Last updated on July 16th, 2025
We use the derivative of cos²(x), which helps us understand how this function changes with a slight change in x. Derivatives are essential in various fields, such as physics and economics, to calculate rates of change. We will now discuss the derivative of cos²(x) in detail.
We now understand the derivative of cos²(x). It is commonly represented as d/dx (cos²(x)) or (cos²(x))', and its value is -2cos(x)sin(x) or -sin(2x). The function cos²(x) is differentiable within its domain.
The key concepts are mentioned below:
Cosine Function: (cos(x)).
Chain Rule: Rule for differentiating composite functions like cos²(x).
Sine Function: sin(x) = opposite/hypotenuse in a right triangle.
The derivative of cos²(x) can be denoted as d/dx (cos²(x)) or (cos²(x))'. The formula we use to differentiate cos²(x) is: d/dx (cos²(x)) = -2cos(x)sin(x) or (cos²(x))' = -sin(2x)
This formula applies to all x where the cosine and sine functions are defined.
We can derive the derivative of cos²(x) using proofs. To show this, we will use trigonometric identities along with the rules of differentiation.
There are several methods we use to prove this, such as:
By First Principle Using Chain Rule Using Product Rule We will now demonstrate that the differentiation of cos²(x) results in -sin(2x) using the above-mentioned methods: By First Principle The derivative of cos²(x) can be proved using the First Principle, which expresses the derivative as the limit of the difference quotient.
To find the derivative of cos²(x) using the first principle, we will consider f(x) = cos²(x).
Its derivative can be expressed as the following limit. f'(x) = limₕ→₀ [f(x + h) - f(x)] / h … (1) Given that f(x) = cos²(x), we write f(x + h) = cos²(x + h).
Substituting these into equation (1), f'(x) = limₕ→₀ [cos²(x + h) - cos²(x)] / h = limₕ→₀ [(cos(x + h) - cos(x))(cos(x + h) + cos(x))] / h = limₕ→₀ [-sin(x + h + x)sin(h)] / h
Using limit formulas, limₕ→₀ (sin(h)/h) = 1. f'(x) = -sin(2x)
Hence, proved.
Using Chain Rule To prove the differentiation of cos²(x) using the chain rule, We use the formula: y = cos²(x) Let u = cos(x), then y = u² dy/dx = d/du(y) · du/dx = 2u · (-sin(x)) = -2cos(x)sin(x) Since -2cos(x)sin(x) = -sin(2x), the derivative is -sin(2x).
Using Product Rule We will now prove the derivative of cos²(x) using the product rule. The step-by-step process is demonstrated below:
Here, we use the formula, y = cos²(x) = (cos(x))(cos(x)) Given that, u = cos(x) and v = cos(x)
Using the product rule formula: d/dx [u·v] = u'·v + u·v' u' = d/dx (cos(x)) = -sin(x) v' = d/dx (cos(x)) = -sin(x)
d/dx (cos²(x)) = (-sin(x))(cos(x)) + (cos(x))(-sin(x)) = -2cos(x)sin(x)
Thus, the derivative is -sin(2x).
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like cos²(x).
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues.
For the nth Derivative of cos²(x), we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is π/2, the derivative is 0 because cos²(x) = 0 at that point, and the derivative is defined there.
When x is 0, the derivative of cos²(x) = -sin(2(0)), which is 0.
Students frequently make mistakes when differentiating cos²(x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (cos²(x)·sin(x))
Here, we have f(x) = cos²(x)·sin(x). Using the product rule, f'(x) = u′v + uv′ In the given equation, u = cos²(x) and v = sin(x).
Let’s differentiate each term, u′ = d/dx (cos²(x)) = -sin(2x) v′ = d/dx (sin(x)) = cos(x)
Substituting into the given equation, f'(x) = (-sin(2x))(sin(x)) + (cos²(x))(cos(x))
Let’s simplify terms to get the final answer, f'(x) = -sin(2x)sin(x) + cos³(x)
Thus, the derivative of the specified function is -sin(2x)sin(x) + cos³(x).
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company is designing a rotating sign that traces a path modeled by y = cos²(x). If x represents the angle in radians, calculate the rate of change of the path at x = π/3.
We have y = cos²(x) (path of the sign)...(1)
Now, we will differentiate the equation (1) Take the derivative cos²(x): dy/dx = -sin(2x)
Given x = π/3 (substitute this into the derivative),
dy/dx = -sin(2(π/3)) = -sin(2π/3) = -√3/2
Hence, the rate of change of the path at x = π/3 is -√3/2.
We calculate the rate of change of the path at x = π/3 as -√3/2, which indicates the direction and magnitude of change in the path at that specific angle.
Derive the second derivative of the function y = cos²(x).
The first step is to find the first derivative, dy/dx = -sin(2x)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [-sin(2x)]
Here we use the chain rule, d²y/dx² = -2cos(2x)
Therefore, the second derivative of the function y = cos²(x) is -2cos(2x).
We use the step-by-step process, where we start with the first derivative. Using the chain rule, we differentiate -sin(2x). We then simplify the terms to find the final answer.
Prove: d/dx (cos(2x)) = -2sin(2x).
Let’s start using the chain rule: Consider y = cos(2x)
To differentiate, we use the chain rule: dy/dx = -sin(2x) · d/dx (2x) = -2sin(2x)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. We replaced the inner function with its derivative to derive the equation.
Solve: d/dx (cos²(x)/x)
To differentiate the function, we use the quotient rule: d/dx (cos²(x)/x) = (d/dx (cos²(x))·x - cos²(x)·d/dx(x))/x²
We will substitute d/dx (cos²(x)) = -sin(2x) and d/dx(x) = 1 = (-sin(2x)·x - cos²(x)·1) / x² = (-xsin(2x) - cos²(x)) / x²
Therefore, d/dx (cos²(x)/x) = (-xsin(2x) - cos²(x)) / x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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