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Last updated on February 24th, 2025
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use the divisibility rule for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 35.
The divisibility rule for 35 is a method by which we can find out if a number is divisible by 35 or not without using the division method. Check whether 2450 is divisible by 35 with the divisibility rule.
Step 1: Check the divisibility of the number by 5. The number should end in 0 or 5. Here, 2450 ends in 0.
Step 2: Check the divisibility of the number by 7. Use the rule for 7: double the last digit and subtract from the rest. For 245, double 0 is 0, and 245−0=245. Double 5 is 10, and 24−10=14, which is a multiple of 7.
Step 3: Since 2450 is divisible by both 5 and 7, it is divisible by 35.
Learning the divisibility rule will help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 35.
The divisibility rule of 35 helps us quickly check if a number is divisible by 35, but common mistakes like calculation errors lead to incorrect conclusions. Here are some common mistakes and solutions.
Is the number of pages in a book, 245, divisible by 35?
Yes, 245 is divisible by 35.
To check the divisibility by 35, verify divisibility by both 5 and 7.
1) For divisibility by 5, the last digit is 5, so 245 is divisible by 5.
2) For divisibility by 7, multiply the last digit by 2, 5 × 2 = 10.
3) Subtract the result from the remaining digits, 24 – 10 = 14.
4) Check if 14 is a multiple of 7, yes, 14 is a multiple of 7 (7 × 2 = 14).
Since 245 is divisible by both 5 and 7, it is divisible by 35.
A factory produces 560 units. Is this number divisible by 35?
Yes, 560 is divisible by 35.
Check divisibility by both 5 and 7.
1) For divisibility by 5, the last digit is 0, so 560 is divisible by 5.
2) For divisibility by 7, multiply the last digit by 2, 0 × 2 = 0.
3) Subtract the result from the remaining digits, 56 – 0 = 56.
4) Check if 56 is a multiple of 7, yes, 56 is a multiple of 7 (7 × 8 = 56).
Since 560 is divisible by both 5 and 7, it is divisible by 35.
Is the number 315, representing the total score in a game, divisible by 35?
Yes, 315 is divisible by 35.
Verify divisibility by both 5 and 7.
1) For divisibility by 5, the last digit is 5, so 315 is divisible by 5.
2) For divisibility by 7, multiply the last digit by 2, 5 × 2 = 10.
3) Subtract the result from the remaining digits, 31 – 10 = 21.
4) Check if 21 is a multiple of 7, yes, 21 is a multiple of 7 (7 × 3 = 21).
Since 315 is divisible by both 5 and 7, it is divisible by 35.
A shipment contains 490 items. Is this number divisible by 35?
Yes, 490 is divisible by 35.
Check divisibility by both 5 and 7.
1) For divisibility by 5, the last digit is 0, so 490 is divisible by 5.
2) For divisibility by 7, multiply the last digit by 2, 0 × 2 = 0.
3) Subtract the result from the remaining digits, 49 – 0 = 49.
4) Check if 49 is a multiple of 7, yes, 49 is a multiple of 7 (7 × 7 = 49).
Since 490 is divisible by both 5 and 7, it is divisible by 35.
Is the number 672, representing the total attendance at an event, divisible by 35?
No, 672 is not divisible by 35.
Check divisibility by both 5 and 7.
1) For divisibility by 5, the last digit is 2, so 672 is not divisible by 5.
2) Because 672 is not divisible by 5, it cannot be divisible by 35, regardless of its divisibility by 7.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.