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Last updated on July 22nd, 2025

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Derivative of ln(1+1/x)

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We use the derivative of ln(1+1/x), which is -1/(x(x+1)), to understand how the logarithmic function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of ln(1+1/x) in detail.

Derivative of ln(1+1/x) for Indian Students
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What is the Derivative of ln(1+1/x)?

We now understand the derivative of ln(1+1/x). It is commonly represented as d/dx (ln(1+1/x)) or (ln(1+1/x))', and its value is -1/(x(x+1)). The function ln(1+1/x) has a clearly defined derivative, indicating it is differentiable within its domain.

 

The key concepts are mentioned below:

 

Logarithmic Function: ln(1+1/x).

 

Chain Rule: Rule for differentiating composite functions like ln(1+1/x).

 

Reciprocal Rule: Used in simplifying the derivative.

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Derivative of ln(1+1/x) Formula

The derivative of ln(1+1/x) can be denoted as d/dx (ln(1+1/x)) or (ln(1+1/x))'. The formula we use to differentiate ln(1+1/x) is: d/dx (ln(1+1/x)) = -1/(x(x+1))

 

The formula applies to all x where x ≠ -1 or 0.

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Proofs of the Derivative of ln(1+1/x)

We can derive the derivative of ln(1+1/x) using proofs. To show this, we will use chain and reciprocal rules along with differentiation.

 

There are several methods we use to prove this, such as:

 

  1. By First Principle
  2. Using Chain Rule
  3. Using Quotient Rule

 

We will now demonstrate that the differentiation of ln(1+1/x) results in -1/(x(x+1)) using the above-mentioned methods:

 

Using Chain Rule

 

To prove the differentiation of ln(1+1/x) using the chain rule, Let u = 1+1/x Then ln(1+1/x) = ln(u) By chain rule: d/dx (ln(u)) = (1/u) * (du/dx)

 

So, we differentiate u with respect to x: du/dx = d/dx (1+1/x) = -1/x²

 

Therefore, d/dx (ln(1+1/x)) = (1/(1+1/x)) * (-1/x²) = -1/(x(x+1))

 

Using Quotient Rule

 

To prove the differentiation of ln(1+1/x) using the quotient rule, Start with the function u = 1+1/x, then differentiate using the quotient rule:

 

Let u = 1 and v = x, then u/v = 1/x.

 

d/dx (1/x) = (v * du/dx - u * dv/dx) / v² = (x * 0 - 1 * 1) / x² = -1/x²

 

Thus, d/dx (ln(1+1/x)) = 1/(1+1/x) * (-1/x²) = -1/(x(x+1))

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Higher-Order Derivatives of ln(1+1/x)

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.

 

To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like ln(1+1/x).

 

For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.

 

For the nth Derivative of ln(1+1/x), we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).

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Special Cases

When x is -1 or 0, the derivative is undefined because the function ln(1+1/x) has a vertical asymptote there. When x is 1, the derivative of ln(1+1/x) = -1/(1(1+1)) = -1/2.

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Common Mistakes and How to Avoid Them in Derivatives of ln(1+1/x)

Students frequently make mistakes when differentiating ln(1+1/x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

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Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using the chain or quotient rule. Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Forgetting the Undefined Points of ln(1+1/x)

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They might not remember that ln(1+1/x) is undefined at the points such as x = -1 or 0. Keep in mind that you should consider the domain of the function that you differentiate. It will help you understand that the function is not continuous at such certain points.

Mistake 3

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Incorrect use of Chain Rule

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While differentiating functions such as ln(1+1/x), students misapply the chain rule. For example: Incorrect differentiation: d/dx (ln(1+1/x)) = 1/(1+1/x). d/dx (ln(u)) = (1/u) * (du/dx) (where u = 1+1/x) To avoid this mistake, apply the chain rule correctly by identifying the inner function and differentiating it properly.

Mistake 4

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Not considering Reciprocal Rule

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There is a common mistake where students forget to apply the reciprocal rule when needed. Ensure to use it when simplifying derivatives of functions like ln(1+1/x).

Mistake 5

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Not Applying the Quotient Rule

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Students often forget to use the quotient rule where applicable. This happens when the derivative of a quotient is not considered properly. To fix this error, students should divide the functions into numerator and denominator parts and ensure that each part is differentiated correctly.

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Examples Using the Derivative of ln(1+1/x)

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Problem 1

Calculate the derivative of ln(1+1/x)²

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Here, we have f(x) = ln(1+1/x)².

