Last updated on August 11th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 15 and 30.
The greatest common factor of 15 and 30 is 15. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 15 and 30, a few methods are described below - Listing Factors Prime Factorization Long Division Method / by Euclidean Algorithm
Steps to find the GCF of 15 and 30 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 15 = 1, 3, 5, 15. Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Step 2: Now, identify the common factors of them Common factors of 15 and 30: 1, 3, 5, 15.
Step 3: Choose the largest factor The largest factor that both numbers have is 15. The GCF of 15 and 30 is 15.
To find the GCF of 15 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 15: 15 = 3 x 5 Prime Factors of 30: 30 = 2 x 3 x 5
Step 2: Now, identify the common prime factors The common prime factors are: 3 x 5 = 3 x 5
Step 3: Multiply the common prime factors 3 x 5 = 15. The Greatest Common Factor of 15 and 30 is 15.
Find the GCF of 15 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 30 by 15 30 ÷ 15 = 2 (quotient), The remainder is calculated as 30 − (15×2) = 0
The remainder is zero, so the divisor will become the GCF. The GCF of 15 and 30 is 15.
Finding the GCF of 15 and 30 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 15 loaves of bread and 30 containers of milk. She wants to arrange them into the largest number of equal sets. How many items will be in each set?
We should find the GCF of 15 and 30 GCF of 15 and 30 3 x 5 = 15. There are 15 equal groups 15 ÷ 15 = 1 30 ÷ 15 = 2 There will be 15 groups, and each group gets 1 loaf of bread and 2 containers of milk.
As the GCF of 15 and 30 is 15, the chef can make 15 groups. Now divide 15 and 30 by 15. Each group gets 1 loaf of bread and 2 containers of milk.
A school has 15 red flags and 30 blue flags. They want to arrange them in rows with the same number of flags in each row, using the largest possible number of flags per row. How many flags will be in each row?
GCF of 15 and 30 3 x 5 = 15. So each row will have 15 flags.
There are 15 red and 30 blue flags. To find the total number of flags in each row, we should find the GCF of 15 and 30. There will be 15 flags in each row.
A tailor has 15 meters of silk ribbon and 30 meters of cotton ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating longest equal length, we have to calculate the GCF of 15 and 30 The GCF of 15 and 30 3 x 5 = 15. The ribbon is 15 meters long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 15 and 30, which is 15. The length of each piece of the ribbon will be 15 meters.
A carpenter has two wooden planks, one 15 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 15 and 30 3 x 5 = 15. The longest length of each piece is 15 cm.
To find the longest length of each piece of the two wooden planks, 15 cm and 30 cm, respectively. We have to find the GCF of 15 and 30, which is 15 cm. The longest length of each piece is 15 cm.
If the GCF of 15 and ‘a’ is 5, and the LCM is 45. Find ‘a’.
The value of ‘a’ is 9.
GCF x LCM = product of the numbers 5 × 45 = 15 × a 225 = 15a a = 225 ÷ 15 = 15
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.