Last updated on May 26th, 2025
If a number is multiplied by the same number, the result is a square. The inverse of the square is a square root. Square roots are used in fields such as vehicle design, finance, etc. Here, we will discuss the square root of 1444.
The square root is the inverse of the square of the number. 1444 is a perfect square. The square root of 1444 is expressed in both radical and exponential forms. In radical form, it is expressed as √1444, whereas (1444)^(1/2) in exponential form. √1444 = 38, which is a rational number because it can be expressed in the form of p/q, where p and q are integers and q ≠ 0.
The prime factorization method is used for finding the square root of perfect square numbers. Let's learn how to find the square root using the following methods:
The product of prime factors is the prime factorization of a number. Now let us look at how 1444 is broken down into its prime factors.
Step 1: Finding the prime factors of 1444 Breaking it down, we get 2 x 2 x 19 x 19: 2^2 x 19^2
Step 2: Now that we have found the prime factors of 1444, we make pairs of those prime factors. Since 1444 is a perfect square, we can pair the factors and take one factor from each pair.
Therefore, the square root of 1444 using prime factorization is 2 x 19 = 38.
The long division method is used for perfect and non-perfect square numbers. Let us now learn how to find the square root using the long division method, step by step.
Step 1: To begin, we need to group the numbers from right to left. In the case of 1444, we group it as 44 and 14.
Step 2: Now, find n whose square is less than or equal to 14. We can say n is ‘3’ because 3 x 3 = 9, which is less than 14. The quotient is 3 after subtracting 9 from 14, and the remainder is 5.
Step 3: Bring down 44, making the new dividend 544. Add the old divisor with the same number 3, getting 6, which will be part of our new divisor.
Step 4: The new divisor is 6n. We need to find the value of n so that 6n x n ≤ 544. Let's consider n as 8; 68 x 8 = 544.
Step 5: Subtract 544 from 544, getting a remainder of 0, and the quotient is 38.
So the square root of √1444 is 38.
Since 1444 is a perfect square, we don't need to use the approximation method to find its square root. However, if needed, we would find it by identifying perfect squares around 1444 and estimating the value, but in this case, we already know that √1444 = 38.
Students may make mistakes while finding the square root, such as forgetting about the negative square root or skipping steps in the long division method. Let us look at a few of these mistakes in detail.
Can you help Max find the area of a square box if its side length is given as √1444?
The area of the square is 1444 square units.
The area of the square = side^2.
The side length is given as √1444.
Area of the square = side^2 = √1444 × √1444 = 38 × 38 = 1444.
Therefore, the area of the square box is 1444 square units.
A square-shaped building measuring 1444 square feet is built; if each of the sides is √1444, what will be the square feet of half of the building?
722 square feet
We can just divide the given area by 2 as the building is square-shaped.
Dividing 1444 by 2 = we get 722.
So half of the building measures 722 square feet.
Calculate √1444 × 5.
190
The first step is to find the square root of 1444, which is 38.
The second step is to multiply 38 by 5.
So 38 × 5 = 190.
What will be the square root of (1400 + 44)?
The square root is 38.
To find the square root, we need to find the sum of (1400 + 44). 1400 + 44 = 1444, and then √1444 = 38.
Therefore, the square root of (1400 + 44) is ±38.
Find the perimeter of the rectangle if its length ‘l’ is √1444 units and the width ‘w’ is 50 units.
We find the perimeter of the rectangle as 176 units.
Perimeter of the rectangle = 2 × (length + width)
Perimeter = 2 × (√1444 + 50) = 2 × (38 + 50) = 2 × 88 = 176 units.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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