Last updated on July 14th, 2025
We use the derivative of arcsec(x), which is 1/(|x|√(x²-1)), as a measuring tool for how the arcsecant function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of arcsec(x) in detail.
We now understand the derivative of arcsec(x). It is commonly represented as d/dx (arcsec x) or (arcsec x)', and its value is 1/(|x|√(x²-1)). The function arcsec x has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below: Arcsecant Function: arcsec(x) is the inverse function of sec(x). Inverse Function Rule: Rule for differentiating arcsec(x) using its relationship with sec(x). Absolute Value: |x| is used in the formula to ensure the result is valid for both positive and negative x.
The derivative of arcsec(x) can be denoted as d/dx (arcsec x) or (arcsec x)'. The formula we use to differentiate arcsec x is: d/dx (arcsec x) = 1/(|x|√(x²-1)) The formula applies to all x where |x| > 1.
We can derive the derivative of arcsec x using proofs. To show this, we will use the trigonometric identities along with the rules of differentiation. There are several methods we use to prove this, such as: By First Principle Using Inverse Function Rule Using Implicit Differentiation We will now demonstrate that the differentiation of arcsec x results in 1/(|x|√(x²-1)) using the above-mentioned methods: Using Inverse Function Rule The derivative of arcsec x can be proved using the inverse function rule. If y = arcsec x, then x = sec y. Differentiating both sides with respect to x, we have: d/dx (x) = d/dx (sec y) 1 = sec y tan y (dy/dx) We know from trigonometric identities that sec² y - 1 = tan² y, hence tan y = √(sec² y - 1). Substituting sec y = x: 1 = x √(x² - 1) (dy/dx) dy/dx = 1/(x √(x² - 1)) Since y = arcsec x, the derivative is: d/dx (arcsec x) = 1/(|x|√(x²-1)).
When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like arcsec(x). For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative and this pattern continues. For the nth Derivative of arcsec(x), we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).
When x is 1 or -1, the derivative is undefined because arcsec(x) is not defined there. When x is √2, the derivative of arcsec x = 1/(|√2|√((√2)²-1)), which simplifies to 1/√2.
Students frequently make mistakes when differentiating arcsec x. These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:
Calculate the derivative of arcsec(x) when x = 3.
To find the derivative of the arcsec(x) at x = 3, we use the formula: d/dx (arcsec x) = 1/(|x|√(x²-1)) Substituting x = 3, d/dx (arcsec 3) = 1/(|3|√(3²-1)) = 1/(3√(9-1)) = 1/(3√8) = 1/(6√2) Thus, the derivative of arcsec(x) at x = 3 is 1/(6√2).
We find the derivative of arcsec(x) at a specific point by substituting the value of x into the derivative formula and then simplifying.
A light beam is directed onto a mirror at an angle described by the function y = arcsec(x), where y represents the angle of incidence. If x = √5, calculate the rate of change of the angle with respect to x.
We have y = arcsec(x) (angle of incidence)...(1) Now, we will differentiate the equation (1) Take the derivative arcsec(x): dy/dx = 1/(|x|√(x²-1)) Given x = √5, substitute this into the derivative: dy/dx = 1/(|√5|√((√5)²-1)) = 1/(√5√(5-1)) = 1/(√5√4) = 1/(2√5) Hence, the rate of change of the angle of incidence at x = √5 is 1/(2√5).
We find the rate of change of the angle by substituting the given value of x into the derivative formula and simplifying the expression.
Derive the second derivative of the function y = arcsec(x).
The first step is to find the first derivative, dy/dx = 1/(|x|√(x²-1))...(1) Now we will differentiate equation (1) to get the second derivative. Let u = |x|√(x²-1), then d²y/dx² = -d/dx (1/u) = -(-1/u²)(du/dx) We differentiate u = |x|√(x²-1) using the product rule: du/dx = (x/|x|) * (x²-1)^(-1/2) * (2x) + |x| * ((x²-1)^(-1/2) * (2x)) = (x²/(|x|√(x²-1))) + (x/√(x²-1)) Substitute u and du/dx back into the formula for d²y/dx²: d²y/dx² = - (1/(|x|√(x²-1)))² [x²/(|x|√(x²-1)) + x/√(x²-1)] Therefore, the second derivative of the function y = arcsec(x) is complex and involves further simplification.
We use the step-by-step process, where we start with the first derivative and differentiate it again using the chain and product rules to find the second derivative.
Prove: d/dx (arcsec(2x)) = 1/(2|x|√(4x²-1)).
Let's start using the chain rule: Consider y = arcsec(2x) To differentiate, we use the chain rule: dy/dx = 1/(|2x|√((2x)²-1)) * d/dx(2x) = 1/(2|x|√(4x²-1)) * 2 = 1/(|x|√(4x²-1)) Hence proved.
In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace 2x with its derivative. As a final step, we simplify the expression to derive the equation.
Solve: d/dx (arcsec(x)/x)
To differentiate the function, we use the quotient rule: d/dx (arcsec(x)/x) = (d/dx (arcsec(x)) * x - arcsec(x) * d/dx(x)) / x² We will substitute d/dx (arcsec(x)) = 1/(|x|√(x²-1)) and d/dx(x) = 1 = (1/(|x|√(x²-1)) * x - arcsec(x)) / x² = (1/√(x²-1) - arcsec(x)) / x² Therefore, d/dx (arcsec(x)/x) = (1/√(x²-1) - arcsec(x)) / x²
In this process, we differentiate the given function using the quotient rule. As a final step, we simplify the equation to obtain the final result.
Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x. Arcsecant Function: The arcsecant function is the inverse of the secant function and is written as arcsec x. Inverse Function Rule: A method used to find the derivative of inverse functions. Chain Rule: A rule for finding the derivative of a composition of functions. Absolute Value: The non-negative value of a number without regard to its sign, denoted as |x|.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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