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Last updated on December 11, 2025

Volume of Truncated Pyramid

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The volume of a truncated pyramid is the total space it occupies or the number of cubic units it can hold. A truncated pyramid is a 3D shape with a top and bottom base that are parallel but not of the same size. To find the volume of a truncated pyramid, we use the formula that involves the areas of the bases and the height of the pyramid. In real life, kids relate to the volume of a truncated pyramid by thinking of things like a frustum of a pyramid-shaped glass or a lampshade. In this topic, letโ€™s learn about the volume of a truncated pyramid.

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What is the volume of the truncated pyramid?

The volume of a truncated pyramid is the amount of space it occupies.

 

It is calculated using the formula:\( [ \text{Volume} = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) ] where ( h ) \)is the height of the truncated pyramid,\( ( A_1 ) \)is the area of the top base, and\( ( A_2 )\) is the area of the bottom base.

 

This formula accounts for both bases and the height of the pyramid.

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How to Derive the Volume of a Truncated Pyramid?

To derive the volume of a truncated pyramid, we use the concept of volume as the total space occupied by a 3D object.

 

The formula for the volume of a truncated pyramid is derived from the volume of a full pyramid: \([ \text{Volume} = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) ]\)

 

This formula considers the average of the areas of the bases and the height to determine the volume.

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How to find the volume of a truncated pyramid?

The volume of a truncated pyramid is usually expressed in cubic units, for example, cubic centimeters\( (cm^3), cubic meters (m^3).\)

 

To find the volume, calculate the areas of the top and bottom bases, determine the height, and apply the formula: \([ \text{Volume} = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) ]\)

 

Once we know the areas of the bases and the height, substitute these values into the formula to find the volume.

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Tips and Tricks for Calculating the Volume of Truncated Pyramid

Remember the formula: The formula for the volume of a truncated pyramid is:\( [ \text{Volume} = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) ] \)

Break it down: Calculate the areas of the bases and the height separately, then substitute them into the formula. Ensure the bases are parallel and the height is perpendicular to them.

 

Simplify the numbers: If the areas and height are simple numbers, it is easier to substitute them directly into the formula.

 

Check for unit consistency: Ensure all measurements are in the same units before calculating the volume.

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Common Mistakes and How to Avoid Them in Volume of Truncated Pyramid

Making mistakes while learning the volume of a truncated pyramid is common. Let’s look at some common mistakes and how to avoid them to get a better understanding of the volume of truncated pyramids.

Mistake 1

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Confusing Volume with Surface Area

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Some students confuse the formula for volume with the formula for surface area. Surface area involves calculating the lateral and base areas. Volume is calculated by the specific formula for the truncated pyramid.

Mistake 2

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Confusing Volume with Perimeter

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Some kids may think of the perimeter of the bases instead of the volume formula. Volume refers to the space inside the truncated pyramid, while perimeter refers to the total edge length of a 2D shape.

Mistake 3

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Using the wrong Formula for full pyramids

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Some kids use the formula for the volume of a full pyramid instead of the truncated pyramid formula.

Mistake 4

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Confusing cubic volume with linear volume

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Thinking of volume in terms of linear measurements. This happens when someone uses the linear dimensions without applying the correct formula for volume calculation.

Mistake 5

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Incorrectly calculating the areas of the bases

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Some students calculate the given volume with errors in finding the areas of the top and bottom bases. Ensure the base areas are calculated correctly before using the formula.

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Volume of Truncated Pyramid Examples

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Problem 1

A truncated pyramid has a top base area of 20 cmยฒ, a bottom base area of 50 cmยฒ, and a height of 10 cm. What is its volume?

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The volume of the truncated pyramid is 366.03 cm³.

Explanation

To find the volume of a truncated pyramid, use the formula: \([ V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) ]\)

 

Here, \(( A_1 = 20 \, \text{cm}^2 ), ( A_2 = 50 \, \text{cm}^2 ), and ( h = 10 \, \text{cm} ).\) 

 

\(V = \frac{1}{3} \times 10 \times (20 + 50 + \sqrt{20 \times 50}) \)

 

\(V = \frac{1}{3} \times 10 \times (70 + \sqrt{1000}) \)

 

\(V = \frac{1}{3} \times 10 \times (70 + 31.62) \)

 

\( V = 366.03 \, \text{cm}^3 \)

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Problem 2

A truncated pyramid has a top base area of 30 mยฒ, a bottom base area of 70 mยฒ, and a height of 8 m. Find its volume.

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The volume of the truncated pyramid is 800.34 m³.

