Last updated on August 1st, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items and schedule events. In this topic, we will learn about the GCF of 14 and 10.
The greatest common factor of 14 and 10 is 2. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 14 and 10, a few methods are described below -
Steps to find the GCF of 14 and 10 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 14 = 1, 2, 7, 14.
Factors of 10 = 1, 2, 5, 10.
Step 2: Now, identify the common factors of them Common factors of 14 and 10: 1, 2.
Step 3: Choose the largest factor
The largest factor that both numbers have is 2.
The GCF of 14 and 10 is 2.
To find the GCF of 14 and 10 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 14: 14 = 2 x 7
Prime Factors of 10: 10 = 2 x 5
Step 2: Now, identify the common prime factors
The common prime factor is: 2
Step 3: Multiply the common prime factors
The GCF of 14 and 10 is 2.
Find the GCF of 14 and 10 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 14 by 10 14 ÷ 10 = 1 (quotient)
The remainder is calculated as 14 − (10×1) = 4
The remainder is 4, not zero, so continue the process
Step 2: Now divide the previous divisor (10) by the previous remainder (4)
Divide 10 by 4 10 ÷ 4 = 2 (quotient), remainder = 10 − (4×2) = 2
The remainder is not zero, so continue
Step 3: Divide the previous divisor (4) by the previous remainder (2)
Divide 4 by 2 4 ÷ 2 = 2 (quotient), remainder = 4 − (2×2) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 14 and 10 is 2.
Finding the GCF of 14 and 10 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A baker has 14 chocolate muffins and 10 blueberry muffins. She wants to arrange them into equal sets with the largest number of muffins in each set. How many muffins will be in each set?
We should find the GCF of 14 and 10 GCF of 14 and 10 is 2.
There are 2 muffins in each set. 14 ÷ 2 = 7
10 ÷ 2 = 5
There will be 2 muffins in each set, with 7 sets of chocolate muffins and 5 sets of blueberry muffins.
As the GCF of 14 and 10 is 2, the baker can make sets with 2 muffins each. Now divide 14 and 10 by 2. Each set has 7 chocolate muffins and 5 blueberry muffins.
A gardener has 14 apple trees and 10 orange trees. He wants to plant them in rows with the same number of trees in each row, using the largest possible number of trees per row. How many trees will be in each row?
GCF of 14 and 10 is 2.
So each row will have 2 trees.
There are 14 apple trees and 10 orange trees. To find the total number of trees in each row, we should find the GCF of 14 and 10. There will be 2 trees in each row.
A chef has 14 kilograms of flour and 10 kilograms of sugar. She wants to divide both into containers of equal weight, with the largest possible weight. What should be the weight of each container?
For calculating the largest equal weight, we have to calculate the GCF of 14 and 10
The GCF of 14 and 10 is 2.
Each container should weigh 2 kilograms.
For calculating the largest weight of the containers, first we need to calculate the GCF of 14 and 10 which is 2. Each container will weigh 2 kilograms.
A carpenter has two wooden planks, one 14 cm long and the other 10 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 14 and 10 is 2.
The longest length of each piece is 2 cm.
To find the longest length of each piece of the two wooden planks, 14 cm and 10 cm, respectively. We have to find the GCF of 14 and 10, which is 2 cm. The longest length of each piece is 2 cm.
If the GCF of 14 and ‘a’ is 2, and the LCM is 70. Find ‘a’.
The value of ‘a’ is 10.
GCF x LCM = product of the numbers 2 × 70 = 14 × a
140 = 14a
a = 140 ÷ 14 = 10
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.