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Last updated on July 24th, 2025

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Derivative of Arcsinh

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We use the derivative of arcsinh(x), which is 1/√(x²+1), as a measuring tool for how the arcsinh function changes in response to a slight change in x. Derivatives help us calculate profit or loss in real-life situations. We will now talk about the derivative of arcsinh(x) in detail.

Derivative of Arcsinh for Australian Students
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What is the Derivative of Arcsinh?

We now understand the derivative of arcsinh(x). It is commonly represented as d/dx (arcsinh(x)) or (arcsinh(x))', and its value is 1/√(x²+1). The function arcsinh(x) has a clearly defined derivative, indicating it is differentiable within its domain. The key concepts are mentioned below: Inverse Hyperbolic Sine Function: arcsinh(x) is the inverse of sinh(x). Hyperbolic Sine Function: sinh(x) = (e^x - e^(-x))/2. Chain Rule: Rule for differentiating compositions of functions.

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Derivative of Arcsinh Formula

The derivative of arcsinh(x) can be denoted as d/dx (arcsinh(x)) or (arcsinh(x))'. The formula we use to differentiate arcsinh(x) is: d/dx (arcsinh(x)) = 1/√(x²+1) (or) (arcsinh(x))' = 1/√(x²+1). The formula applies to all x in the domain of real numbers.

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Proofs of the Derivative of Arcsinh

We can derive the derivative of arcsinh(x) using proofs. To show this, we will use the definition of the inverse function along with the rules of differentiation. There are several methods we use to prove this, such as: By Implicit Differentiation Using Chain Rule We will now demonstrate that the differentiation of arcsinh(x) results in 1/√(x²+1) using the above-mentioned methods: By Implicit Differentiation The derivative of arcsinh(x) can be proved using implicit differentiation. To find the derivative of arcsinh(x), we consider y = arcsinh(x), which implies sinh(y) = x. Differentiating both sides with respect to x, we have: cosh(y) dy/dx = 1. Using the identity cosh²(y) - sinh²(y) = 1, we find cosh(y) = √(1 + sinh²(y)) = √(1 + x²). Thus, dy/dx = 1/√(1 + x²). Hence, proved. Using Chain Rule To prove the differentiation of arcsinh(x) using the chain rule, We use the formula: y = arcsinh(x) implies sinh(y) = x. Differentiating both sides with respect to x, we use the chain rule: cosh(y) dy/dx = 1. From cosh²(y) - sinh²(y) = 1, we find cosh(y) = √(1 + x²). So, dy/dx = 1/√(1 + x²). Hence, dy/dx = 1/√(1 + x²).

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Higher-Order Derivatives of Arcsinh

When a function is differentiated several times, the derivatives obtained are referred to as higher-order derivatives. Higher-order derivatives can be a little tricky. To understand them better, think of a car where the speed changes (first derivative) and the rate at which the speed changes (second derivative) also changes. Higher-order derivatives make it easier to understand functions like arcsinh(x). For the first derivative of a function, we write f′(x), which indicates how the function changes or its slope at a certain point. The second derivative is derived from the first derivative, which is denoted using f′′(x). Similarly, the third derivative, f′′′(x), is the result of the second derivative, and this pattern continues. For the nth Derivative of arcsinh(x), we generally use fⁿ(x) for the nth derivative of a function f(x), which tells us the change in the rate of change (continuing for higher-order derivatives).

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Special Cases:

When x is 0, the derivative of arcsinh(x) = 1/√(0²+1), which is 1. When x approaches ±∞, the derivative approaches 0 since the denominator becomes larger.

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Common Mistakes and How to Avoid Them in Derivatives of Arcsinh

Students frequently make mistakes when differentiating arcsinh(x). These mistakes can be resolved by understanding the proper solutions. Here are a few common mistakes and ways to solve them:

Mistake 1

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Not simplifying the equation

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Students may forget to simplify the equation, which can lead to incomplete or incorrect results. They often skip steps and directly arrive at the result, especially when solving using the chain rule. Ensure that each step is written in order. Students might think it is awkward, but it is important to avoid errors in the process.

Mistake 2

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Incorrect use of Chain Rule

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While differentiating functions such as arcsinh(x²), students misapply the chain rule. For example: Incorrect differentiation: d/dx (arcsinh(x²)) = 1/√(x⁴+1). To differentiate correctly, use the chain rule: d/dx (arcsinh(x²)) = (2x)/√(x⁴+1). To avoid this mistake, write the chain rule without errors. Always check for errors in the calculation and ensure it is properly simplified.

Mistake 3

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Forgetting the Identity for Hyperbolic Functions

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Students might not remember the identity cosh²(y) - sinh²(y) = 1, which is crucial for finding the derivative of arcsinh. Ensure you recall and apply this identity correctly when differentiating.

Mistake 4

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Not Applying the Implicit Differentiation

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Students often forget to use implicit differentiation when dealing with inverse functions. This happens when the derivative of the implicit function is not considered. For example: Incorrect: d/dx (arcsinh(x)) = √(1 + x²). To fix this error, use implicit differentiation and solve for dy/dx correctly, resulting in 1/√(1 + x²).

Mistake 5

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Ignoring Higher-Order Derivatives

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When asked for higher-order derivatives, students might stop at the first derivative. It's important to continue differentiating to find the second, third, or nth derivative as required. Practice differentiating multiple times to avoid this oversight.

