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Last updated on July 9th, 2025

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Polynomial Equations

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Polynomial equations are important in math because they show how numbers and variables are connected through a specific pattern. These are a common type of algebraic equation that is formed using coefficients and variables arranged in a specific pattern. In this article, we will discuss polynomial equations, their formulas, types, and applications in detail.

Polynomial Equations for Canadian Students
Professor Greenline from BrightChamps

What are Polynomial Equations?

A polynomial equation is an equation with a polynomial expression equals to zero. It is made up of variables, numbers, and basic operations like addition, subtraction, and multiplication. The highest power of the variable shows the degree of the polynomial. In a polynomial equation, the exponents must be nonnegative numbers; negative numbers or fractions are not     allowed. If this condition is satisfied, the equation can be classified as a polynomial equation.

 


For example, 2x² + 3x + 1 is a polynomial. When we set it to zero, it becomes a polynomial equation: 
2x² + 3x + 1 = 0

 

 

Look at more such equations:

 


  

  • x² – 4 = 0
  • 3x³ + x – 7 = 0
  • x⁴ + 2x² – x + 5 = 0
     
Professor Greenline from BrightChamps

Difference Between Polynomial and Polynomial Equation

A polynomial is an algebraic expression made up of variables and constants. We use addition, subtraction, and multiplication to work with polynomials. The variables in a polynomial have powers that are non-negative integers.
Example: 2x + 3

 

 

A polynomial equation is formed when a polynomial is made equal to a value using the equal sign (=).
Example: 2x + 3 = 0

 

 

Note:

 

  • The degree of a polynomial equation depends on the highest exponent of the variable. 
  • To solve the equation, we find the value or values of the variable that make both sides equal.
  • If you know the solutions, you can also form a polynomial equation from them. 
     
Professor Greenline from BrightChamps

What is the Formula for a Polynomial Equation?

A polynomial equation is in the form:
p(x) = 0

 

In algebra, it can be written in the form:
p(x) = aₙxⁿ + aₙ₋₁xⁿ⁻¹ + ... + a₁x + a₀ = 0

 

 

Where:

 

  • aₙ, aₙ₋₁, ..., a₁, a₀ are real numbers called coefficients
  • ‘x’ is the variable
  • p(x) means "a polynomial in x"
  • n is a non-negative integer that shows the degree of the polynomial, which is the highest exponent of x in the expression.
     
Professor Greenline from BrightChamps

What are the Types of Polynomial Equations?

Depending on the degree of a polynomial equation, it is classified into different types. We will learn about each one step by step:

 

 

Linear Polynomial Equation


Linear polynomials are equations where the variable has the highest power of 1.
General Form: ax + b = 0

Examples:
  4x + 5 = 0
  7x – 9 = 0

 

 

Quadratic Polynomial Equation


Quadratic polynomial equations are equations where the variable has the highest power of 2.

General Form: ax² + bx + c = 0

Examples:
  2x² – 4x + 6 = 0
  5x² + 3x – 8 = 0

 

 

Cubic Polynomial Equation


If the highest power of the variable is 3, then it is said to be a cubic polynomial equation.

General Form: ax³ + bx² + cx + d = 0

Examples:
  x³ + 2x² – 3 = 0
  2x³ – x + 4 = 0

 

 

Biquadratic Polynomial Equation


Biquadratic polynomial equations are polynomial equations in which the highest power of the variable is 4.

General Form: ax⁴ + bx³ + cx² + dx + e = 0

Example: 4x⁴ + 2x² – 6x + 1 = 0.
 

Professor Greenline from BrightChamps

How to Solve Polynomial Equations?

To solve the equation p(x) = 0, we have to find the value or values of x that satisfy the equation. Such values are called roots or zeros because p(a) = 0, where ‘a’ is a root of the polynomial. Let’s learn how different polynomial equations are solved.

 

 

Forming Linear Polynomial Equations


To solve a linear polynomial equation, we set it equal to zero and find the value of the variable.
Example:
Solve 6x - 9 = 0


Step 1: Add 9 to both sides:
 6x = 9


Step 2: Divide both sides by 6:
 x = 9/6 = 3/2

 


Solving a Quadratic Polynomial from its Roots


To find a quadratic polynomial when its roots are known, we utilize the fact that the polynomial can be formed using the sum and product of the roots.
Find the quadratic polynomial whose roots are -3 and 5.


Step 1: Sum of roots = -3 + 5 = 2

 


Step 2: Product of roots = -3 × 5 = -15

 


Step 3: Use the formula
 x² - (sum of roots)x + (product of roots) = 0
 Substitute values:
 x² - 2x - 15 = 0

 


Solving Cubic Polynomial Equations


To solve a cubic polynomial equation, we find its roots by factoring or by using techniques such as synthetic division and the factor theorem. Let’s solve it step by step.

General form:
ax³ + bx² + cx + d = 0, a ≠ 0

 

Steps:


1.     Write the equation in standard form.
2.      Use the factor theorem or synthetic division to factor into a linear factor and a quadratic factor.
3.      Find the remaining roots by solving the quadratic equation

Example:


Solve x³ - 5x² + 8x - 4 = 0.


