Last updated on July 4th, 2025
The process of removing irrational numbers like cube roots and square roots from the denominator of a fraction is called the rationalization of the denominator. This is performed by multiplying both the numerator and denominator by the appropriate factor to remove the irrational term. In this topic, we will learn the importance of rationalizing the denominator and its applications.
An irrational denominator in a fraction can be converted into a rational number by rationalizing the denominator. If the denominator of a fraction is irrational, then the fraction becomes irrational. Therefore, rationalization is done to convert the denominator into a rational number. This process of rationalization helps us remove radicals like square roots and cube roots from the denominator.
Different methods can be used to rationalize various types of irrational denominators. The main approaches for rationalizing the denominators are as follows:
Now let us understand each method in detail.
While rationalizing a square or cube root of a single term, it is mandatory to multiply both numerator and denominator by a factor to eliminate the radical present in the denominator. For a term like a yⁿ where n < m, we multiply the denominator and numerator by y(m-n) and we get a yᵐ, which simplifies to say, removing the radical. For a better understanding, take a look at this example.
Let us rationalize 1/√5.
Since √5 is irrational, we will rationalize it.
To rationalize, we will multiply both the numerator and denominator by √5
1/√5 × √5/√5
Next, we can multiply: 1 x √5/√5 x 5 = 1/√5
Thus, 1/√5 is rationalized as √5/5.
When the denominator contains a radical and is in the form a +√b or a + i√b, we multiply both the numerator and denominator by a – √b or a – i√b, which is the algebraic conjugate of the terms. Since the algebraic identity (a+b) (a-b) = a2– b2, this method can be used to rationalize the denominator of the form a +√b or a + i√b. To take a look at this example, let us simplify 1/(1 + √5).
Here the denominator is 1 + √5 and the conjugate is 1 - √5. To remove the square root, we have to multiply both the numerator and denominator by the same conjugate.
1/1 + √5 × 1 - √5/1- √5
Next, we can expand the denominator by using the identity (a+b) (a-b) = a2– b2
(1 + √5 ) (1 - √5 ) = 12 - (√5)2 = 1 - 5 = - 4
Then we can expand the numerator 1 × (1 - √5 ) = 1 - √5
So the answer is 1 - √5/-4
Since the denominator is -4, we can rewrite the fraction as -(1 - √5)/4 to get √5 - 1/4.
When the denominator has three terms or trinomials, like a±√b±√c, the process of rationalizing is more complex. To rationalize a trinomial denominator, treat two terms as a single binomial, and the third term separately. Select a rationalizing factor that simplifies at least one irrational term when multiplied. If radicals are not eliminated completely after the first rationalization process, repeat the process with the obtained result to eliminate the remaining irrational terms.
For instance, the given expression is 1/(1 + √2 - √3)
Step 1: Select two terms to form a binomial. Here we choose (1 + √2) and treat - √3 as the third term. So, the conjugate of the three terms is (1 - √2) + √3.
Now, we can multiply this conjugate with both numerator and denominator.
1/1 + √2 - √3 × (1 - √2 )+ √3 / (1 - √2 )+ √3
Step 2: Simplify the denominator by using the difference of squares formula:
(A−B)(A+B) = A2 - B2
Here, A = (1 + √2)
B = √3
(1 + √2)2 - (√3)2
We can expand it to:
1 + 2√2 + 2 - 3
= 3 + 2√2 - 3 = 2√2
Here the fraction becomes:
1 + √2 + √3 2√2
Step 3: Multiply with √2 in numerator and denominator.
(1 + √2 + √3) 2√2 × √2√2
So, we can expand the numerators as:
√2 + 2 + √6
Next, we can expand the denominator as:
2√2 × √2 = 4
Therefore, the final answer is √2 + 2 + √6 4.
We apply the method of rationalizing the denominator in math to simplify complex calculations by removing radicals. Here are some applications of rationalizing the denominator.
The process of rationalizing a denominator means eliminating or removing the square roots or cube roots from the denominator of a fraction. However, students often make errors while they perform rationalization. Here are some common mistakes and ways to avoid them.
Rationalize 6/√2
3/√2
Since (√2) is an irrational number, to remove it from the denominator, multiplying both the numerator and denominator by the conjugate of the denominator (√2).
6/√2 x √2/√2
√2 x √2 = 2
The denominator becomes:
6 x √2/2
6 ÷ 2 = 3
Therefore, the expression simplifies to:
3√2
Rationalize 1/5+√4
1/7
Since the denominator is 5 + √4, we rationalize it by multiplying both the numerator and denominator by its conjugate, 5 - √4.
The formula for the difference of squares: (a + b) (a - b) = a2- b2.
Now, we can multiply both numerator and denominator by the conjugate:
1/5 + √4 x 5 - √4/5 - √4
We expand the denominator and numerator:
Denominator = (5 + √4) (5 - √4) = 52 - (√4)2
= 25 - 4 = 21
Numerator = 1 × (5 - √4) = 5 - √4
So, the simplified expression:
5 - √4/21
√4 = 2
So, 5 - 2/21 = 3/21 = 1/7
Rationalize 1/4 +√2
2/7 - √2/14
We need to multiply the numerator and denominator by the conjugate of 4 + √2, which is 4 - √2.
1/4 + √2 x 4 - √2/4 - √2
Next, we can expand the numerator and denominator:
Numerator = 1 (4 - √2)
= 4 - √2
We can use the formula (a + b) (a - b) = a2- b2
Denominator = (4 + √2) (4 - √2) = 42 - (2)2
= 16 - 2 = 4
So, the rationalized form is:
4 - √2/14
Now we can simplify it by dividing the numerators by 14.
4/14 - √2/14
= 2/7 - √2 /14
The final answer is 2/7 - √2 /14
Rationalize the denominator in 1/√6
√6/6
To make the denominator rational, we must multiply the denominator and numerator by √6 .
Multiply 1/√6 by √6/√6 equals 1
That is, 1 x √6 = √6 (numerator)
√6 x √6 = 6
So, the fraction is √6/6
No further simplification is possible.
Therefore, the rationalized form of 1/√6 is √6/6
Rationalize 4/√7
4√7/ 7
First, multiply the numerator and denominator by √7, which the conjugate of √7.
4/√7 x √7/√7
Next, multiply the numerator and denominator separately:
4/√7 x √7/√7
Since, √7 x √7 = 7
So, the fraction simplifies to:
4√7 / 7
The rationalized form of 4/√7 is 4√7/ 7
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
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