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Examples Using the Derivative of Arcsinh

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Problem 1

Calculate the derivative of (arcsinh(x) * x²).

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Here, we have f(x) = arcsinh(x) * x². Using the product rule, f'(x) = u′v + uv′. In the given equation, u = arcsinh(x) and v = x². Let’s differentiate each term: u′ = d/dx (arcsinh(x)) = 1/√(x²+1). v′ = d/dx (x²) = 2x. Substituting into the given equation, f'(x) = (1/√(x²+1)) * x² + arcsinh(x) * 2x. Let’s simplify terms to get the final answer, f'(x) = x²/√(x²+1) + 2x * arcsinh(x). Thus, the derivative of the specified function is x²/√(x²+1) + 2x * arcsinh(x).

Explanation

We find the derivative of the given function by dividing the function into two parts. The first step is finding its derivative and then combining them using the product rule to get the final result.

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Problem 2

A new roller coaster is designed with a track that follows the function y = arcsinh(x), representing the vertical displacement of the track at a horizontal distance x. If x = 2 meters, measure the slope of the track.

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We have y = arcsinh(x) (slope of the track)...(1). Now, we will differentiate the equation (1). Take the derivative arcsinh(x): dy/dx = 1/√(x²+1). Given x = 2 (substitute this into the derivative), dy/dx = 1/√(2²+1) = 1/√5. Hence, we get the slope of the track at a distance x = 2 as 1/√5.

Explanation

We find the slope of the track at x = 2 as 1/√5, which means that at a given point, the height of the track would rise at a rate of 1/√5 per unit of horizontal distance.

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Problem 3

Derive the second derivative of the function y = arcsinh(x).

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The first step is to find the first derivative, dy/dx = 1/√(x²+1)...(1). Now we will differentiate equation (1) to get the second derivative: d²y/dx² = d/dx [1/√(x²+1)]. Here we use the chain rule, d²y/dx² = -x/(x²+1)^(3/2). Therefore, the second derivative of the function y = arcsinh(x) is -x/(x²+1)^(3/2).

Explanation

We use the step-by-step process, where we start with the first derivative. Using the chain rule, we differentiate 1/√(x²+1). We then substitute the identity and simplify the terms to find the final answer.

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Problem 4

Prove: d/dx (arcsinh(x²)) = 2x/√(x⁴+1).

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Let’s start using the chain rule: Consider y = arcsinh(x²). To differentiate, we use the chain rule: dy/dx = (d/dx (x²))/√((x²)²+1). Since the derivative of x² is 2x, dy/dx = 2x/√(x⁴+1). Substituting y = arcsinh(x²), d/dx (arcsinh(x²)) = 2x/√(x⁴+1). Hence proved.

Explanation

In this step-by-step process, we used the chain rule to differentiate the equation. Then, we replace x² with its derivative. As a final step, we substitute y = arcsinh(x²) to derive the equation.

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Problem 5

Solve: d/dx (arcsinh(x)/x).

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To differentiate the function, we use the quotient rule: d/dx (arcsinh(x)/x) = (d/dx (arcsinh(x)) * x - arcsinh(x) * d/dx(x))/x². We will substitute d/dx (arcsinh(x)) = 1/√(x²+1) and d/dx (x) = 1, (1/√(x²+1) * x - arcsinh(x) * 1)/x². = (x/√(x²+1) - arcsinh(x))/x². Therefore, d/dx (arcsinh(x)/x) = (x/√(x²+1) - arcsinh(x))/x².

Explanation

In this process, we differentiate the given function using the product rule and quotient rule. As a final step, we simplify the equation to obtain the final result.

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FAQs on the Derivative of Arcsinh

1.Find the derivative of arcsinh(x).

Using the definition of inverse hyperbolic functions, d/dx (arcsinh(x)) = 1/√(x²+1).

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2.Can we use the derivative of arcsinh(x) in real life?

Yes, we can use the derivative of arcsinh(x) in real life in calculating the rate of change of any motion or deformation, especially in fields such as engineering and physics.

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3.Is it possible to take the derivative of arcsinh(x) at x = 0?

Yes, at x = 0, the derivative of arcsinh(x) is 1, as shown in the formula 1/√(x²+1).

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4.What rule is used to differentiate arcsinh(x²)?

We use the chain rule to differentiate arcsinh(x²), d/dx (arcsinh(x²)) = (2x)/√(x⁴+1).

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5.Are the derivatives of arcsinh(x) and sinh⁻¹(x) the same?

Yes, arcsinh(x) and sinh⁻¹(x) represent the same function, and their derivatives are identical: 1/√(x²+1).

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6.Can we find the second derivative of the arcsinh(x) formula?

Yes, by differentiating the first derivative 1/√(x²+1), we use the chain rule to obtain the second derivative: -x/(x²+1)^(3/2).

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Important Glossaries for the Derivative of Arcsinh

Derivative: The derivative of a function indicates how the given function changes in response to a slight change in x. Inverse Hyperbolic Function: A function that is the inverse of a hyperbolic function, such as arcsinh(x). Chain Rule: A rule in calculus used to differentiate compositions of functions. Implicit Differentiation: A method used to find derivatives of functions not easily expressed as explicit functions. Higher-Order Derivative: A derivative obtained by differentiating a function multiple times, showing changes in the rate of change.

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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