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Last updated on July 10th, 2025

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Factor Theorem

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The factor theorem, a fundamental concept in algebra, determines if a binomial is a factor of a polynomial. It is also used to find polynomial roots and solve higher-degree polynomial equations, with applications in single processing and optimization

Factor Theorem for UK Students
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What is the Factor Theorem?

The factor theorem is particularly beneficial in polynomial divisions, graphing functions, and factoring polynomials completely.
The theorem suggests; if f(a) =0, for a polynomial f(x), then (x-a) is a factor of f(x).

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Difference Between Factor Theorem and Remainder Theorem

The remainder theorem helps in finding remainders without going through the whole process of long division. It states that when a linear divisor (x-a) divides a polynomial f(x), the remainder is the value of the polynomial at x = a, i.e., f(a). The factor theorem is a special case of the remainder theorem

Factor Theorem

Remainder Theorem

Used to check if a given binomial is a factor of the given polynomial or not.

Used to find the remainder for polynomials being divided by binomials

Focuses on when f(a)=0

Focuses on calculating f(a)

Confirms whether (x-a) is a factor or not

Gives the exact remainder

Factor polynomials and find exact roots

Finds remainders without having to complete the entire division process

Factor theorem is applied when the remainder is 0

Works even when the remainder is not zero

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Factor Theorem Statement

The factor theorem states:
For a polynomial f(x), if f(a) = 0, then (x - a) is a factor of f(x). 
Conversely, if (x - a) is a factor of f(x), then f(a) = 0
For instance, let f(x) = x3 -6x2 + 11x - 6.
  Check f(1),
 f(1) = 13 -  6(1)2 + 11(1) - 6 = 0
 

So, by factor theorem, (x-1) is a factor of f(x)

 

Proof of Factor Theorem: 
According to division algorithm for polynomials:
f(x) = (x - a)  q(x) + r
Where:
f(x) is the original polynomial
(x - a) is the divisor
q(x) is the quotient polynomial
r is the remainder   

Substituting x=a
f(a)= (a - a)   q(a) + r =  r           
So, f(a) = r
If f(a) = 0, then r = 0
f(x) = (x-a)    q(x)
So,  
(x-a) is a factor of f(x)
The factor theorem is a result of the remainder theorem.


 

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What is zero of a Polynomial?

A value that, when substituted with the variable, makes the whole polynomial value zero is the zero of that polynomial. Zeroes of a polynomial are visual representations of the point on a graph where a curve intersects with the x-axis. In other words; If f(a)=0, a is a zero of polynomial f(x).

 

For example: Let’s take f(x) = x2 - 4
To find the zero, set f(x) = 0
                                        x2- 4 = 0
                                                              (x - 2) (x + 2) = 0
So, the zeroes are x= 2 and x= -2

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What is the Formula for Factor Theorem?

According to the theorem, polynomial f(x) has degree  1. This means that the highest power of variable x is 1. (x - a) is a factor of f(x) if f(a)=0. Here’ a’ is a real number.
So, the formula for factor theorem is:  f(x)=(x-a)q(x)

 

  • (x-a) is a factor of f(x)
  • f(a)=0
  • q(x) represents the quotient polynomial, i.e., the result of dividing the original polynomial by the factor.
  • When f(x) is divided by (x-a) the remainder is zero
  • a is the solution to f(x) =0 and also the zero function of f(x).
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How to Use Factor Theorem?

As established above, the factor theorem is generally used while solving polynomial equations.

Let’s see how to apply it, using an example:

Question: Use the factor theorem to check whether (x-3) is a factor of 
                                       f(x) - x3 -6x2 = 11x - 6
According to the theorem:
If f(3)=0, then, (x-3) is a factor of f(x)
         f(3) = (3)3 - 6(3)2 + 11(3) - 6 
                  = 27- 54 + 33 - 6
                      = 0
Since f(3) = 0
(x-3) is a factor of the polynomial f(x) - x3 -6x2=11x-6
 

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How to Use the Factor Theorem to Factor a Cubic Polynomial?

To factorize a cubic polynomial:
Find zero using the trail- and-error method. Then, using synthetic division method, divide the given polynomial f(x) by the given binomial (x-a), 

After division, if the remainder is not zero, then (x-a) is not a factor of f(x). 

If the remainder is zero, use the division algorithm and write the given polynomial as a product of (x-a) and quadratic quotient q(x); f(x) = (x-a)q(y) + r

If possible, factor the quadratic quotient further

Then, represent the polynomial in factored form.

Let’s factor f(x) = x3 - 6x2 + 11x - 6 using the aforementioned procedure 

The first step is to find a zero using the hit and try method and dividing the given polynomial
Try x=1,
            f(1) = 13 - 6(1)2 + 11(1) - 6 = 1 - 6 + 11 - 6 = 0    
So, x = 1 is a zero, a (x-1) is a factor.

Now, we will use synthetic division to divide f(x) by (x-1)
            
                  | 1   -6    11   -6
              1  |      1   -5     6   | 0
                  ---------------------
                    1   -5     6    0
 
The quotient is: x2 - 5x = 6 

Since the remainder is zero, 

                 X2 - 5x + 6 = (x-2) (x-3)
The polynomial, in its final factored form, is 
                                       f(x) = (x-1)(x-2)(x-3)

Thus, the zeroes of given polynomial x3 - 6x2 + 11x - 6 are 1, 2, and 3
 

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Common Mistakes and How to Avoid Them in Factor Theorem

The factor theorem is essential in finding zeroes of polynomials. Here are some common mistakes students make while using the theorem and ways to avoid them.

