Last updated on July 16th, 2025
We use the derivative of f(x) as a tool to understand how the function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of f(x) in detail.
We now understand the derivative of f(x). It is commonly represented as d/dx (f(x)) or (f(x))'. The function f(x) has a clearly defined derivative, indicating it is differentiable within its domain.
The key concepts are mentioned below:
Function Definition: The expression f(x) defines the function.
Differentiability: The function f(x) is differentiable if its derivative exists at all points in its domain.
Derivative Notation: The derivative is represented as f'(x) or d/dx (f(x)).
The derivative of f(x) can be denoted as d/dx (f(x)) or (f(x))'. The formula we use to differentiate f(x) depends on the specific form of the function.
For example, if f(x) is a polynomial, we use standard differentiation rules. The formula applies to all x where the function is defined and differentiable.
We can derive the derivative of f(x) using proofs. To show this, we will use the rules of differentiation and mathematical principles.
There are several methods we use to prove this, such as:
We will now demonstrate that the differentiation of f(x) results in its derivative using the above-mentioned methods:
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky.
To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like f(x).
For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x) is the result of the second derivative and this pattern continues.
For the nth Derivative of f(x), we generally use fⁿ(x) for the nth derivative of a function f(x) which tells us the change in the rate of change.
There may be points where the derivative is undefined due to discontinuities or vertical asymptotes. When x is in a domain where f(x) is defined and differentiable, the derivative can be calculated as specified by the differentiation rules.
Students frequently make mistakes when differentiating f(x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of (f(x)·g(x))
Here, we have h(x) = f(x)·g(x). Using the product rule, h'(x) = u′v + uv′ In the given equation, u = f(x) and v = g(x).
Let’s differentiate each term, u′= d/dx (f(x)) v′= d/dx (g(x))
Substituting into the given equation, h'(x) = (f'(x)).(g(x)) + (f(x)).(g'(x))
Let’s simplify terms to get the final answer, h'(x) = f'(x)g(x) + f(x)g'(x)
Thus, the derivative of the specified function is f'(x)g(x) + f(x)g'(x).
We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.
A company’s revenue is represented by the function R(x) = f(x), where R represents revenue at a certain production level x. If x = 100 units, measure the rate of change of revenue.
We have R(x) = f(x) (revenue function)...(1)
Now, we will differentiate the equation (1) Take the derivative f(x): dR/dx = f'(x)
Given x = 100, substitute this into the derivative Measure f'(100) to find the rate of change of revenue.
Hence, we get the rate of change of revenue at a production level of x = 100 as f'(100).
We find the rate of change of revenue at x = 100 by evaluating the derivative f'(100), which tells us how revenue changes with respect to production level at that specific point.
Derive the second derivative of the function y = f(x).
The first step is to find the first derivative, dy/dx = f'(x)...(1)
Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [f'(x)]
This gives us the second derivative, which is denoted by f''(x).
Therefore, the second derivative of the function y = f(x) is f''(x).
We use the step-by-step process, where we start with the first derivative. We then differentiate the first derivative to find the second derivative.
Prove: d/dx (f(x)²) = 2f(x)f'(x).
Let’s start using the chain rule: Consider y = f(x)² [f(x)]²
To differentiate, we use the chain rule: dy/dx = 2f(x).d/dx [f(x)]
Since the derivative of f(x) is f'(x), dy/dx = 2f(x).f'(x)
Substituting y = f(x)², d/dx (f(x)²) = 2f(x).f'(x)
Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace f(x) with its derivative. As a final step, we substitute y = f(x)² to derive the equation.
Solve: d/dx (f(x)/x)
To differentiate the function, we use the quotient rule: d/dx (f(x)/x) = (d/dx (f(x)).x - f(x).d/dx(x))/x²
We will substitute d/dx (f(x)) = f'(x) and d/dx (x) = 1 (f'(x)x - f(x)·1) / x² = (f'(x)x - f(x)) / x²
Therefore, d/dx (f(x)/x) = (f'(x)x - f(x)) / x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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