for x into the second equation, we solved for y, then back-substituted to find x.
Solve the system of equations: \( x - 3y = 7 \) and \( 4x + y = 9 \).
Step 1: Solve the first equation for x:
x = 3y + 7
Step 2: Substitute x = 3y + 7 into the second equation:
4(3y + 7) + y = 9
Step 3: Simplify and solve for y:
12y + 28 + y = 9
13y + 28 = 9
13y = -19
y = -19⁄13
Step 4: Substitute back to find x:
x = 3(−19⁄13) + 7 = 4⁄13
After substituting the expression for x, we solved for y and then used it to find x.
Solve the system of equations: \( 2x + 3y = 18 \) and \( x - y = 4 \).
Step 1: Solve the second equation for x:
x = y + 4
Step 2: Substitute x = y + 4 into the first equation:
2(y + 4) + 3y = 18
Step 3: Simplify and solve for y:
2y + 8 + 3y = 18
5y + 8 = 18
5y = 10
y = 2
Step 4: Substitute back to find x:
x = 2 + 4 = 6
Using the substitution method, we found y from the second equation and substituted it back to find x.
Solve the system of equations: \( 5x + 2y = 20 \) and \( x + y = 6 \).
Step 1: Solve the second equation for x:
x = 6 − y
Step 2: Substitute x = 6 − y into the first equation:
5(6 − y) + 2y = 20
Step 3: Simplify and solve for y:
30 − 5y + 2y = 20
30 − 3y = 20
−3y = −10
y = 10⁄3
Step 4: Substitute back to find x:
x = 6 − 10⁄3 = 8⁄3
By substituting the expression for x into the first equation, we solved for y and then back-substituted to find x.
Solve the system of equations: \( 3x - 4y = 12 \) and \( x + 2y = 5 \).
Step 1: Solve the second equation for x:
x = 5 − 2y
Step 2: Substitute x = 5 − 2y into the first equation:
3(5 − 2y) − 4y = 12
Step 3: Simplify and solve for y:
15 − 6y − 4y = 12
15 − 10y = 12
−10y = −3
y = 3⁄10
Step 4: Substitute back to find x:
x = 5 − 2(3⁄10) = 44⁄10 = 4.4
We solved for y using the substitution method and then back-substituted to find x.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables