Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without a remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 1090, how they are used in real life, and tips to learn them quickly.
The numbers that divide 1090 evenly are known as factors of 1090.
A factor of 1090 is a number that divides the number without a remainder.
The factors of 1090 are 1, 2, 5, 10, 109, 218, 545, and 1090.
Negative factors of 1090: -1, -2, -5, -10, -109, -218, -545, and -1090.
Prime factors of 1090: 2, 5, and 109.
Prime factorization of 1090: 2 × 5 × 109.
The sum of factors of 1090: 1 + 2 + 5 + 10 + 109 + 218 + 545 + 1090 = 1980
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 1090. Identifying the numbers that are multiplied to get the number 1090 is the multiplication method.
Step 1: Multiply 1090 by 1, 1090 × 1 = 1090.
Step 2: Check for other numbers that give 1090 after multiplying
2 × 545 = 1090
5 × 218 = 1090
10 × 109 = 1090
Therefore, the positive factor pairs of 1090 are: (1, 1090), (2, 545), (5, 218), (10, 109).
All these factor pairs result in 1090.
For every positive factor, there is a negative factor.
Dividing the given numbers with the whole numbers until the remainder becomes zero and listing out the numbers which result as whole numbers as factors. Factors can be calculated by following a simple division method -
Step 1: Divide 1090 by 1, 1090 ÷ 1 = 1090.
Step 2: Continue dividing 1090 by the numbers until the remainder becomes 0.
1090 ÷ 1 = 1090
1090 ÷ 2 = 545
1090 ÷ 5 = 218
1090 ÷ 10 = 109
Therefore, the factors of 1090 are: 1, 2, 5, 10, 109, 218, 545, 1090.
The factors can be found by dividing it with a prime number. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 1090 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
1090 ÷ 2 = 545
545 ÷ 5 = 109
109 ÷ 109 = 1
The prime factors of 1090 are 2, 5, and 109.
The prime factorization of 1090 is: 2 × 5 × 109.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows -
Step 1: Firstly, 1090 is divided by 2 to get 545.
Step 2: Now divide 545 by 5 to get 109.
Step 3: Then divide 109 by 109 to get 1.
Here, 109 is the smallest prime number that cannot be divided anymore.
So, the prime factorization of 1090 is: 2 × 5 × 109.
Factor Pairs Two numbers that are multiplied to give a specific number are called factor pairs.
Both positive and negative factors constitute factor pairs.
Positive factor pairs of 1090: (1, 1090), (2, 545), (5, 218), and (10, 109).
Negative factor pairs of 1090: (-1, -1090), (-2, -545), (-5, -218), and (-10, -109).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 5 teams and 1090 participants in a marathon. How will they divide the participants equally?
They will get 218 participants each.
To divide the participants equally, we need to divide the total participants by the number of teams.
1090/5 = 218
A rectangular garden has a length of 109 meters and a total area of 1090 square meters. Find the width?
10 meters.
To find the width of the garden, we use the formula,
Area = length × width
1090 = 109 × width
To find the value of width, we need to shift 109 to the left side.
1090/109 = width
Width = 10.
There are 545 candies, and each box can hold 2 candies. How many boxes are needed?
273 boxes are needed.
To find the number of boxes needed, divide the total candies by the number of candies each box can hold.
545/2 = 272.5, rounded up to 273 boxes.
In a school, there are 1090 students, and 10 buses. How many students are there in each bus?
There are 109 students in each bus.
Dividing the students with the total buses, we will get the number of students in each bus.
1090/10 = 109
1090 pages need to be printed and each printer can print 109 pages at a time. How many batches of printing will need to be done?
10 batches of printing are needed.
Divide total pages by pages per batch.
1090/109 = 10
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.