Step 1: The given equation is already in standard form.


Step 2: Substitute x = 1 as a root:
1 – 5 + 8 – 4 = 0, so x = 1 is a root.
 

Professor Greenline from BrightChamps

Real-Life Applications of Polynomial Equations

Polynomial equations have several practical applications in different fields and help students develop problem-solving skills. Let’s now learn how they are applied in various real-life situations:

 

 

  • In business and economics, polynomial equations are used to analyze and predict profit, revenue, and costs for forecasting and decision-making.

 

  • In animation and video games, polynomials help to design smooth curves and realistic motion paths.

 

  • Polynomial equations in environmental studies are used to track changes in pollution levels, population growth, and climate patterns over a period.
     
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Common Mistakes and How to Avoid Them in Polynomial Equations

When working with polynomial equations, students sometimes misunderstand the concept of polynomial equations, which leads to several errors. Here are a few common mistakes and ways to avoid them:
 

Mistake 1

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Incorrect Sign Handling
 

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Students often forget to change the sign of the terms when they are transposed across the equal sign. Ensure that the signs are handled correctly while rearranging terms.
 

Mistake 2

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Ignoring Roots
 

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 In some cases, students forget to find out all the roots of the equation. They should find various roots for higher-degree polynomials by factoring them thoroughly or by applying techniques such as the factor theorem.
 

Mistake 3

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 Usage of Incorrect Formulas
 

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Using the wrong formula when solving quadratic equations. Learn the standard formulas by heart and know when to apply them. For example: Always use the correct quadratic formula: x = (−b ± √(b² − 4ac)) / 2a.
 

Mistake 4

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Errors in Substitution
 

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Getting a non-zero result after substituting the root into the equation indicates an error. Verify the answers by plugging them back into the original equation to ensure they satisfy it. 
 

Mistake 5

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Ignoring Steps
 

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Ignoring the steps and solving the problems quickly leads to an error. Write each step clearly to prevent misunderstandings and make it easier to identify errors.
 

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Solved Examples of Polynomial Equations

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Problem 1

Solve: 2x + 3 = 7

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 x = 2
 

Explanation

Consider the given equation:
2x + 3 = 7
We subtract 3 from both sides, to isolate the term with x:
2x + 3 – 3 = 7 – 3
2x = 4Now, divide both sides by 2:
2x ÷ 2 = 4 ÷ 2
x = 2
 

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Problem 2

Solve: x² – 9 = 0

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x = ±3 
 

Explanation

Step-by-step solution:
Write the equation:
x² – 9 = 0
Add 9 to both sides:
x² = 9
Take the square root of both sides:
x = ±√9
x = ±3 
So, x can have values (–3) and 3
 

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Problem 3

Solve: x³ – 4x = 0

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x = 0, x = 2, or x = –2
 

Explanation

First, write the equation:
x³ – 4x = 0

Factor out the common term (x):
x(x² – 4) = 0

Factor the difference of squares:
x(x – 2)(x + 2) = 0

Set each factor to 0:
x = 0
x – 2 = 0 → x = 2
x + 2 = 0 → x = –2

So, x = 0, x = 2, or x = –2
 

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Problem 4

Solve: x² + 5x + 6 = 0

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 x = –2 or x = –3
 

Explanation

Write the equation:
x² + 5x + 6 = 0

We then factor the quadratic expression:
Look for two numbers that multiply to 6 and add to 5 → (2 and 3)
(x + 2)(x + 3) = 0

Set each factor to 0:
x + 2 = 0 → x = –2
x + 3 = 0 → x = –3

So, x = –2 or x = –3
 

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Problem 5

Solve: 3x² – 7x – 6 = 0

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x = 3 or x = -⅔
 

Explanation

We first identify the coefficients:
  a = 3, b = -7, c = -6

Use the quadratic formula
  x = [-b ± √(b² – 4ac)] / 2a

Let’s substitute the values into the formula
  x = [-(-7) ± √((-7)² – 4×3×-6)] / (2×3)
  x = [7 ± √(49 + 72)] / 6
  x = [7 ± √121] / 6

Simplify the square root
  x = [7 ± 11] / 6

Find the two solutions
  x = (7 + 11)/6 = 18/6 = 3
  x = (7 –11)/6 = -4/6 = -2/3

So, x = 3 or x = -2/3.
 

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FAQs on Polynomial Equations

1.What do you mean by a polynomial equation?

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2.Name the different kinds of polynomial equations.

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3.What is meant by the degree of a polynomial?

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4.How can we solve a polynomial equation?

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5.What does a polynomial's root represent?

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6.How does learning Algebra help students in Canada make better decisions in daily life?

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7.How can cultural or local activities in Canada support learning Algebra topics such as Polynomial Equations?

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8.How do technology and digital tools in Canada support learning Algebra and Polynomial Equations?

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9.Does learning Algebra support future career opportunities for students in Canada?

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