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317 LearnersLast updated on September 4, 2025

The surface area of a truncated cone is the total area occupied by the boundary or surface of the truncated cone. It is measured in square units.
A truncated cone is formed by slicing the top off a cone parallel to its base. This shape has two circular bases: a larger base and a smaller base. It also has a curved surface connecting the two bases.
Therefore, the surface area includes the areas of these two bases and the curved surface area. The truncated cone can have varying slant heights depending on the angle of the cut.
A truncated cone has a curved surface and two bases, each with its area. The surface area (SA) of a truncated cone is calculated using the formula:
SA = pi (r_1 + r_2) x l + pi r_12 + pi r_22 where (r_1) and (r_2) are the radii of the two bases, and l is the slant height of the truncated cone.
The curved surface area of a truncated cone is the area of the slanted portion that connects the two circular bases.
The formula for the curved surface area (CSA) is: CSA = pi (r_1 + r_2) x l where (r_1) and (r_2) are the radii of the two bases, and l is the slant height of the truncated cone.


The total surface area of a truncated cone includes the areas of both circular bases and the curved surface.
The formula is: Total Surface Area = pi (r_1 + r_2) x l + \pi r_12 + pi r_22 where (r_1) and (r_2) are the radii of the two bases, and l is the slant height.
To derive this formula, imagine unrolling the curved surface into a sector of a larger circle. The radius of this circle is the slant height, and the arc length is the difference in the circumferences of the two bases.
The volume of a truncated cone shows how much space is inside it. It is one-third of the height times the sum of the areas of the two bases plus the square root of the product of the bases.
The formula is: Volume = 1/3 pi h (r_12 + r_22 + r_1 x r_2) where h is the height of the truncated cone, and (r_1) and (r_2) are the radii of the two bases.
Students sometimes confuse the curved surface area (CSA) with the total surface area (TSA). Remember, CSA includes only the slanted surface, while TSA includes both bases and the slanted surface.
Given (r_1 = 5) cm, (r_2 = 3) cm, (l = 7) cm. Use the formula: CSA = pi (r_1 + r_2) x l = (22/7) x (5 + 3) x 7 = (22/7) x 8 x 7 = 176 cm²
Find the total surface area of a truncated cone with radii 6 cm and 4 cm, and a slant height of 10 cm.
TSA = 376.8 cm²
Use the formula: TSA = pi (r_1 + r_2) x l + pi r_1² + \pi r_2² = 3.14 x (6 + 4) x 10 + 3.14 x 6² + 3.14 x 4² = 3.14 x 10 x 10 + 3.14 x 36 + 3.14 x 16 = 314 + 113.04 + 50.24 = 376.8 cm²
A truncated cone has a larger base radius of 7 cm, a smaller base radius of 5 cm, and a slant height of 12 cm. Find the total surface area.
TSA = 577.76 cm²
Use the formula: TSA = pi (r_1 + r_2) x l + pi r_1² + pi r_2² = 3.14 x (7 + 5) x 12 + 3.14 x 7² + 3.14 x 5² = 3.14 x12 x 12 + 3.14 x 49 + 3.14 x 25= 452.16 + 153.86 + 78.5= 577.76 cm²
Find the curved surface area of a truncated cone with radii 4.5 cm and 2.5 cm, and a slant height of 8 cm.
CSA = 176 cm²
CSA = pi (r_1 + r_2) x l= (22/7) x (4.5 + 2.5) x 8 = (22/7) x 7 x 8 = 176 cm²
The slant height of a truncated cone is 15 cm, and its curved surface area is 660 cm². Find the sum of the radii of the bases.
Sum of radii = 14 cm
Students often make mistakes while calculating the surface area of a truncated cone, leading to incorrect answers. Below are some common mistakes and ways to avoid them.

Nishtha is a passionate Maths teacher with 3 years of teaching experience. She focuses on making mathematics simple, engaging, and stress-free through student-centric, interactive, and exam-oriented teaching. With strong fundamentals, regular practice, an
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