Last updated on May 26th, 2025
The divisibility rule is a way to find out whether a number is divisible by another number without using the division method. In real life, we can use divisibility rules for quick math, dividing things evenly, and sorting things. In this topic, we will learn about the divisibility rule of 585.
The divisibility rule for 585 is a method by which we can find out if a number is divisible by 585 or not without using the division method. Check whether 1755 is divisible by 585 with the divisibility rule.
Step 1: Check if the number is divisible by 5. A number is divisible by 5 if it ends in 0 or 5. Here, 1755 ends in 5, so it is divisible by 5.
Step 2: Check if the number is divisible by 9. Add all the digits of the number and check if the sum is divisible by 9. For 1755, add the digits: 1 + 7 + 5 + 5 = 18. Since 18 is divisible by 9, 1755 is divisible by 9.
Step 3: Check if the number is divisible by 13. This step may involve some trial division or subtraction method, as the simple rule involves checking divisibility by 13 directly. In this case, let's say we confirm through division that 1755 is divisible by 13.
Since 1755 is divisible by 5, 9, and 13, it is divisible by 585 (since 585 = 5 × 9 × 13).
Learn the divisibility rule to help kids master division. Let’s learn a few tips and tricks for the divisibility rule of 585.
The divisibility rule of 585 helps us to quickly check if the given number is divisible by 585, but common mistakes like calculation errors lead to incorrect conclusions. Here we will understand some common mistakes and how to avoid them.
Is the number of pages in a book, 1170, divisible by 585?
Yes, 1170 is divisible by 585.
To check if 1170 is divisible by 585, follow these steps:
1) Verify if 1170 is divisible by 5 (the last digit should be 0 or 5). The last digit is 0, so it is divisible by 5.
2) Check if 1170 is divisible by 9 (the sum of the digits should be divisible by 9). The sum of the digits is 1 + 1 + 7 + 0 = 9, which is divisible by 9.
3) Check if 1170 is divisible by 13. Divide 1170 by 13, resulting in 90, which is an integer.
Since 1170 is divisible by 5, 9, and 13, it is divisible by 585.
Can a shipment of 1755 items be evenly divided into boxes of 585 items each?
Yes, 1755 can be evenly divided into boxes of 585 items each.
To determine if 1755 is divisible by 585, use the following checks:
1) The last digit of 1755 is 5, so it is divisible by 5.
2) The sum of the digits is 1 + 7 + 5 + 5 = 18, which is divisible by 9.
3) Divide 1755 by 13, resulting in 135, which is an integer.
Since 1755 meets all the conditions for divisibility by 5, 9, and 13, it is divisible by 585.
Is the total cost of $2925 for a bulk order divisible by 585?
Yes, 2925 is divisible by 585.
To check if 2925 is divisible by 585, proceed with these checks:
1) The last digit is 5, so it is divisible by 5.
2) The sum of the digits is 2 + 9 + 2 + 5 = 18, which is divisible by 9.
3) Divide 2925 by 13, resulting in 225, which is an integer.
Since 2925 is divisible by 5, 9, and 13, it is divisible by 585.
Is a batch of 2345 products evenly divisible by 585?
No, 2345 is not divisible by 585.
To determine if 2345 is divisible by 585, conduct these checks:
1) The last digit is 5, so it is divisible by 5.
2) The sum of the digits is 2 + 3 + 4 + 5 = 14, which is not divisible by 9.
Since 2345 fails the divisibility test for 9, it is not divisible by 585.
Is the number of participants, 5265, in a conference divisible by 585?
Yes, 5265 is divisible by 585.
To verify if 5265 is divisible by 585, follow these steps:
1) The last digit is 5, so it is divisible by 5.
2) The sum of the digits is 5 + 2 + 6 + 5 = 18, which is divisible by 9.
3) Divide 5265 by 13, resulting in 405, which is an integer.
Since 5265 is divisible by 5, 9, and 13, it is divisible by 585.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.