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455 LearnersLast updated on November 20, 2025

Imagine you own a mechanic shop. You know that the wait time for a repair job follows a normal distribution. You want to see how a customer's wait time compares to everyone else's.
The Question: What percentage of customers have to wait less time than this particular customer?
Calculation: To use the table, we must first convert the “minutes” to a “Z-score.” This normalizes the data.
\(Z = \frac{x - \mu}{\sigma}\)
\(Z = \frac{7.4 - 5.6}{1.5}\)
\(Z = \frac{1.8}{1.5} = 1.2\)
Result: The Z-score is 1.2. This means the customer waited 1.2 standard deviations longer than the average.
The Lookup (Using the Table)
Now look at the Z-score Table (Standard Normal Table). Since the Z-score is 1.2, we split it into two parts to find our coordinates:
Here is a snippet of what the table looks like:
|
Z |
0.00 |
0.01 |
0.02 |
0.03 |
|
1.1 |
.8643 |
.8665 |
.8686 |
.8708 |
|
1.2 |
.8849 |
.8869 |
.8888 |
.8907 |
|
1.3 |
.9032 |
.9049 |
.9066 |
.9082 |
How to read it:
The value is 0.8849.
The Conclusion: The table gives us a probability (area under the curve) of 0.8849.
Z score table can only be used when we know the value of z. The value represents a number to indicate how many standard deviations the value is below or above the mean. Z score can be used to calculate both sample and population data.
By using the given formulas, z score is calculated:
For population data: \(z = \frac{x - μ} {σ}\)
Here, x is the raw score
μ is the population mean
𝞂 is the standard deviation of a population
Next, for sample data: \(z = \frac{x - x̄} {s}\)
Here,
\( x̄ =\) sample mean
\(s =\) sample standard deviation
\(x =\) raw score
Take a look at this example,
If the class average on a science test is 60 with a standard deviation of 10, if a student scored 80, we can calculate their Z score as follows. Let’s say a class is averaging 60 on a recently concluded examination, with a standard deviation of 10. Then, the students averaging 80 can calculate their Z score as follows:
Here, the raw score (x) = 80
The mean (μ) = 60
the population standard deviation (𝞂) = 10
By using the formula of Z score: \(z = \frac{x - μ} {σ}\)
\(z = \frac{80 – 60}{10} = 2 \)
\(z = 2\)
Thus, the student’s science score is 2 standard deviations above the class average.
The Z score table is divided into two types, negative and positive z score tables. A negative z score means the data point of the random variable is below the mean.
A positive z score means the value is above the mean. We should use the negative z score table to find the values below the mean. Likewise, we use a positive z score table to find the values that fall above the mean or less than the positive z score. The cells in the table describe the area and the rows and columns represent the z score. Here are the negative and positive z score tables, take a look at this:
The Altman Z-Score is a financial model that predicts whether a company will go bankrupt within two years. Unlike statistical Z-tables, which use coordinates to compute probabilities, the Altman table serves as a threshold guide by combining five key financial ratios into a single score. You then compare this score to three distinct zones—Safe, Grey, and Distress—to determine the company's economic situation.
| Model |
Target Company |
Distress Cutoff | Safe Cutoff |
|
Original |
Public Manufacturing | < 1.81 | > 2.99 |
| Z' Score | Private Manufacturing | < 1.23 |
> 2.90 |
| Z'' Score |
Service / Non-Manufacturing |
< 1.10 |
> 2.60 |
In essence, the Altman Z-Score acts as a “financial traffic light”, allowing investors to assess the complex balance sheet data quickly.


There are certain steps that should be followed while using a Z score table. The steps are listed below:
Step 1: The first step is to determine the z score for the said data point. Then, we should find the mean and standard deviation. The z score explains how far the data point is from the average or mean.
Step 2: Analyze the Z score table. The left side column represents the Z scores. The matching percentiles or probabilities are on the table’s body.
Step 3: Identifying the z score, located on the left-most column of the table, is the next step. If we do not find the exact z score, estimate the probability by interpolating between the nearest values.
Let us understand this with an example,
In a university, the average score of an entrance exam has a mean of 70 and a standard deviation of 10. One of the students wants to find the probability of scoring below 85.
Solution:
First, we need to calculate the Z score.
z = (x - μ) / σ
z = \( {{85 - 70} \over 10} \)
z = 15 / 10 = 1.5
Now, from the z score table, we should identify the cumulative probability corresponding to 1.5. The probability for z = 1.5 is 0.9332.
0.9332 × 100 = 93.32%
The probability of the student scoring below 85 is 93.32%.
