Last updated on August 26th, 2025
Compound inequalities are two inequalities that are joined by the words "and" or "or". Each part is solved like a regular inequality, but the final answer depends on whether both conditions must be true (“and”) or just one needs to be true (“or”).
A compound inequality merges two separate inequalities using the words “and” or “or”. Conjunction means both must hold simultaneously, like 1 < x < 3, while disjunction uses “or,” requiring at least one condition to be true.
1. Solve Each Inequality Separately
For example, in the compound inequality x > 1 and x ≤ 4, treat each part as its own inequality and solve for x.
2. Plot Each Inequality on the Same Number Line
After plotting, use open dots for strict inequalities (< or >) and closed dots for inclusive ones (≤ or ≥). Shade to the left for “<” or “≤” and to the right for “>” or “≥”.
3. Combine the Shaded Regions
1. Recognize “AND” vs “OR”:
2. Break the compound inequality into two separate inequalities. Solve each part as usual:
We need to isolate x while solving an inequality. However, when multiplying and dividing both sides by a negative number, we should flip the inequality sign.
3. Combine solutions:
4. (Optional) Graph on a number line to verify the solution.
Compound inequalities are used in our daily life. It helps us in budgeting and monitoring speed limits and temperature ranges. We will be learning in the field of architecture, nature, biology, art, and design also.
Students might make mistakes while dealing with compound inequalities. Some of these mistakes are common and can be avoided. Take a look at these common mistakes so that you can avoid them in the future.
Solve −3 ≤ 2x −1 < 5
−1 ≤ x < 3
Start with the compound inequality:
−3 ≤ 2x −1 < 5
Step 1: Add 1 to all three parts to isolate the term with x:
−2 ≤ 2x < 6
Step 2: Divide all parts by 2:
−1 ≤ x < 3
Solve 4x − 7 > 9 or 2x + 1 ≤ −3
x > 4 or x ≤ −2
We’re given: 4x − 7 > 9 or 2x + 1 ≤ − 3
Solve each part separately:
1. 4x − 7 > 9
Add 7: 4x > 16
Divide by 4: x > 4
2. 2x + 1 ≤ −3
Subtract 1: 2x ≤ −4
Divide by 2:
x ≤ −2
Combine using OR:
Final Answer: x > 4 or x ≤ −2
If 7 is less than 2x + 1 which is also at most 15, what can x be?
3 < x ≤7
We’re given: 7 < 2x +1 ≤ 15
Step 1: Subtract 1 from all parts
6 < 2x ≤ 14
Step 2: Divide all parts by 2
3 < x ≤7
Solve −2 ≤ 4 −3x < 10
−2 <x ≤ 2
We’re solving the compound inequality: −2 ≤ 4 −3x < 10
Step 1: Subtract 4 from all parts
−6 ≤ −3x < 6
Step 2: Divide all parts by -3, and flip the inequality signs
2 ≥ x > −2
Rewriting in standard form:
−2 <x ≤ 2
Solve 6x − 3 < 9 and 2x + 7 ≥ 3
−2 ≤ x < 2
We’re solving a compound inequality using "and": 6x − 3 < 9 and 2x + 7 ≥ 3
Solve each part:
1. 6x − 3 < 9
Add 3: 6x < 12
Divide by 6: x < 2
2. 2x + 7 ≥ 3
Subtract 7: 2x ≥ −4
Divide by 2: x ≥ −2
Combine using AND (overlap):
Final answer: −2 ≤ x < 2