Last updated on May 26th, 2025
If a number is multiplied by itself, the result is a square. The inverse operation is finding the square root. The square root is used in various fields such as engineering, finance, and architecture. Here, we will discuss the square root of 726.
The square root is the inverse of squaring a number. Since 726 is not a perfect square, its square root is expressed in both radical and exponential forms. In radical form, it is expressed as √726, whereas in exponential form, it is expressed as (726)^(1/2). √726 ≈ 26.933, which is an irrational number because it cannot be expressed as a ratio of two integers.
The prime factorization method is applicable for perfect square numbers. For non-perfect squares like 726, the long division and approximation methods are often used. Let's explore these methods:
The prime factorization of a number involves expressing it as a product of prime numbers. Let's explore the prime factorization of 726.
Step 1: Finding the prime factors of 726
Breaking it down, we get 2 x 3 x 11 x 11: 2^1 x 3^1 x 11^2
Step 2: Now we have the prime factors of 726. Since 726 is not a perfect square, we cannot pair all the factors evenly. Thus, prime factorization doesn't yield an exact square root for 726.
The long division method is used for non-perfect square numbers. Here's how to find the square root of 726 using this method:
Step 1: Group the digits of 726 from right to left. We group it as 26 and 7.
Step 2: Find n whose square is closest to 7. Use n = 2 because 2 x 2 = 4, which is less than 7. The quotient is 2, and after subtracting 4 from 7, the remainder is 3.
Step 3: Bring down 26, making the new dividend 326. Double the quotient (2), giving the new divisor as 4.
Step 4: Find n such that (4n) x n ≤ 326. Let's use n = 7, giving us 47 x 7 = 329, which is too large, so let's try n = 6.
Step 5: 46 x 6 = 276. Subtract 276 from 326, leaving a remainder of 50.
Step 6: Add a decimal point and bring down two zeros, making it 5000. Use 532 x 3 = 1596, which is too large.
Step 7: Adjust n to get a closer approximation. Continuously apply these steps until you reach the desired decimal precision.
The approximation method is an easier way to estimate square roots:
Step 1: Identify the nearest perfect squares around 726. The nearest smaller perfect square is 625 (25^2), and the nearest larger is 729 (27^2). Thus, √726 is between 25 and 27.
Step 2: Use the formula for approximation: (Given number - smaller perfect square) / (larger perfect square - smaller perfect square) Using (726 - 625) / (729 - 625) = 101 / 104 ≈ 0.971. Adding this to the base of 25: 25 + 0.971 = 25.971, so the square root of 726 is approximately 25.971.
Students often make mistakes when calculating square roots, such as ignoring the negative square root or skipping steps in the long division method. Let's explore some common mistakes:
Can you help Max find the area of a square box if its side length is given as √726?
The area of the square is approximately 726 square units.
The area of a square is calculated as side^2.
With a side length of √726, the area = (√726)^2 = 726 square units.
A square-shaped building measures 726 square feet. If each side is √726, what will be the square footage of half the building?
363 square feet
Since the building is square-shaped, dividing the total area by 2 gives half the building's area: 726 / 2 = 363 square feet.
Calculate √726 x 5.
Approximately 134.665
First, find the square root of 726, approximately 26.933, then multiply by 5: 26.933 x 5 = 134.665.
What will be the square root of (726 + 9)?
The square root is 27.
Calculate the sum of (726 + 9) = 735, then find the square root: √735 ≈ 27.
Find the perimeter of the rectangle if its length ‘l’ is √726 units and the width ‘w’ is 20 units.
The perimeter is approximately 93.866 units.
Perimeter of a rectangle = 2 × (length + width).
Perimeter = 2 × (√726 + 20) ≈ 2 × (26.933 + 20) ≈ 2 × 46.933 = 93.866 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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