Last updated on July 31st, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 60 and 75.
The greatest common factor of 60 and 75 is 15. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors, which are always positive.
To find the GCF of 60 and 75, a few methods are described below:
Steps to find the GCF of 60 and 75 using the listing of factors:
Step 1: Firstly, list the factors of each number:
Factors of 60 = 1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60.
Factors of 75 = 1, 3, 5, 15, 25, 75.
Step 2: Now, identify the common factors of them.
Common factors of 60 and 75: 1, 3, 5, 15.
Step 3: Choose the largest factor:
The largest factor that both numbers have is 15.
The GCF of 60 and 75 is 15.
To find the GCF of 60 and 75 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number:
Prime Factors of 60: 60 = 2 x 2 x 3 x 5 = 22 x 3 x 5
Prime Factors of 75: 75 = 3 x 5 x 5 = 3 x 52
Step 2: Now, identify the common prime factors. The common prime factors are: 3 x 5
Step 3: Multiply the common prime factors 3 x 5 = 15.
The Greatest Common Factor of 60 and 75 is 15.
Find the GCF of 60 and 75 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 75 by 60 75 ÷ 60 = 1 (quotient), The remainder is calculated as 75 − (60×1) = 15
The remainder is 15, not zero, so continue the process
Step 2: Now divide the previous divisor (60) by the previous remainder (15)
Divide 60 by 15 60 ÷ 15 = 4 (quotient), remainder = 60 − (15×4) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 60 and 75 is 15.
Finding GCF of 60 and 75 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 60 tulips and 75 roses. He wants to plant them in rows with the same number of flowers in each row, using the largest possible number of flowers per row. How many flowers will be in each row?
We should find the GCF of 60 and 75 GCF of 60 and 75
3 x 5 = 15.
There are 15 equal rows
60 ÷ 15 = 4
75 ÷ 15 = 5
There will be 15 rows, and each row gets 4 tulips and 5 roses.
As the GCF of 60 and 75 is 15, the gardener can make 15 rows.
Now divide 60 and 75 by 15.
Each row gets 4 tulips and 5 roses.
A school has 60 desks and 75 chairs. They want to arrange them in rows with the same number of items in each row, using the largest possible number of items per row. How many items will be in each row?
GCF of 60 and 75 3 x 5 = 15. So each row will have 15 items.
There are 60 desks and 75 chairs.
To find the total number of items in each row, we should find the GCF of 60 and 75.
There will be 15 items in each row.
A tailor has 60 meters of green fabric and 75 meters of yellow fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 60 and 75
The GCF of 60 and 75
3 x 5 = 15.
The fabric is 15 meters long.
For calculating the longest length of the fabric first, we need to calculate the GCF of 60 and 75, which is 15. The length of each piece of the fabric will be 15 meters.
A carpenter has two wooden planks, one 60 cm long and the other 75 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 60 and 75
3 x 5 = 15.
The longest length of each piece is 15 cm.
To find the longest length of each piece of the two wooden planks, 60 cm and 75 cm, respectively.
We have to find the GCF of 60 and 75, which is 15 cm.
The longest length of each piece is 15 cm.
If the GCF of 60 and ‘b’ is 15, and the LCM is 300. Find ‘b’.
The value of ‘b’ is 75.
GCF x LCM = product of the numbers
15 × 300 = 60 × b
4500 = 60b
b = 4500 ÷ 60 = 75
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.