 

Using the chain rule, f'(x) = 2 * ln(1+1/x) * d/dx (ln(1+1/x)) In the given equation, d/dx (ln(1+1/x)) = -1/(x(x+1)).

 

Substituting this into the equation, f'(x) = 2 * ln(1+1/x) * (-1/(x(x+1)))

 

Let's simplify terms to get the final answer, f'(x) = -2 ln(1+1/x)/(x(x+1))

 

Thus, the derivative of the specified function is -2 ln(1+1/x)/(x(x+1)).

Explanation

We find the derivative of the given function by using the chain rule. The first step is finding its derivative and then simplifying the terms to get the final result.

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Problem 2

AXB International School invested in a project where the logarithmic growth of resources is modeled by y = ln(1+1/x), where y represents the growth at time x. If x = 2, find the rate of growth.

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We have y = ln(1+1/x) (growth model)...(1)

 

Now, we will differentiate the equation (1) Take the derivative ln(1+1/x): dy/dx = -1/(x(x+1))

 

Given x = 2 (substitute this into the derivative)

 

dy/dx = -1/(2(2+1)) = -1/6

 

Hence, we get the rate of growth at x=2 as -1/6.

Explanation

We find the rate of growth at x=2 as -1/6, which means that at this point, the growth rate is decreasing slightly.

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Problem 3

Derive the second derivative of the function y = ln(1+1/x).

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The first step is to find the first derivative, dy/dx = -1/(x(x+1))...(1)

 

Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-1/(x(x+1))]

 

Using the quotient rule, d²y/dx² = d/dx [x(x+1)] * (-1) - (-1) * [d/dx (x(x+1))] / [x(x+1)]² = [-(x+1) - x] / [x(x+1)]³ = -2x - 1 / [x³(x+1)³]

 

Therefore, the second derivative of the function y = ln(1+1/x) is -2x - 1 / [x³(x+1)³].

Explanation

We use the step-by-step process, where we start with the first derivative. Using the quotient rule, we differentiate the function again. We then simplify the terms to find the final answer.

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Problem 4

Prove: d/dx (ln(1+1/x)³) = 3 ln(1+1/x)² * (-1/(x(x+1))).

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Let’s start using the chain rule: Consider y = ln(1+1/x)³ = [ln(1+1/x)]³

 

To differentiate, we use the chain rule: dy/dx = 3 [ln(1+1/x)]² * d/dx [ln(1+1/x)]

 

Since the derivative of ln(1+1/x) is -1/(x(x+1)), dy/dx = 3 [ln(1+1/x)]² * (-1/(x(x+1)))

 

Substituting y = ln(1+1/x)³, d/dx (ln(1+1/x)³) = 3 ln(1+1/x)² * (-1/(x(x+1)))

 

Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace ln(1+1/x) with its derivative. As a final step, we substitute y = ln(1+1/x)³ to derive the equation.

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Problem 5

Solve: d/dx (ln(1+1/x)/x)

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To differentiate the function, we use the quotient rule: d/dx (ln(1+1/x)/x) = (d/dx (ln(1+1/x)) * x - ln(1+1/x) * d/dx(x))/x²

 

We will substitute d/dx (ln(1+1/x)) = -1/(x(x+1)) and d/dx (x) = 1 = (-1/(x(x+1)) * x - ln(1+1/x) * 1) / x² = (-1/(x+1) - ln(1+1/x)) / x²

 

Therefore, d/dx (ln(1+1/x)/x) = (-1/(x+1) - ln(1+1/x)) / x²

Explanation

In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of ln(1+1/x)

1.Find the derivative of ln(1+1/x).

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2.Can we use the derivative of ln(1+1/x) in real life?

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3.Is it possible to take the derivative of ln(1+1/x) at the point where x = -1?

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4.What rule is used to differentiate ln(1+1/x)/x?

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5.Are the derivatives of ln(1+1/x) and ln(x) the same?

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6.Can we find the derivative of the ln(1+1/x) formula?

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Important Glossaries for the Derivative of ln(1+1/x)

  • Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x.

 

  • Logarithmic Function: A function that involves the logarithm, such as ln(1+1/x).

 

  • Chain Rule: A rule for differentiating composite functions by differentiating the outer and inner functions.

 

  • Quotient Rule: A rule used for finding the derivative of a quotient of two functions.

 

  • Undefined: A term describing a point where a function does not have a defined value, often leading to division by zero.
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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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