Last updated on August 5th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 45 and 75.
The greatest common factor of 45 and 75 is 15. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 45 and 75, a few methods are described below:
Steps to find the GCF of 45 and 75 using the listing of factors:
Step 1: Firstly, list the factors of each number:
Factors of 45 = 1, 3, 5, 9, 15, 45.
Factors of 75 = 1, 3, 5, 15, 25, 75.
Step 2: Now, identify the common factors of them Common factors of 45 and 75: 1, 3, 5, 15.
Step 3: Choose the largest factor The largest factor that both numbers have is 15.
The GCF of 45 and 75 is 15.
To find the GCF of 45 and 75 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 45: 45 = 3 x 3 x 5 = 3² x 5
Prime Factors of 75: 75 = 3 x 5 x 5 = 3 x 5²
Step 2: Now, identify the common prime factors The common prime factors are: 3 x 5
Step 3: Multiply the common prime factors 3 x 5 = 15.
The Greatest Common Factor of 45 and 75 is 15.
Find the GCF of 45 and 75 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 75 by 45 75 ÷ 45 = 1 (quotient),
The remainder is calculated as 75 − (45×1) = 30
The remainder is 30, not zero, so continue the process
Step 2: Now divide the previous divisor (45) by the previous remainder (30)
Divide 45 by 30 45 ÷ 30 = 1 (quotient), remainder = 45 − (30×1) = 15
Step 3: Finally, divide the previous divisor (30) by the previous remainder (15) 30 ÷ 15 = 2 (quotient), remainder = 30 − (15×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 45 and 75 is 15.
Finding GCF of 45 and 75 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 45 apples and 75 bananas. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 45 and 75 GCF of 45 and 75 3 x 5 = 15.
There are 15 equal groups
45 ÷ 15 = 3
75 ÷ 15 = 5
There will be 15 groups, and each group gets 3 apples and 5 bananas.
As the GCF of 45 and 75 is 15, the teacher can make 15 groups.
Now divide 45 and 75 by 15.
Each group gets 3 apples and 5 bananas.
A school has 45 red chairs and 75 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
GCF of 45 and 75 3 x 5 = 15. So each row will have 15 chairs.
There are 45 red and 75 blue chairs. To find the total number of chairs in each row, we should find the GCF of 45 and 75. There will be 15 chairs in each row.
A tailor has 45 meters of red ribbon and 75 meters of blue ribbon. She wants to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 45 and 75 The GCF of 45 and 75
3 x 5 = 15.
The ribbon is 15 meters long.
For calculating the longest length of the ribbon, first we need to calculate the GCF of 45 and 75, which is 15. The length of each piece of the ribbon will be 15 meters.
A carpenter has two wooden planks, one 45 cm long and the other 75 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 45 and 75
3 x 5 = 15.
The longest length of each piece is 15 cm.
To find the longest length of each piece of the two wooden planks, 45 cm and 75 cm, respectively.
We have to find the GCF of 45 and 75, which is 15 cm.
The longest length of each piece is 15 cm.
If the GCF of 45 and ‘b’ is 15, and the LCM is 225. Find ‘b’.
The value of ‘b’ is 75.
GCF x LCM = product of the numbers
15 × 225 = 45 × b
3375 = 45b
b = 3375 ÷ 45 = 75
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.