Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. The square root is used in the field of vehicle design, finance, etc. Here, we will discuss the square root of 253.
The square root is the inverse of the square of the number. 253 is not a perfect square. The square root of 253 is expressed in both radical and exponential form. In the radical form, it is expressed as √253, whereas (253)^(1/2) in the exponential form. √253 ≈ 15.90597, which is an irrational number because it cannot be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for perfect square numbers. However, the prime factorization method is not used for non-perfect square numbers where long-division method and approximation method are used. Let us now learn the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 253 is broken down into its prime factors:
Step 1: Finding the prime factors of 253 Breaking it down, we get 11 x 23.
Step 2: Since 253 is not a perfect square, the digits of the number can’t be grouped in pairs. Therefore, calculating 253 using prime factorization is not straightforward.
The long division method is particularly used for non-perfect square numbers. In this method, we should check the closest perfect square number for the given number. Let us now learn how to find the square root using the long division method, step by step:
Step 1: To begin with, we need to group the numbers from right to left. In the case of 253, we need to group it as 53 and 2.
Step 2: Now we need to find n whose square is less than or equal to 2. We can say n as ‘1’ because 1 x 1 is lesser than or equal to 2. Now the quotient is 1; after subtracting 1 from 2, the remainder is 1.
Step 3: Now let us bring down 53, which is the new dividend. Add the old divisor with the same number 1 + 1 to get 2, which will be our new divisor.
Step 4: The new divisor will be the sum of the dividend and quotient. Now we get 2n as the new divisor, and we need to find the value of n.
Step 5: The next step is finding 2n × n ≤ 153. Let us consider n as 7, now 27 x 7 = 189, which is too large, so n is 5.
Step 6: Subtract 125 (25 x 5) from 153; the difference is 28, and the quotient is 15.
Step 7: Since the dividend is less than the divisor, we need to add a decimal point. Adding the decimal point allows us to add two zeroes to the dividend. Now the new dividend is 2800.
Step 8: Now we need to find the new divisor that is 310 because 310 x 9 = 2790. Step 9: Subtracting 2790 from 2800, we get the result 10.
Step 10: Now the quotient is 15.9
Step 11: Continue doing these steps until we get two numbers after the decimal point. Suppose if there are no decimal values, continue till the remainder is zero So the square root of √253 is approximately 15.90.
The approximation method is another method for finding square roots. It is an easy method to find the square root of a given number. Now let us learn how to find the square root of 253 using the approximation method.
Step 1: Now we have to find the closest perfect square of √253. The smallest perfect square less than 253 is 225, and the largest perfect square greater than 253 is 256. √253 falls somewhere between 15 and 16.
Step 2: Now we need to apply the formula: (Given number - smallest perfect square) / (Greater perfect square - smallest perfect square). Using the formula (253 - 225) ÷ (256 - 225) = 28 ÷ 31 ≈ 0.903. Using the formula, we identified the decimal point of our square root. The next step is adding the value we got initially to the decimal number, which is 15 + 0.903 ≈ 15.903.
So, the square root of 253 is approximately 15.90.
Students do make mistakes while finding the square root, like forgetting about the negative square root, skipping steps in long division methods, etc. Now let us look at a few of those mistakes that students tend to make in detail.
Can you help Max find the area of a square box if its side length is given as √253?
The area of the square is approximately 253 square units.
The area of the square = side².
The side length is given as √253.
Area of the square = side² = √253 × √253 = 253.
Therefore, the area of the square box is approximately 253 square units.
A square-shaped plot measuring 253 square meters is built; if each of the sides is √253, what will be the square meters of half of the plot?
126.5 square meters
We can just divide the given area by 2 as the plot is square-shaped.
Dividing 253 by 2 gives us 126.5.
So half of the plot measures 126.5 square meters.
Calculate √253 × 5.
Approximately 79.53
The first step is to find the square root of 253, which is approximately 15.90597.
The second step is to multiply 15.90597 by 5.
So 15.90597 × 5 ≈ 79.53.
What will be the square root of (225 + 28)?
The square root is approximately 15.90.
To find the square root, we need to find the sum of (225 + 28).
225 + 28 = 253, and then √253 ≈ 15.90597.
Therefore, the square root of (225 + 28) is approximately ±15.90.
Find the perimeter of the rectangle if its length ‘l’ is √253 units and the width ‘w’ is 38 units.
We find the perimeter of the rectangle as approximately 107.81 units.
Perimeter of the rectangle = 2 × (length + width).
Perimeter = 2 × (√253 + 38)
≈ 2 × (15.90597 + 38)
≈ 2 × 53.90597
≈ 107.81 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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