In a standard Z-score table (Normal Distribution), the total area under the curve is always 1 (or 100%).
\(\text{Area to the Right} = 1 - \text{Area to the Left}\)
Example: If the table says the area to the left is 0.80 (80%), the area to the right is 0.20 (20%).
This concept connects the “math score” (Z-score) to the “human score” (Percentile).
Select the Positive Table if your Z-score is greater than zero, and the Negative Table if it is less than zero. Both tables display the area on the left.
The Lookup Method: To find Z = 0.57:
Get the Percentile: Multiply that decimal by 100.
The “Greater Than” Rule: If the question asks for “Area greater than…”, take your table answer and subtract it from 1.
In statistics, mathematics, and research Z score is a vital tool to find the probabilities of values. It makes the calculation and analysis of data much easier for students.
The Z score table helps quickly find probabilities in a normal distribution. By using symmetry, subtraction rules, and memorizing key values, calculations become much easier.
Misunderstanding the concepts of the Z score table can lead to incorrect probability calculations. The Z score is a fundamental aspect of statistics and mathematics. It helps students to calculate the probabilities in a normal distribution. Some of the common mistakes and its helpful solutions are given below:
The Z score table is used to measure how far a value is from the mean. It is applied in exams, health, business, and sports to compare performance with standards.
Exam results - Z scores help compare a student's performance with the class average.
Medical diagnosis - Used in health tests like bone density to see how far a patient's score is from the healthy mean.
Stock market - Analyst use Z scores to detect unusual price movements or volatility.
Quality control - Factories apply z scores to check if a product falls within acceptable limits.
Sports analytics - Coaches compare player performance with league averages using Z scores.
Joe took a math test where the class average was 75 with a standard deviation of 5. He scored 80. Joe wants to know how well he performed compared to his classmates.
Better than 84.13% of his classmates.
To calculate the Z score, we can use the formula:
\(z = \frac{x - μ}{σ}\)
Here, \(x = 80\)
\(μ = 75\)
𝞂 = 5
Now, we can substitute the values:
\(z = \frac{80 - 75}{5}\)
\(z = \frac{5}{5}=1\)
So, the cumulative probability for \(z = 1.0\) is 0.8413
It means Joe performed better than 84.13% of his classmates.
Sam is 7 feet tall. The average height for men in his college is 6.5 feet with a standard deviation of 0.5 feet. Sam wonders how much taller he is compared to the average man.
Sam is taller than 84.13% of the men in his college.
x = 7 feet
μ = 6.5 feet
𝞂 = 0.5 feet
The Z score formula is:
\(z = \frac{x - μ}{σ}\)
\(z = \frac{7 - 6.5}{0.5}\)
\(z = \frac{0.5}{0.5} = 1\)
Here, the cumulative probability of 1 is 0.8413.
Sam is taller than approximately 84.13% of the men in his college.
In a school, the average weight of students is 30 kg with a standard deviation of 25 kg. A student has 40 kg. Is this student heavier than most?
Yes, the student is heavier than most.
The formula for the Z score is:
\(z = \frac{x - μ}{σ}\)
Where, x = 40
μ = 30
𝞂 = 25
z = \({{40 - 30} \over 25} \)
40 - 30 / 25
z = 10 / 25 = 0.4
The Z score of 0.4 corresponds to 0.6554.
So, more than half of the students (65.54%) weigh less than this student.
If x is 50, the mean (μ) is 40, and the standard deviation (𝞂) is 5. What is the Z score?
2.0
Here, x = 50
μ = 40
𝞂 = 5
The formula is: z = (x - μ) / σ
Now, we can substitute the values.
z = 50 - 40 / 5
z = 10 / 5 = 2
The Z score is 2.0, which means, the value 50 is 2 standard deviations above the mean.
What is the probability that a Z score lies between -2.00 and 2.00?
0.9544 or 95.44%
Here, we need to find the cumulative probability for z = -2.00 and z = 2.00. From the Z score table, we find that the probability of z = -2.00 is 0.0228
The probability for z = 2.00 is 0.9772
Next, we have to subtract the lower from the higher probability.
0.9772 - 0.0228 = 0.9544
To convert the number to percentage, we have to multiply it by 100:
0.9544 × 100 = 95.44%
So, the probability that a Z score lies between -2.00 and 2.00 is 0.9544 or 95.44%.
Jaipreet Kour Wazir is a data wizard with over 5 years of expertise in simplifying complex data concepts. From crunching numbers to crafting insightful visualizations, she turns raw data into compelling stories. Her journey from analytics to education ref
: She compares datasets to puzzle games—the more you play with them, the clearer the picture becomes!
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