Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 1815, how they are used in real life, and the tips to learn them quickly.
The numbers that divide 1815 evenly are known as factors of 1815.
A factor of 1815 is a number that divides the number without remainder.
The factors of 1815 are 1, 3, 5, 11, 15, 33, 55, 121, 165, 363, 605, and 181
Negative factors of 1815: -1, -3, -5, -11, -15, -33, -55, -121, -165, -363, -605, and -1815.
Prime factors of 1815: 3, 5, and 11.
Prime factorization of 1815: 3 × 5 × 11 × 11.
The sum of factors of 1815: 1 + 3 + 5 + 11 + 15 + 33 + 55 + 121 + 165 + 363 + 605 + 1815 = 3192
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 1815. Identifying the numbers which are multiplied to get the number 1815 is the multiplication method.
Step 1: Multiply 1815 by 1, 1815 × 1 = 1815.
Step 2: Check for other numbers that give 1815 after multiplying
3 × 605 = 1815
5 × 363 = 1815
11 × 165 = 1815
15 × 121 = 1815
Therefore, the positive factor pairs of 1815 are: (1, 1815), (3, 605), (5, 363), (11, 165), (15, 121).
All these factor pairs result in 1815.
For every positive factor, there is a negative factor.
Dividing the given numbers with the whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following a simple division method -
Step 1: Divide 1815 by 1, 1815 ÷ 1 = 1815.
Step 2: Continue dividing 1815 by the numbers until the remainder becomes 0.
1815 ÷ 1 = 1815
1815 ÷ 3 = 605
1815 ÷ 5 = 363
1815 ÷ 11 = 165
1815 ÷ 15 = 121
Therefore, the factors of 1815 are: 1, 3, 5, 11, 15, 33, 55, 121, 165, 363, 605, 1815.
The factors can be found by dividing them with a prime number. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 1815 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
1815 ÷ 3 = 605
605 ÷ 5 = 121
121 ÷ 11 = 11
11 ÷ 11 = 1
The prime factors of 1815 are 3, 5, and 11.
The prime factorization of 1815 is: 3 × 5 × 11 × 11.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows -
Step 1: Firstly, 1815 is divided by 3 to get 605.
Step 2: Now divide 605 by 5 to get 121.
Step 3: Then divide 121 by 11 to get 11.
Step 4: Divide 11 by 11 to get 1.
Here, 11 is the smallest prime number, that cannot be divided anymore.
So, the prime factorization of 1815 is: 3 × 5 × 11 × 11.
Factor Pairs Two numbers that are multiplied to give a specific number are called factor pairs.
Both positive and negative factors constitute factor pairs.
Positive factor pairs of 1815: (1, 1815), (3, 605), (5, 363), (11, 165), and (15, 121).
Negative factor pairs of 1815: (-1, -1815), (-3, -605), (-5, -363), (-11, -165), and (-15, -121).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
A group of 11 people is planning to split a total of 1815 candies equally. How many candies will each person get?
Each person will get 165 candies.
To divide the candies equally, we need to divide the total candies with the number of people.
1815/11 = 165
A hall is rectangular, the width of the hall is 15 meters, and the total area is 1815 square meters. Find the length?
121 meters.
To find the length of the hall, we use the formula,
Area = length × width
1815 = 15 × length
To find the value of length, we need to shift 15 to the left side.
1815/15 = length
Length = 121.
There are 33 boxes and 1815 items. How many items will be in each box?
Each box will have 55 items.
To find the items in each box, divide the total items with the boxes.
1815/33 = 55
In a class, there are 1815 students, and 5 sections. How many students are there in each section?
There are 363 students in each section.
Dividing the students with the total sections, we will get the number of students in each section.
1815/5 = 363
1815 books need to be arranged in 3 shelves. How many books will go on each shelf?
Each of the shelves has 605 books.
Divide total books with shelves.
1815/3 = 605
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.