Mistake 1

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Incorrect substitution in f(a)

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Plugging in the wrong value causes calculation errors when evaluating f(a). Be careful with signs and arithmetic, and double-check the values.
For example: Let f(x) = x2 − 4x +3 
Let’s check if x = 1 is a zero
f(1) = 12 − 4(1) + 3 = 1 − 4 + 3 = 2. This is incorrect substitution.
The correct calculation of values is: f(1) = 1− 4 + 3 = 0

Mistake 2

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Misunderstanding the statement

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People believe f(a) = 0 means that x = a is a factor but x - a is not necessarily the solution. This is wrong. According to the factor theorem, If f(a) = 0, then x - a is a factor and a is a root.

Mistake 3

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Forgetting synthetic division after finding a factor

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The remaining quotient can be factored further so continue dividing the polynomial.

Mistake 4

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 Assuming zeroes without verification

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Always confirm a zero by substituting the values in f(x), guesswork will give false solutions.

Mistake 5

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Confusing factor theorem with remainder theorem.

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The factor theorem is only used when the remainder is zero.

Always make sure to verify, divide, and factor the equation completely.

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Real-life Applications of Factor Theorem

The factor theorem is a mathematical concept helpful in practical fields like engineering, physics, computer graphics, economics, business marketing, robotics etc. Let’s discuss how:

 

  • Analyzing modelling systems in engineering: Engineers use polynomials for analyzing and modelling systems. The factor theorem helps analyze stability or resonance points.

 

  • Solving displacement points in physical systems: The factor theorem contributes in solving for critical values like time of flight, maximum height or zero- displacement points in physical systems like projectile motion, waveforms, or oscillations.

 

  • Simplifying and computing transformations in computer graphics: Factorization helps simplify curve behavior for curves like Bézier curves, used to draw animations or 3D models; it also helps simplify curve behavior, find intersections and compute transformations efficiently. 

 

  • Finding break-even points in economic and business modeling: Analysts use factor theorems to find break-even points and optimize production. Polynomial functions model profit, cost, and revenue functions.

 

  • Breaking down complex polynomials in robotics and game development:The theorem breaks down complex polynomial-based decisions or movements into manageable parts. Robots and engines use these polynomials to calculate motion paths or AI decision models.
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Solved Examples of Factor Theorem

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Problem 1

Given: f(x)=x3−4x2+x+6 Show that x = −1 is a root and (x+1) is a factor.

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(x+1) is a factor of f(x)
 

Explanation

f(x) = x3 - 4x2 + x + 6
Check f(-1):
f(-1) = (-1)3 - 4(-1)2 + (-1) + 6 = -1 - 4–1 + 6 = 0
Since f(-1) = 0, by factor theorem, (x+1) is a factor of f(x)
 

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Problem 2

Given: f(x) = x3 + 2x2 - 5x - 6 Show that x = -3 is a root and (x + 3) is a factor.

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f(−3) = 0, so (x + 3) is a factor of f(x)
 

Explanation

f(x) = x3 + 2x2 − 5x − 6 
Check f(−3):
f(−3) = (−3)2 + 2(−3)2 − 5(−3) − 6
= −27 + 18 + 15 − 6
= 0
f(−3) = 0, so (x + 3) is a factor of f(x)
 

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Problem 3

Given, f(x) = 2x3 + 3x2 − 2x − 3 Prove that x =−1 is a root, and (x+1) is a factor.

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f(−1) = 0 ⇒ (x + 1) is a factor of f(x)

Explanation

f(x) = 2x3 + 3x2 − 2x − 3
Check f(−1)
f(−1) = 2(−1)3 + 3(−1)2 − 2(−1) − 3 = −2 + 3 + 2 − 3 = 0 
f(−1) = 0 ⇒ (x + 1) is a factor of f(x)
 

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Problem 4

Given: f(x) = x3 − 3x2 − 4x + 12 Show that x = 2 is a root and (x − 2) is a factor.

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 f(2) = 0

Explanation

f(x) = x3 − 3x2 − 4x + 12
Check f(2):
f(2) = 23 − 3(2)2 − 4(2) + 12
= 8 − 12 − 8 + 12
= 0
 

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Problem 5

Given, f(x) = x3 + x2 − 4x − 4. Show that x = −2 is a root and (x + 2) is a factor.

Ray, the Boy Character from BrightChamps Saying "Let’s Begin"

f(−2) = 0, (x = 2) is a factor of f(x)
 

Explanation

f(x) = x3 + x2 − 4x − 4
Check f(-2) 
 f(-2) = -23 + (-2)2 − 4(-2) − 4
= −8 + 4 + 8 − 4
= 0
 Since f(−2) = 0, (x = 2) is a factor of f(x)
 

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FAQs on Factor theorem

1.What is a polynomial?

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2.What is the factor theorem used for?

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3. How to find the factors of a polynomial?

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4.When is the factor theorem used?

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5.What are the other methods for finding roots of a polynomial?

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6.How does learning Algebra help students in United Kingdom make better decisions in daily life?

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7.How can cultural or local activities in United Kingdom support learning Algebra topics such as Factor Theorem?

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8.How do technology and digital tools in United Kingdom support learning Algebra and Factor Theorem?

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9.Does learning Algebra support future career opportunities for students in United Kingdom?

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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