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175 LearnersLast updated on September 10, 2025

A quadratic formula calculator is a tool to solve quadratic equations of the form ax² + bx + c = 0. The calculator uses the quadratic formula to find the roots of the equation.
This tool makes solving quadratic equations much easier and faster, saving time and effort.
Given below is a step-by-step process on how to use the calculator:
Step 1: Enter the coefficients: Input the values of a, b, and c into the given fields.
Step 2: Click on solve: Click on the solve button to compute the roots of the equation.
Step 3: View the results: The calculator will display the roots instantly.
To solve quadratic equations using the quadratic formula, the calculator uses the formula: x = (-b ± √(b² - 4ac)) / 2a The discriminant (b² - 4ac) determines the nature of the roots.
If the discriminant is positive, there are two real and distinct roots. If it is zero, there is one real repeated root. If it is negative, the roots are complex.


When using a quadratic formula calculator, there are a few tips and tricks to make it easier and avoid mistakes:
We may think that when using a calculator, mistakes will not happen. But it is possible to make mistakes when using a calculator.
Solve the quadratic equation 2x² - 4x - 6 = 0.
Use the formula: x = (-b ± √(b² - 4ac)) / 2a For 2x² - 4x - 6 = 0, a = 2, b = -4, c = -6. Discriminant = (-4)² - 4(2)(-6) = 16 + 48 = 64 x = (4 ± √64) / 4 x = (4 ± 8) / 4 x₁ = 12/4 = 3 x₂ = -4/4 = -1
Substituting the values of a, b, and c into the quadratic formula gives us the roots x₁ = 3 and x₂ = -1.
Solve the quadratic equation x² + 6x + 9 = 0.
Use the formula: x = (-b ± √(b² - 4ac)) / 2a For x² + 6x + 9 = 0, a = 1, b = 6, c = 9. Discriminant = 6² - 4(1)(9) = 36 - 36 = 0 x = (-6 ± √0) / 2 x = -6 / 2 x = -3
The discriminant is zero, indicating one repeated real root, x = -3.
Solve the quadratic equation 3x² + 4x + 2 = 0.
Use the formula: x = (-b ± √(b² - 4ac)) / 2a For 3x² + 4x + 2 = 0, a = 3, b = 4, c = 2. Discriminant = 4² - 4(3)(2) = 16 - 24 = -8 x = (-4 ± √(-8)) / 6 x = -2/3 ± i√2/3
The discriminant is negative, indicating two complex roots: x = -2/3 ± i√2/3.
Solve the quadratic equation 5x² - 20x + 15 = 0.
Use the formula: x = (-b ± √(b² - 4ac)) / 2a For 5x² - 20x + 15 = 0, a = 5, b = -20, c = 15. Discriminant = (-20)² - 4(5)(15) = 400 - 300 = 100 x = (20 ± √100) / 10 x = (20 ± 10) / 10 x₁ = 30/10 = 3 x₂ = 10/10 = 1
The roots are real and distinct, given by x₁ = 3 and x₂ = 1.
Solve the quadratic equation 4x² + 0x + 1 = 0.
Use the formula: x = (-b ± √(b² - 4ac)) / 2a For 4x² + 0x + 1 = 0, a = 4, b = 0, c = 1. Discriminant = 0² - 4(4)(1) = -16 x = (0 ± √(-16)) / 8 x = ± i/2
There are two complex roots: x = ± i/2.
Nishtha is a passionate Maths teacher with 3 years of teaching experience. She focuses on making mathematics simple, engaging, and stress-free through student-centric, interactive, and exam-oriented teaching. With strong fundamentals, regular practice, an
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