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224 LearnersLast updated on December 11, 2025

The volume of a solid of revolution is the amount of space it occupies. It is calculated using the method of integration.
One common method is the disk method, where you integrate the area of circular disks along the axis of rotation. Another is the shell method, which uses cylindrical shells.
To derive the volume of a solid of revolution, we use calculus, specifically integration. The disk method involves slicing the solid perpendicular to the axis of rotation into thin disks and summing their volumes.
The formula for the volume using the disk method is: \(V = \pi \int_{a}^{b} [f(x)]^2 \, dx ]\)where f(x) is the function being rotated around the axis.
The volume of a solid of revolution can be found using integral calculus. First, determine the axis of rotation and the function or region being rotated. Use the disk or shell method to set up an integral that represents the volume.
For the disk method, the formula is: \( V = \pi \int_{a}^{b} [f(x)]^2 \, dx \)
For the shell method, the formula is:\( V = 2\pi \int_{a}^{b} x \cdot f(x) \, dx
\)
Evaluate the integral to find the volume.


Choose the appropriate method: Decide between the disk and shell method based on the axis of rotation and the function given.
Understand the geometry: Visualize the shape formed by the revolution, which helps in setting up the integral correctly.
Simplify calculations: If possible, simplify the function before integrating to make the calculations easier.
Check units: Make sure your final answer is in cubic units, as volume is a measure of space.
Making mistakes while learning the volume of solids of revolution is common. Let’s look at some common mistakes and how to avoid them to get a better understanding of these volumes.
Find the volume of the solid obtained by rotating the region bounded by \( y = x^2 \) and \( y = 0 \) from \( x = 0 \) to \( x = 1 \) about the x-axis.
The volume of the solid is \((\frac{\pi}{5}).\)
Using the disk method:\( V = \pi \int_{0}^{1} (x^2)^2 \, dx \)
\(V = \pi \int_{0}^{1} x^4 \, dx \)
\(V = \pi \left[ \frac{x^5}{5} \right]_{0}^{1} \)
\(V = \frac{\pi}{5} \)
Calculate the volume of the solid formed by rotating the function \( y = \sqrt{x} \) from \( x = 0 \) to \( x = 4 \) about the x-axis.
The volume of the solid is \((\frac{32\pi}{3}).\)
Using the disk method:\( [ V = \pi \int_{0}^{4} (\sqrt{x})^2 \, dx ]\)
\([ V = \pi \int_{0}^{4} x \, dx ]\)
\([ V = \pi \left[ \frac{x^2}{2} \right]_{0}^{4} ]\)
\[ V = \pi \left( \frac{16}{2} \right) \]
\([ V = 8\pi ]\)
Determine the volume of the solid obtained by rotating the region between \( y = x + 1 \) and \( y = 0 \) from \( x = 0 \) to \( x = 2 \) about the y-axis.
The volume of the solid is\( (8\pi).\)
Using the shell method:\( [ V = 2\pi \int_{0}^{2} x(x+1) \, dx ]\)
\([ V = 2\pi \int_{0}^{2} (x^2 + x) \, dx ]\)
\([ V = 2\pi \left[ \frac{x^3}{3} + \frac{x^2}{2} \right]_{0}^{2} ]\)
\([ V = 2\pi \left( \frac{8}{3} + 2 \right) ]\)
\([ V = 8\pi ]\)

Nishtha is a passionate Maths teacher with 3 years of teaching experience. She focuses on making mathematics simple, engaging, and stress-free through student-centric, interactive, and exam-oriented teaching. With strong fundamentals, regular practice, an
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