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Last updated on July 15th, 2025

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Geometric Progression

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A Geometric Progression (GP) is a sequence where each number is the product of the previous term and a fixed value known as the common ratio. We can find the preceding term in a GP by dividing the given term by the same common ratio. For example, 3, 6, 12, 24, 48,... is a GP with a common ratio of 2. Geometric progressions can contain a finite or an infinite number of terms. In this article, we will learn about the meaning of GP, its formulas, and different types.

Geometric Progression for Vietnamese Students
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What is a Geometric Progression?

The sequence in which each term is obtained by multiplying the previous term by a fixed number (common ratio) is known as a Geometric Progression. It is usually expressed as: a, ar, ar2, ar3…, where ‘a’ represents the first term and ‘r’ represents the common ratio. A common ratio can either be positive or negative. Any term in a GP can be determined using the first term and the common ratio.

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What are the Types of Geometric Progression?

Geometric progressions are mainly classified into two types based on their length.

The different types of geometric progressions are:

 

  • Finite geometric progression

 

  • Infinite geometric progression


We will now learn about each type in detail:

 

Finite geometric progression
A finite geometric progression has a limited number of terms, and the last term is known.

For example: 1/2, 1/4, 1/8, 1/16,…,1/32768 is a finite geometric progression. Here, 1/32768 is the last term.

 

Infinite geometric progression

An infinite geometric progression has an endless number of terms. Since there is no fixed number of terms, the last term cannot be specified.  

For example, the infinite series 3, −6, +12, −24, +... does not have a definite end term.

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GP vs AP

To help you identify the sequence effectively, we will now look at the key differences between GP and AP.

 

Geometric Progression (GP) Arithmetic Progression (AP)
Multiply each term by the same number (common ratio). Adds the same number to each term (common difference).
No common difference between the terms. No fixed ratio between terms.
For example: 2, 4, 8, 16,...(r = 2) For example: 3, 6, 9, 12,...(d = 3)
Such series can converge or diverge depending on r. The series is always divergent unless the common difference is zero.
Terms progress exponentially. Terms progress linearly.

 

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What are the Properties of GP?

Understanding the unique features of a progression helps us identify it more easily. Here are a few properties that geometric progressions (GP) follow. 

 

  • The square of any term in a GP is equal to the product of the terms that are directly adjacent to it: ak2 = ak-1 × ak+1

 

  • In a finite geometric progression, terms that are equally spaced from the beginning and the end have the same product: a1 × an = a2 × an-1 =…= ak × an-k+1

 

  • Multiplying or dividing a GP by a non-zero constant, the new sequence remains a GP with the same common ratio.

 

  • The reciprocal of each term in a GP results in another GP with a new common ratio equal to 1/r (r = original common ratio).

 

  • A GP remains a GP even if each of its terms is raised to the same power. 
    Example: GP: a, ar, ar2,...,
    Raise each term to the power k:
    ak, (ar)k, (ar2)k,..., which is still a GP.
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What is the Formula for GP?

In a GP, the sum of the terms can be calculated using the following formulas:

 

For a GP:  a, ar, ar2, ar3, …

nth term: 

an = arn–1 or an =  r × an– 1

Sum of the first n terms:

Sn = a(1 − rn)/(1 − r) for r ≠ 1, and

Sn = n × a for r = 1

Sum of infinite terms: 

S = a/(1 - r), when |r| < 1

The sum does not exist when |r| ≥ 1.

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Real-Life Applications of Geometric Progression

Geometric progression has a vital role in various real-life situations. Let’s now learn how this concept can be applied outside mathematics.

 

  • Geometric progressions help analyze populations that grow at a steady rate, like 20% each year. An example would be 1,000 → 1,200 → 1,440 → 1,728 (20% annual growth).

 

  • GP also describes how a substance decreases by a set proportion over time, such as in radioactive decay.

 

  • The exponential growth of the computer memory units forms a geometric progression. For example: Doubling of memory sizes: 1GB → 2 GB → 4 GB → 8 GB.
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Common Mistakes and How to Avoid Them in Geometric Progression

Geometric progression is a simple mathematical concept, but many students struggle with its problems. Here are a few common mistakes and tips to avoid them:

Mistake 1

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Confusion Between GP and AP

To distinguish between GP and AP is difficult for students. They often think that GP has a common difference instead of a constant ratio.

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Ensure that each term in a GP is determined by multiplying the one before it by the same ratio.

Mistake 2

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Using the Sum Formula Incorrectly

Students mistakenly use the sum formula for r = 1 when it does not apply.

