Last updated on May 26th, 2025
Factors of any number are the whole numbers that can divide the number completely. Why are factors important to learn? For mathematical approaches, factors are used in organizing and bringing more efficiency to any task. In this article, let's learn how to solve factors 50 easily.
Factors of 50 are those numbers that can divide 50 perfectly. The factors of 50 are:
1,2,5,10,25, and 50.
Negative factors of 50: -1, -2, -5, -10, -25, -50
Prime factors of 50: 2,5
Prime factorization of 50: 52×2
The sum of factors of 50: 1+2+5+10+25+50 = 93
For finding factors of 50, we will be learning these below-mentioned methods:
This particular method often finds the pair of factors which, on multiplication together, produces 50. Let us find the pairs which, on multiplication, yields 50.
1×50=50
2×25=50
5×10=50
From this, we conclude that, factors of 50 are: 1,2,5,10,25, and 50.
The division method finds the numbers that evenly divides the given number 50. To find the factors of 50, we have to divide 50 by all possible natural numbers less than 50 and check.
1,2,5,10,25,50 are the only factors that the number 50 has. So to verify the factors of 50 using the division method, we just need to divide 50 by each factor.
50/1 =50
50/2 =25
50/5=10
50/10=5
50/25=2
50/50=1
Prime Factorization is the easiest process to find prime factors. It decomposes 50 into a product of its prime integers.
Prime Factors of 50: 2,5.
Prime Factorization of 50: 5×5×2 = 52×2
The number 50 is written on top and two branches are extended.
Fill in those branches with a factor pair of the number above, i.e., 50.
Continue this process until each branch ends with a prime factor (number).
The first two branches of the factor tree of 50 are 2 and 25, then proceeding to 25, we get 5 and 5. So, now the factor tree for 50 is achieved.
Factor Pairs:
Positive pair factors: (1,50), (2,25), and (5,10)
Negative pair factors: (-1,-50), (-2,-25), and (-5,-10).
Children quite often make silly mistakes while solving factors. Let us see what are the common errors to occur and how to avoid them.
A baker has 50 cupcakes and 150 cookies. He wants to divide them equally among some plates. What is the maximum number of plates he can use?
Number of cupcakes: 50
Number of cookies: 150
Factors of 50: 1,2,5,10,25,50
Factors of 150: 1,2,3,5,6,10,15,25,30,50,75,150
Common factors of 50 and 150: 1,2,5,10,25,50.
Greatest common factor of 50 and 150: 50
So, there will be 50 plates he can use.
Answer: 50 plates
To divide equally, the maximum number of plates can be found through the Greatest Common Factor. Here, we found the GCF, which is the answer.
Two trains leave a station at the same time. One leaves every 25 minutes and the other every 50 minutes. When will they leave together again?
Time-lapse of the 1st train: 25 minutes
Time-lapse of the 2nd train: 50 minutes
Prime factorization of 25: 52.
Prime factorization of 50: 52×2
LCM of 25 and 50: 52×2 = 50.
Both the trains will meet each other after 50 minutes.
Answer: 50 minutes
To find the time again when two trains will meet, we have to find the LCM of the two given time-lapses. So, did prime factorization of both 50 and 25. The LCM is the product of the highest power of each factor.
The area of a rectangle is 50 square units. If the length is 10 units, then what is the measure of its width?
Area of rectangle: 50 sq units
Factors of 50: 1,2,5,10,25,50
We know that the area of a rectangle is the product of its length and breadth.
Given, length= 10 units
There exists a factor pair of 50, which is (5,10). Hence, width is 5 units. Let’s check it through the formula for area.
So, length×width = area
⇒ 10 × width = 50
⇒ width = 50/10 = 5
Answer: 5 units
Used the concept of factor pairs for 50 and rechecked using the formula for finding area of a rectangle.
Find the smallest number that is divisible by 5,10, and 25.
Prime factorization of 5: 5×1.
Prime factorization of 10: 5×2
Prime factorization of 25: 52
LCM of 5,10 and 25: 52×2 = 50
Answer: 50 is the smallest number which is divisible by 5,10, and 25.
To find the smallest number which is divisible by 5,10,25, we need to find the LCM of these numbers.
If a number is divisible by both 2 and 25, is it divisible by 50?
Yes, any number which is divisible by 2 and 25 is also divisible by 50, since 50 = 2×25
Answer: Yes
Any number which is divisible by the factor 2 and factor 25 of 50, then it is also divisible by 50 because 50 is a product of 2 and 25.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.