Last updated on July 9th, 2025
Exponential growth and decay describe how quantities increase or decrease quickly over time, such as the growth of a tree (increase) or decline in the stock market (decrease). The increase is represented by exponential growth and the decrease by exponential decay.
Physical quantities experience changes over time, and they can be studied using exponential growth and decay. When the change is not constant but exponential, it is termed exponential growth or exponential decay. Exponential growth tells us how something increases with time, and exponential decay shows how something reduces with time. It is expressed in the form f(x) = abx, where
a = initial quantity
b = growth factor
and x is the time over which the growth and decay happen.
If the value of b >1, it represents exponential growth, and if b< 1, it represents exponential decay.
Now, let’s learn how to calculate exponential growth and decay. The formulas to calculate them are given below:
Exponential Growth |
Exponential Decay |
f(x) = abx |
f(x) = ab-x |
f(x) = a(1 + r)t |
f(x) = a(1 - r)t |
P = P0ekt |
P = P0e-kt |
Where a or P0 represents the initial quantity of the substance, r represents the rate of growth, and t represents the time steps.
Exponential growth and decay have many real-life applications. They are used in various fields as mentioned below:
Exponential growth and decay are the basis of many fields, from population dynamics to radioactive decay analysis. In this topic, we learned more about exponential growth and decay.
A city has a population of 50,000 people, and it grows at a rate of 3% per year. Find the population after 5 years.
After 5 years, the population is approximately 58,090
To calculate the population growth, we use the formula P = P0ekt
Where, P0 = 50,000
k = 3% = 0.03
t = 5 years
So, P(5) = 50,000 × e(0.03 × 5)
= 50,000 × e0.15
= 50,000 × 1.1618 = 58,090
An investment of $1,000 is placed in a bank that offers a 5% annual interest rate, compounded continuously. Find the amount after 10 years.
The investment after 10 years is equal to $1648.72
For continuous compounding, the amount after t years is calculated using;
A = P × ekt
Here, P = $1000
k = 5% = 0.05
t = 10 years
e = 2.718
So, A = 1000 × e0.05 × 10
As, e0.5 = 1.64872
So, A = 1000 × 1.64872 = 1648.72
A bacterial culture starts at 100 mg and grows by 7% per hour. Find the amount after 8 hours.
The amount increase in bacterial culture after 8 hours is 171.51 mg
The exponential growth can be calculated by using the following formula;
A = P0(1 + r)t
Here, P0 = 100 mg
r = 7% = 0.07
t = 8 hours
So, A = 100 (1 + 0.07)8
= 100 × 1.078
= 171.8 mg
A radioactive substance has 200 grams and decays at a rate of 5% per year. Find the remaining amount after 6 years.
The radioactive decay after 6 years is 143.26 grams
The exponential decay can be calculated by
A = P0(1-r)t
Here, P0 = 200 grams
r = 5% = 0.05
t = 6 years
So, A = 200 (1 - 0.05)6
= 200(0.95)6
= 143.26 grams
A social media account has 500 followers and grows at a rate of 6% per week. How many followers will it have after 10 weeks?
The growth after 10 weeks is approximately 895 followers
The exponential growth is calculated using f(x) = a(1 + r)t
Where, a = 500
r = 6% = 0.06
t = 10 weeks
So, f(x) = 500(1 + 0.06)10
= 500 × 1.0610
= 500 × 1.7908 = 895.4
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
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