For example: 

For the GP 2, 6, 18,...(where r = 3) and n = 4, use:

S4 = 2(34 – 1)/ 3 – 1

= 2(81 – 1)/ 2 

= 2 × 80/ 2 = 80

If we use r = 1 formula, it will give an incorrect result.

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  • Always apply the formula Sn = a (rn – 1 )/ r – 1 when r ≠ 1
     
  • Apply the formula: Sn  = n × a, when r = 1.

Mistake 3

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Overlooking Signs in Common Ratio

Ignoring negative signs in the common ratio can lead to incorrect results.

For example:

Consider the GP:

3, -6, 12, -24,...

Here, we have the common ratio (r) = -2. Ignoring the negative sign can give incorrect terms and sums.
 

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To avoid this error, always check whether the signs of the common ratio and terms are handled correctly.

Mistake 4

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Incorrect Use of Reciprocals
 

Assuming that a GP's reciprocal does not constitute a GP.

For example: 
Original GP: 2, 6, 18, 54,...
Common ratio = 3.

Reciprocals: 
1/2, 1/6, 1/18, 1/54,...

New common ratio:
1/6/1/2 = 1/3

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Keep in mind that the reciprocal of a GP is still a GP even if none of the terms are zero. So the new ratio becomes 1/r.

Mistake 5

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Using an Incorrect Formula for the nth Term

Some students write the formula for the nth term as an= arn.

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The correct formula for the nth term is an = arn–1

An easy way to remember it is that the first term is a1 = a and the exponent of r is n –1.

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Solved Examples of Geometric Progression

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Problem 1

Find the 5ᵗʰ term of a GP Given: First term (a) = 3 Common ratio (r) = 2

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a₅ =  48

Explanation

First, apply the formula for the nᵗʰ term:
aₙ = a × rⁿ⁻¹

Substituting the values into the formula:
a₅ = 3 × 2⁵⁻¹ = 3 × 2⁴

Here, we get:
a₅ = 3 × 16 = 48

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Problem 2

Find the sum to infinity of a GP Given: a = 8, r = 1/2

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S∞ = 16

Explanation

Let’s first check if |r| < 1
It holds true for the infinite sum since |1/2| < 1.

 

Using the formula:
S∞ = a / (1 - r)

 

Substituting the values into the formula:
S∞ = 8 / (1 - 1/2) = 8 / (1/2)

 

So,
S∞ = 8 × 2 = 16

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Problem 3

Find the sum of the first 6 terms of a GP Given: a = 5, r = 3, n = 6

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S₆ = 1820

Explanation

Here, we use the formula for the sum of the first n terms:
Sₙ = a(rⁿ - 1) / (r - 1)

 

Let’s substitute the values:
S₆ = 5(3⁶ - 1) / (3 - 1)

 

We now calculate powers and simplify:
3⁶ = 729
S₆ = 5(729 - 1) / 2 = 5 × 728 / 2

 

So,
S₆ = 3640 / 2 = 1820

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Problem 4

Find the 8ᵗʰ term of the GP 5, 10, 20, 40,... Given: a = 5, r = 2, n = 8

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a₈ =  640

Explanation

Here, we apply the formula for the nᵗʰ term:
aₙ = a × rⁿ⁻¹

 

Substituting the values into the formula:
a₈ = 5 × 2⁸⁻¹ = 5 × 2⁷

 

So,
a₈ = 5 × 128 = 640

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Problem 5

Find how many terms of the GP 3, 6, 12, 24,... are needed to make the sum 93 Given: a = 3, r = 2, Sₙ = 93

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n = 5

Explanation

Using the formula:
Sₙ = a(rⁿ - 1) / (r - 1)

 

Substituting the given values:
93 = 3(2ⁿ - 1) / (2–1)

 

Now, simplify to get the result:

93 = 3(2ⁿ - 1)

93 ÷ 3 = 2ⁿ - 1

31 = 2ⁿ - 1

2n = 31 + 1

2ⁿ = 32 

 

Here, n is the exponent to which 2 needs to be raised to obtain 32.
Since 25 = 32
→ n = 5

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FAQs on Geometric Progression

1.What is meant by the term GP?

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2.Give the formula for the nth term of a GP.

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3.What do you mean by a common ratio?

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4.Can the common ratio be 1?

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5.Is it possible for a geometric progression's common ratio to be negative?

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6.How does learning Algebra help students in Vietnam make better decisions in daily life?

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7.How can cultural or local activities in Vietnam support learning Algebra topics such as Geometric Progression?

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8.How do technology and digital tools in Vietnam support learning Algebra and Geometric Progression?

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9.Does learning Algebra support future career opportunities for students in Vietnam?

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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