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400 LearnersLast updated on August 5, 2025

A rational inequalities calculator is a tool to solve inequalities involving rational expressions. Since rational inequalities can be complex, this calculator helps in finding the solution set of such inequalities efficiently. This tool simplifies the process and provides quick results, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the rational inequality: Input the inequality expression into the given field.
Step 2: Click on solve: Click on the solve button to compute the solution set.
Step 3: View the result: The calculator will display the solution set instantly.


To solve rational inequalities, the calculator uses a systematic approach. Here’s the general process:
1. Find the critical points by setting the numerator and denominator equal to zero separately.
2. Determine the intervals using these critical points.
3. Test each interval to see if it satisfies the inequality.
4. Combine the intervals to find the solution set.
Understanding the sign changes across intervals is crucial for solving rational inequalities accurately.
When using a rational inequalities calculator, there are a few tips and tricks to make it easier and avoid mistakes:
While using a calculator, mistakes can occur. Here's how to avoid them:
Solve the rational inequality x/(x-2) > 0.
First, find the critical points:
x = 0 (numerator) and x = 2 (denominator).
Test intervals: (-∞, 0), (0, 2), and (2, ∞).
For x in (-∞, 0), (negative)/(negative) = positive; satisfies the inequality.
For x in (0, 2), (positive)/(negative) = negative; does not satisfy.
For x in (2, ∞), (positive)/(positive) = positive; satisfies the inequality.
Solution set: x ∈ (-∞, 0) ∪ (2, ∞).
The solution involves finding critical points and testing intervals. The inequality holds for x in (-∞, 0) and (2, ∞).
Solve the rational inequality (x+3)/(x-1) ≤ 0.
Critical points: x = -3 (numerator) and x = 1 (denominator).
Test intervals: (-∞, -3), (-3, 1), (1, ∞).
For x in (-∞, -3), (negative)/(negative) = positive; does not satisfy.
For x in (-3, 1), (positive)/(negative) = negative; satisfies the inequality.
For x in (1, ∞), (positive)/(positive) = positive; does not satisfy.
Solution set: x ∈ [-3, 1).
Using critical points and interval testing, the solution set is within the interval [-3, 1).
Solve the rational inequality (2x)/(x+4) < 1.
Rearrange: (2x)/(x+4) - 1 < 0, or (2x-x-4)/(x+4) < 0, simplifies to (x-4)/(x+4) < 0.
Critical points: x = 4 and x = -4 (denominator).
Test intervals: (-∞, -4), (-4, 4), (4, ∞).
For x in (-∞, -4), (negative)/(negative) = positive; does not satisfy.
For x in (-4, 4), (negative)/(positive) = negative; satisfies the inequality.
For x in (4, ∞), (positive)/(positive) = positive; does not satisfy.
Solution set: x ∈ (-4, 4).
After rearranging and simplifying the inequality, the solution set is x ∈ (-4, 4).
Solve the rational inequality (x^2-9)/(x+3) ≥ 0.
Factor numerator: (x-3)(x+3)/(x+3) ≥ 0.
Critical points: x = 3 and x = -3.
Test intervals: (-∞, -3), (-3, 3), (3, ∞).
For x in (-∞, -3), (negative)/(negative) = positive; satisfies the inequality.
For x in (-3, 3), (negative)/(positive) = negative; does not satisfy.
For x in (3, ∞), (positive)/(positive) = positive; satisfies the inequality.
Solution set: x ∈ (-∞, -3) ∪ (3, ∞).
Factoring and testing intervals show that the solution set is x ∈ (-∞, -3) ∪ (3, ∞).
Solve the rational inequality (x+2)/(x^2-1) > 0.
Factor denominator: (x+2)/((x-1)(x+1)) > 0.
Critical points: x = -2, x = 1, and x = -1.
Test intervals: (-∞, -2), (-2, -1), (-1, 1), (1, ∞).
For x in (-∞, -2), (negative)/(positive) = negative; does not satisfy.
For x in (-2, -1), (positive)/(positive) = positive; satisfies the inequality.
For x in (-1, 1), (positive)/(negative) = negative; does not satisfy.
For x in (1, ∞), (positive)/(positive) = positive; satisfies the inequality.
Solution set: x ∈ (-2, -1) ∪ (1, ∞).
Factoring and testing intervals indicate the solution set is x ∈ (-2, -1) ∪ (1, ∞).
Nishtha is a passionate Maths teacher with 3 years of teaching experience. She focuses on making mathematics simple, engaging, and stress-free through student-centric, interactive, and exam-oriented teaching. With strong fundamentals, regular practice, an
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