Last updated on August 12th, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and to schedule events. In this topic, we will learn about the GCF of 14 and 22.
The greatest common factor of 14 and 22 is 2. The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 14 and 22, a few methods are described below:
Steps to find the GCF of 14 and 22 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 14 = 1, 2, 7, 14. Factors of 22 = 1, 2, 11, 22.
Step 2: Now, identify the common factors of them Common factors of 14 and 22: 1, 2.
Step 3: Choose the largest factor The largest factor that both numbers have is 2. The GCF of 14 and 22 is 2.
To find the GCF of 14 and 22 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 14: 14 = 2 x 7
Prime Factors of 22: 22 = 2 x 11
Step 2: Now, identify the common prime factors The common prime factor is: 2
Step 3: Multiply the common prime factors The Greatest Common Factor of 14 and 22 is 2.
Find the GCF of 14 and 22 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 22 by 14 22 ÷ 14 = 1 (quotient), The remainder is calculated as 22 − (14×1) = 8 The remainder is 8, not zero, so continue the process
Step 2: Now divide the previous divisor (14) by the previous remainder (8) Divide 14 by 8 14 ÷ 8 = 1 (quotient), remainder = 14 − (8×1) = 6
Step 3: Now divide the previous divisor (8) by the previous remainder (6) Divide 8 by 6 8 ÷ 6 = 1 (quotient), remainder = 8 − (6×1) = 2
Step 4: Now divide the previous divisor (6) by the previous remainder (2) Divide 6 by 2 6 ÷ 2 = 3 (quotient), remainder = 6 − (2×3) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 14 and 22 is 2.
Finding the GCF of 14 and 22 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 14 apples and 22 oranges. He wants to create fruit baskets with an equal number of apples and oranges in each basket. What is the maximum number of baskets he can make?
We should find the GCF of 14 and 22. GCF of 14 and 22 is 2. There are 2 equal baskets. 14 ÷ 2 = 7 22 ÷ 2 = 11\
There will be 2 baskets, and each basket gets 7 apples and 11 oranges.
As the GCF of 14 and 22 is 2, the chef can make 2 baskets. Now divide 14 and 22 by 2. Each basket gets 7 apples and 11 oranges.
A gardener has 14 rose plants and 22 tulip plants. He wants to arrange them in rows with the same number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
GCF of 14 and 22 is 2. So each row will have 2 plants.
There are 14 rose plants and 22 tulip plants.
To find the total number of plants in each row, we should find the GCF of 14 and 22. There will be 2 plants in each row.
A tailor has 14 meters of red fabric and 22 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 14 and 22. The GCF of 14 and 22 is 2. The fabric is 2 meters long.
For calculating the longest length of the fabric, first we need to calculate the GCF of 14 and 22, which is 2. The length of each piece of fabric will be 2 meters.
A carpenter has two wooden planks, one 14 cm long and the other 22 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 14 and 22 is 2. The longest length of each piece is 2 cm.
To find the longest length of each piece of the two wooden planks, 14 cm and 22 cm respectively, we have to find the GCF of 14 and 22, which is 2 cm. The longest length of each piece is 2 cm.
If the GCF of 14 and ‘b’ is 2, and the LCM is 154, find ‘b’.
The value of ‘b’ is 22.
GCF x LCM = product of the numbers
2 × 154 = 14 × b
308 = 14b
b = 308 ÷ 14 = 22
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.