Explanation

To find the volume of a truncated pyramid, use the formula:\( V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) \)

Substitute \( A_1 = 30 \, \text{m}^2 , A_2 = 70 \, \text{m}^2 , and h = 8 \text{m} \)

 

\(V = \frac{1}{3} \times 8 \times (30 + 70 + \sqrt{30 \times 70}) \)

 

\( V = \frac{1}{3} \times 8 \times (100 + \sqrt{2100}) \)

 

\(V = \frac{1}{3} \times 8 \times (100 + 45.83) \)

 

\(V = 800.34 \, \text{m}^3 \)

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Problem 3

The volume of a truncated pyramid is 500 cmยณ. If the top base area is 15 cmยฒ, the bottom base area is 35 cmยฒ, find the height.

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The height of the truncated pyramid is 7.21 cm.

Explanation

If you know the volume of the truncated pyramid and need to find the height, rearrange the formula: \(V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) \)


\(500 = \frac{1}{3} \times h \times (15 + 35 + \sqrt{15 \times 35}) \)

\(500 = \frac{1}{3} \times h \times (50 + \sqrt{525}) \)

 

\(500 = \frac{1}{3} \times h \times (50 + 22.91) \)

 

\( h = \frac{500 \times 3}{72.91} \)

 

h = 7.21 cm

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Problem 4

A truncated pyramid has a top base area of 25 inchesยฒ, a bottom base area of 60 inchesยฒ, and a height of 5 inches. Find its volume.

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The volume of the truncated pyramid is 391.03 inches³.

Explanation

Using the formula for volume: \(V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) \)

Substitute \(A_1 = 25 , \text{inches}^2 , A_2 = 60 , \text{inches}^2 , and h = 5 \, \text{inches} \)

 

\(V = \frac{1}{3} \times 5 \times (25 + 60 + \sqrt{25 \times 60}) \)

 

\(V = \frac{1}{3} \times 5 \times (85 + \sqrt{1500}) \)

 

\(V = \frac{1}{3} \times 5 \times (85 + 38.73) \)

 

\(V = 391.03 \, \text{inches}^3 \)

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Problem 5

You have a truncated pyramid-shaped container with a top base area of 12 ftยฒ, a bottom base area of 45 ftยฒ, and a height of 6 ft. How much space (in cubic feet) is available inside the container?

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The container has a volume of 378.25 cubic feet.

Explanation

Using the formula for volume: \(V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) \)

 

Substitute \(A_1 = 12 \text{ft}^2 , A_2 = 45 \, \text{ft}^2 , and h = 6 \text{ft} \)


\(V = \frac{1}{3} \times 6 \times (12 + 45 + \sqrt{12 \times 45}) \)


\(V = \frac{1}{3} \times 6 \times (57 + \sqrt{540}) \)


\(V = \frac{1}{3} \times 6 \times (57 + 23.24)ย  \)

\(V = 378.25 \, \text{ft}^3ย \)

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FAQs on Volume of Truncated Pyramid

1.Is the volume of a truncated pyramid the same as its surface area?

No, the volume and surface area of a truncated pyramid are different concepts: Volume refers to the space inside the truncated pyramid and is given by the specific formula, while surface area refers to the total area of all faces and bases.

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2.How do you find the volume if the base areas and height are given?

To calculate the volume when the base areas and height are provided, use the formula: \[ V = \frac{1}{3} \times h \times (A_1 + A_2 + \sqrt{A_1 \times A_2}) \] Substitute the known values into the formula to find the volume.

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3.What if I have the volume and need to find the height?

If the volume of the truncated pyramid is given and you need to find the height, rearrange the formula to solve for the height: \[ h = \frac{3 \times V}{(A_1 + A_2 + \sqrt{A_1 \times A_2})} \]

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4.Can the base areas be decimal or fraction values?

Yes, the base areas of a truncated pyramid can be decimal or fraction values. Calculate the areas accordingly and use them in the volume formula.

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5.Is the volume of a truncated pyramid the same as its surface area?

No, the volume and surface area of a truncated pyramid are different concepts: Volume refers to the space inside the truncated pyramid and is given by the formula involving base areas and height.

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Important Glossaries for Volume of Truncated Pyramid

  • Top Base Area: The area of the smaller, top base of the truncated pyramid.

 

  • Bottom Base Area: The area of the larger, bottom base of the truncated pyramid.

 

  • Height: The perpendicular distance between the top and bottom bases of the truncated pyramid.

 

  • Volume: The amount of space enclosed within a 3D object, expressed in cubic units (e.g., cm³, m³).

 

  • Cubic Units: The units of measurement used for volume, corresponding to the units used for base areas and height.
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About the Author

Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.

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