Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 1435, how they are used in real life, and the tips to learn them quickly.
The numbers that divide 1435 evenly are known as factors of 1435.
A factor of 1435 is a number that divides the number without remainder.
The factors of 1435 are 1, 5, 7, 11, 13, 35, 55, 65, 77, 91, 143, 715, and 1435.
Negative factors of 1435: -1, -5, -7, -11, -13, -35, -55, -65, -77, -91, -143, -715, and -1435.
Prime factors of 1435: 5, 7, 11, and 13.
Prime factorization of 1435: 5 × 7 × 11 × 13.
The sum of factors of 1435: 1 + 5 + 7 + 11 + 13 + 35 + 55 + 65 + 77 + 91 + 143 + 715 + 1435 = 2653
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 1435. Identifying the numbers which are multiplied to get the number 1435 is the multiplication method.
Step 1: Multiply 1435 by 1, 1435 × 1 = 1435.
Step 2: Check for other numbers that give 1435 after multiplying
5 × 287 = 1435
7 × 205 = 1435
11 × 130 = 1435
13 × 110 = 1435
Therefore, the positive factor pairs of 1435 are: (1, 1435), (5, 287), (7, 205), (11, 130), (13, 110).
All these factor pairs result in 1435.
For every positive factor, there is a negative factor.
Dividing the given numbers with the whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following a simple division method -
Step 1: Divide 1435 by 1, 1435 ÷ 1 = 1435.
Step 2: Continue dividing 1435 by the numbers until the remainder becomes 0.
1435 ÷ 1 = 1435
1435 ÷ 5 = 287
1435 ÷ 7 = 205
1435 ÷ 11 = 130
1435 ÷ 13 = 110
Therefore, the factors of 1435 are: 1, 5, 7, 11, 13, 35, 55, 65, 77, 91, 143, 715, and 1435.
The factors can be found by dividing it with prime numbers. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 1435 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
1435 ÷ 5 = 287
287 ÷ 7 = 41
41 ÷ 41 = 1
The prime factors of 1435 are 5, 7, 11, and 13.
The prime factorization of 1435 is: 5 × 7 × 11 × 13.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows -
Step 1: Firstly, 1435 is divided by 5 to get 287.
Step 2: Now divide 287 by 7 to get 41.
Step 3: Then divide 41 by 41 to get 1.
So, the prime factorization of 1435 is: 5 × 7 × 11 × 13.
Factor Pairs Two numbers that are multiplied to give a specific number are called factor pairs.
Both positive and negative factors constitute factor pairs.
Positive factor pairs of 1435: (1, 1435), (5, 287), (7, 205), (11, 130), and (13, 110).
Negative factor pairs of 1435: (-1, -1435), (-5, -287), (-7, -205), (-11, -130), and (-13, -110).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 13 students and 1435 candies. How will they divide it equally?
They will get 110 candies each.
To divide the candies equally, we need to divide the total candies with the number of students.
1435/13 = 110
A rectangular field has a length of 11 meters, and the total area is 1435 square meters. Find the width.
130 meters.
To find the width of the field, we use the formula,
Area = length × width
1435 = 11 × width
To find the value of width, we need to shift 11 to the left side.
1435/11 = width
Width = 130.
There are 35 boxes and 1435 apples. How many apples will be in each box?
Each box will have 41 apples.
To find the apples in each box, divide the total apples with the boxes.
1435/35 = 41
In a school, there are 1435 students, and 5 classes. How many students are there in each class?
There are 287 students in each class.
Dividing the students with the total classes, we will get the number of students in each class.
1435/5 = 287
1435 books need to be arranged in 11 shelves. How many books will go on each shelf?
Each of the shelves has 130 books.
Divide total books with shelves.
1435/11 = 130
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.